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Describing a Solid Each integral represents the volume of a solid. Describe each solid. (a) $$\pi \int _ { 0 } ^ { \pi / 2 } \sin ^ { 2 } x d x$$ (b) $$\pi \int _ { 2 } ^ { 4 } y ^ { 4 } d y$$

Short Answer

Expert verified
The first integral describes the volume of a hemisphere of radius 1 (∵ \(sin^2x\) for \(0≤x≤π/2\), is a semicircle of radius 1). The second integral describes the volume of a object whose cross section is a solid disk. The radius of each disk is \(y^2\) and these disks are stacked along the y-axis from y=2 to y=4

Step by step solution

01

Analyzing the first integral

In the first integral, \( \pi \int _ { 0 } ^ { \pi / 2 } \sin ^ { 2 } x d x \), the integral bounds are from 0 to \( \pi / 2 \). Since the bounded function is \( \sin ^ { 2 } x \), which is a familiar curve, we know that it is describing a semicircle squared (a disk) revolved about the x-axis from 0 to \( \pi / 2 \).
02

Determining the volume of first solid

The volume of the solid described by the integral is given by \( \pi \) times the integral over the square of the radius, in this case \( \sin ^ { 2 } x \), from 0 to \( \pi / 2 \).
03

Analyzing the second integral

The second integral, \( \pi \int _ { 2 } ^ { 4 } y ^ { 4 } d y \), is defined from 2 to 4. Here, \( y ^ { 4 } \) describes the shape of the solid when revolved about the y-axis.
04

Determining the volume of second solid

Similar to step 2, we determine the volume of the solid described by the second integral as \( \pi \) times the integral of the square of the radius which is \( y ^ { 4 } \). It describes the volume of a solid of revolution about the y-axis, with the radii of the circular cross sections varying as \( y ^ { 2 } \), and the height of the solid going from 2 to 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definite Integrals
In calculus, a definite integral is a concept that allows us to calculate the accumulation of quantities, such as areas under curves. It is represented by the integral symbol, a function, and the upper and lower limits of integration. For instance, when we encounter an expression like \( \text{\( \text{\(\pi\int_{0}^{\pi/2}\sin^{2}xdx\)}\)} \), it encapsulates the entire area under the curve of \( \sin^{2}x \) from 0 to \( \pi/2 \).

In the context of volume calculation, definite integrals are crucial because they help us sum up an infinite number of infinitely thin cross-sections to find a solid's volume. The integral sign tells us to add up, while the function provides the dimensions of each infinitely thin disc, and the limits tell us where to start and stop summing. Understanding the nature of the function within the integral, like \( \sin^{2}x \) or \( y^{4} \), is key to visualizing the solid whose volume we seek to determine.
Volume Calculation
Volume calculation in calculus typically involves finding the amount of three-dimensional space a solid occupies. It's like pouring water into the shape and measuring how much it holds. With solids of revolution, we calculate volume by imagining how a two-dimensional shape rotates around an axis to form a three-dimensional object.

For instance, when we take a semicircle and rotate it around the x-axis, it creates a sphere. By using calculus and the concept of definite integrals, we don't have to guess the volume; we can compute it precisely. The mathematical approach involves slicing the shape into infinitesimally thin pieces, calculating the volume of each slice, and then adding all these tiny volumes together—which is exactly what integrating does.
Disc Method
The disc method is a technique for finding volumes of solids of revolution. It is used when a shape is rotated around an axis to create a solid, and it involves visualizing the solid as a stack of thin discs or circles.

Imagine slicing your favorite vegetable very thinly and then piling up the slices. You essentially have the disc method idea. Each slice corresponds to a circular disc. The formula for the volume of each disc is \( \pi r^2 \), where \( r \) is the radius of the disc. In the context of integrals, the radius is given by the function being integrated, and we sum up the volumes of all discs from the first to the last by integrating. The integral \( \pi \text{\(\int_a^b f(x)^2dx\)} \), where \( f(x) \) is the radius function, represents the volume of the entire solid.
Solid of Revolution
A solid of revolution is a three-dimensional object created by taking a two-dimensional shape and rotating it around an axis. This rotation sweeps the shape through space to form the solid. The resulting shape has perfect symmetry around the axis of rotation, resembling shapes like cylinders, spheres, and cones, depending on the original two-dimensional figure.

For visualization, take a piece of paper and draw a curve, then spin the paper around one edge. The curve's motion through space would create a hollow shape resembling the solid of revolution. Calculus lets us calculate this solid's volume, even if it's not hollow, by using methods like the disc method explained above. An integral like \( \pi \text{\(\int_2^4 y^4 dy\)} \) isn't just a bunch of symbols; it's a mathematical expression of the volume of a solid formed by rotating the curve \( y^4 \) from 2 to 4 about the y-axis.

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Most popular questions from this chapter

Using a Cone A cone of height \(H\) with a base of radius \(r\) is cut by a plane parallel to and \(h\) units above the base, where \(h

Arc Length and Area Let \(C\) be the curve given by \(f(x)=\cosh x\) for \(0 \leq x \leq t,\) where \(t>0 .\) Show that the arc length of \(C\) is equal to the area bounded by \(C\) and the \(x\) -axis. Identify another curve on the interval \(0 \leq x \leq t\) with this property.

The hydraulic cylinder on a woodsplitter has a 4 -inch bore (diameter) and a stroke of 2 feet. The hydraulic pump creates a maximum pressure of 2000 pounds per square inch. Therefore, the maximum force created by the cylinder is \(2000\left(\pi \cdot 2^{2}\right)=8000 \pi\) pounds. (a) Find the work done through one extension of the cylinder, given that the maximum force is required. (b) The force exerted in splitting a piece of wood is variable. Measurements of the force obtained in splitting a piece of wood are shown in the table. The variable \(x\) measures the extension of the cylinder in feet, and \(F\) is the force in pounds. Use the regression capabilities of a graphing utility to find a fourth-degree polynomial model for the data. Plot the data and graph the model. $$ \begin{array}{|l|l|c|c|c|c|c|c|} \hline x & 0 & \frac{1}{3} & \frac{2}{3} & 1 & \frac{4}{3} & \frac{5}{3} & 2 \\\ \hline F(x) & 0 & 20,000 & 22,000 & 15,000 & 10,000 & 5000 & 0 \\ \hline \end{array} $$ (c) Use the model in part (b) to approximate the extension of the cylinder when the force is maximum. (d) Use the model in part (b) to approximate the work done in splitting the piece of wood.

(a) Given a circular sector with radius \(L\) and central angle \(\theta\) (see figure), show that the area of the sector is given by \(S=\frac{1}{2} L^{2} \theta\) (b) By joining the straight-line edges of the sector in part (a), a right circular cone is formed (see figure) and the lateral surface area of the cone is the same as the area of the sector. Show that the area is \(S=\pi r L,\) where \(r\) is the radius of the base of the cone. (Hint: The arc length of the sector equals the circumference of the base of the cone.) (c)Use the result of part (b) to verify that the formula for the lateral surface area of the frustum of a cone with slant height \(L\) and radii \(r_{1}\) and \(r_{2}\left(\) see figure) is \(S=\pi\left(r_{1}+r_{2}\right) L\right.\) (Note: This formula was used to develop the integral for finding the surface area of a surface of revolution.)

Using a Loop Consider the graph of \(y^{2}=\frac{1}{12} x(4-x)^{2}\) shown in the figure. Find the area of the surface formed when the loop of this graph is revolved about the \(x\) -axis.

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