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Slope Field A slope field shows that the slope at the point \((1,1)\) is \(6 .\) Does this slope field represent the family of solutions for the differential equation \(y^{\prime}=4 x+2 y ?\) Explain.

Short Answer

Expert verified
Yes, the slope field represents the family of solutions for the differential equation \(y^{\prime}=4 x+2 y\).

Step by step solution

01

Substitute Into Differential Equation

Firstly, we need to substitute the point \((1,1)\) into the differential equation \(y^{\prime}=4 x+2 y\). Putting \(x=1\) and \(y=1\) gives \(y^{\prime}=4 * 1 + 2 * 1 = 6\)
02

Compare With Slope Field

After substituting, we obtained that at the point \((1,1)\) the slope, according to the given differential equation, should be \(6\). The slope at the same point, according to the slope field, is also \(6\). The given slope in the field matches the value obtained from the differential equation.
03

Draw Conclusion

Since the slopes from the differential equation and the slope field match at the given point \((1,1)\), we can conclude that the slope field does represent the family of solutions for the given differential equation \(y^{\prime}=4 x+2 y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation
A differential equation is a mathematical equation that relates a function with its derivatives. In simpler terms, it describes the rate at which something changes. For example, the differential equation y'=4x+2y, which appears in the textbook exercise, expresses how the rate of change of the variable y (denoted by y') is dependent on both x and y themselves.

Understanding differential equations is crucial for modeling real-world scenarios where change is a constant, such as in physics, economics, and biology. The primary goal when dealing with these equations is to find a function, or a set of functions, that satisfy the equation—these are known as 'solutions'.

Slope Field Representation
A slope field is a visual representation of a differential equation and is composed of small line segments or arrows at grid points that give a slope, or direction, to the solutions of the equation at those points. This graphical representation helps students visualize the behavior of solutions without actually solving the equation.

In the given exercise, the slope field indicates that for the point (1,1), the slope of the tangent to the curve representing the solution to the differential equation is 6. Through such visualization, slope fields enable a better comprehension of the concept of a family of solutions and provide a tangible means to analyze the dynamic changes expressed by differential equations.
Calculus Problem Solving
Calculus problem solving often involves identifying patterns, applying theorems, and manipulating expressions to find solutions. For differential equations, an essential problem-solving skill is substituting specific values into the equation to verify properties such as the slope of a tangent line at a point.

Through step-by-step solutions like the one provided, students learn to break down complex problems into manageable parts—from substitution to drawing conclusions. This methodical approach not only helps to ensure accuracy but also instills a sense of confidence when tackling calculus problems.
Differential Equation Solutions
Finding solutions to differential equations can range from straightforward methods to intricate techniques, depending on the complexity of the equation. For first-order linear equations like y'=4x+2y, there are established methods to find exact solutions. However, for many real-life problems, exact solutions are either hard to find or don't exist.

In such cases, slope fields serve as an invaluable tool for approximating the behavior of solutions and understanding the general trends they follow. This practical application of slope fields in finding differential equation solutions underpins their significance in calculus.

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Most popular questions from this chapter

Bacteria Growth At time \(t=0,\) a bacterial culture weighs 1 gram. Two hours later, the culture weighs 4 grams. The maximum weight of the culture is 20 grams. $$\begin{array}{l}{\text { (a) Write a logistic equation that models the weight of the }} \\ {\text { bacterial culture. }} \\ {\text { (b) Find the culture's weight after } 5 \text { hours. }} \\ {\text { (c) When will the culture's weight reach } 18 \text { grams? }}\end{array}$$ $$\begin{array}{l}{\text { (d) Write a logistic differential equation that models the }} \\ {\text { growth rate of the culture's weight. Then repeat part (b) }} \\ {\text { using Euler's Method with a step size of } h=1 . \text { Compare }} \\ {\text { the approximation with the exact answer. }} \\\ {\text { (e) At what time is the culture's weight increasing most }} \\\ {\text { rapidly? Explain. }}\end{array}$$

In Exercises \(47-54,\) solve the Bernoulli differential equation. \(y^{\prime}+\left(\frac{1}{x}\right) y=x y^{2}\)

Using a Logistic Equation In Exercises 53 and 54 , the logistic equation models the growth of a population. Use the equation to (a) find the value of \(k,(\) b) find the carrying capacity, (c) find the initial population, (d) determine when the population will reach 50% of its carrying capacity, and (e) write a logistic differential equation that has the solution \(P(t).\) $$P(t)=\frac{5000}{1+39 e^{-0.2 t}}$$

Slope Field Describe the slope field for a logistic differential equation. Explain your reasoning.

Population In Exercises \(51-54,\) the population (in millions) of a country in 2015 and the expected continuous annual rate of change \(k\) of the population are given. (Source: U.S. Census Bureau, International Data Base) (a) Find the exponential growth model \(P=C e^{k t}\) for the population by letting \(t=5\) correspond to \(2015 .\) (b) Use the model to predict the population of the country in \(2030 .\) (c) Discuss the relationship between the sign of \(k\) and the change in population for the country. $$\begin{array}{l}{\text { Country }}&{\text { 2015 Population }}&&{\text { \(k\) }} \\ {Latvia}& {\text {2.0}}&&{{-0.011}}\end{array}

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