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Exercises \(13-16,\) explain why the integral is improper and determine whether it diverges or converges. Evaluate the integral if it converges. $$\int_{0}^{4} \frac{1}{\sqrt{x}} d x$$

Short Answer

Expert verified
The given improper integral, \(\int_{0}^{4} \frac{1}{\sqrt{x}} dx\), converges and its value is 4.

Step by step solution

01

Identify the Type of Improper Integral

This integral is an improper one due to the presence of a singularity at \(x = 0\). The integrand \(\frac{1}{\sqrt{x}}\) is not defined at \(x = 0\), thus representing a jump discontinuity there.
02

Address discontinuity and apply limit

To evaluate the integral, we must change the integrand’s lower limit from 0 to a variable \(t\), and then take the limit as \(t\) approaches 0 to evaluate the convergence of the integral: \[\lim_{t \to 0^+} \int_{t}^{4} \frac{1}{\sqrt{x}} dx \]
03

Evaluate the Definite Integral

The integral of \(\frac{1}{\sqrt{x}}\) is \(2\sqrt{x}\). Hence, the changed definite integral becomes: \[\lim_{t \to 0^+} [2\sqrt{x}]_{t}^{4} \]
04

Solve the Limit

We then substitute the limits \(x = 4\) and \(x = t\) into the expression and evaluate the limit: \[\lim_{t \to 0^+} [2\sqrt{4} - 2\sqrt{t}] = 4 \] Thus, the improper integral converges, and its value is 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence and Divergence
When dealing with improper integrals, it's crucial to establish whether the integral converges or diverges. In mathematical terms, convergence refers to the integral producing a finite value when evaluated. On the other hand, divergence implies that the integral does not result in a finite number and tends to infinity or is undefined.
To determine the convergence or divergence of an integral, especially when it involves a singularity, testing if the limit exists and results in a finite number is essential. In the given problem, replacing the point of singularity with a limit helps in identifying whether the integral converges or diverges as the value approaches that point. This systematic approach is used to discern when you can calculate a meaningful result from the integral.
Limit Evaluation
Limit evaluation is a fundamental step in working with improper integrals, particularly when addressing singularities. After identifying a problematic point, such as where the integrand is undefined, we use a limit to "smooth over" the singularity.
For the integral \[\int_{0}^{4} \frac{1}{\sqrt{x}} dx\], the singularity arises at \(x=0\). To handle this, we replace the undefined limit at zero with a variable, say \(t\), and evaluate the limit as \(t\) approaches zero from the positive side (\(t \to 0^+\)). This careful method ensures the precise handling of the integral's behavior near the singularity. Doing so, we transform the integral into an expression that can be safely evaluated.
Singularities
Singularities in an integral occur when the function becomes undefined or the values sharply jump, causing traditional methods of integration to fail.
An example is the function \( \frac{1}{\sqrt{x}} \), which is undefined at \(x = 0\). This point causes the integral to be improper because the expression becomes infinite or undefined at that spot.
  • To mitigate issues arising from singularities, it is common to employ limit evaluations by substituting the singular point with a variable, then using limits.
  • This is a crucial step for evaluating such integrals without hitting mathematical pitfalls.
Handling singularities present at integration bounds is vital in achieving correct results.
Definite Integrals
Definite integrals represent the accumulation of values—essentially the area under a curve—between specified bounds. In the context of improper integrals, we focus on improper intervals that involve infinity or undefined points.
Once we replace any singularities with a limit (as done before), we solve the integral to find its value between the new bounds. In the exercise example, the integral \( \int_{0}^{4} \frac{1}{\sqrt{x}} dx \) is improper because of the lower bound singularity. We used the limit \( \lim_{t \to 0^+} [2\sqrt{4} - 2\sqrt{t}] \) to evaluate the integral's overall finite result.
By using this method, we determined that this integral converges and results in a finite value of 4, successfully employing the concept of definite integrals.

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