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Choosing a Method In Exercises 43 and 44, state the method of integration you would use to find each integral. Explain why you chose that method. Do not integrate. $$\int x \sqrt{x^{2}+1} d x$$

Short Answer

Expert verified
The method of substitution would be used to integrate the given function because the function \(x \sqrt{x^{2}+1}\) has an inside function \(x^{2}+1\) and its derivative \(2x\) (with a constant factor) present. This allows for a simple substitution \(u=x^{2}+1\) that simplifies the integral.

Step by step solution

01

Identifying the Method

Observe that we have a function inside the square root, which is \(x^{2}+1\), and if we take its derivative, we can see that \(d/dx (x^{2}+1)= 2x\). Notice there is an \(x\) outside of the square root, which serves as the derivative of the inside function with some constant factor. Therefore, this indicates that substitution will be an effective method in this case because we can replace the inside function with a single variable, and it simplifies the integration process.
02

Explanation

The integral as given \(\int x \sqrt{x^{2}+1} dx\) can be greatly simplified if we were to let \(u = x^{2}+1\). After substituting, the integral would become \(\int \sqrt{u} du\) after proper substitution which is a much simpler integral to compute. Although we are not solving this integral in this exercise, we know that this substituted integral can easily be integrated by direct integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

substitution method
The substitution method is a powerful technique in calculus, used to simplify the process of integration. It works much like changing the subject in algebra to make equations easier to handle. In integration, the goal is to replace complex expressions with simpler ones by introducing a new variable. For instance, if you have an integral that involves a function nested within another, such as \( \int x \sqrt{x^2+1} \, dx \), you can use substitution to make it manageable.
Here's how it works:
  • You identify a part of the integrand that can be substituted with a new variable. In our example, you could let \( u = x^2 + 1 \).
  • Next, find the derivative of this new variable with respect to \( x \), which is \( du = 2x \, dx \), and solve for \( dx \).
  • Replace all occurrences of the original expressions in the integrand with \( u \) and \( du \). The integral then becomes \( \int \frac{1}{2} \sqrt{u} \, du \).
This reduces the original, more complicated integral into something simpler that can be easily integrated. While this method requires practice to recognize which part to substitute, it's typically effective whenever you see derivatives of functions linked closely within an integrand.
integrals
Integrals are a fundamental concept in calculus used to find areas, volumes, central points, and other related quantities. Essentially, integration is the mathematical way of adding up infinite tiny parts to calculate a whole.
The integral symbol \( \int \) is used to denote this concept, and it often involves functions, limits, and differentials. For example, you might see an expression such as \( \int f(x) \, dx \), which means to find the integral of \( f(x) \) with respect to \( x \). This process reveals the area under the curve of \( f(x) \) on a given interval.
There are several types of integrals and methods for computing them:
  • Definite Integrals: These have limits of integration and result in a numerical value representing the area under the curve between two points.
  • Indefinite Integrals: These do not have specific bounds, resulting in a general form that includes a constant \( C \), representing an infinite number of possible solutions (the "+C" you see after computing these integrals).
  • Numerical Methods: When functions are too complex for analytical integration, numerical methods like trapezoidal or Simpson's rule can approximate the area.
Mastering integrals involves understanding the function itself and the context in which the integral is needed, combining analytical skills with practical problem-solving techniques.
change of variables
Change of variables, a key part of calculus, helps simplify complex integrals by transforming the variable of integration. It's particularly useful when the direct integration of a function seems challenging. This method is often called the substitution method because it typically involves substituting a new variable to make the integration process easier.
The process involves:
  • Identifying a substitution that transforms the integrand into a simpler form. For example, if given an integral of a function inside a square root, like \( \int x \sqrt{x^2+1} \, dx \), you might decide to let \( u = x^2 + 1 \).
  • Computing the derivative \( du \) of the substituted variable in terms of the original variable, helping to transform \( dx \) into \( du \). In our example, we find \( du = 2x \, dx \), allowing the replacement and transformation of the integral to \( \int \frac{1}{2} \sqrt{u} \, du \).
  • Performing the integration in terms of the new variable, which is typically much simpler. Finally, transform back to the original variable if needed for the solution.
This technique streamlines the process of integration by altering the perspective through which a problem is viewed, opening new ways to comprehend and solve complex integrals effectively. Recognizing when to use this method is key to solving calculus problems efficiently.

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