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Solving a Homogeneous Differential Equation In Exercises \(77-82,\) solve the homogeneous differential equation in terms of \(x\) and \(y .\) A homogeneous differential equation is an equation of the form $$M(x, y) d x+N(x, y) d y=0$$ where \(M\) and \(N\) are homogeneous functions of the same degree. To solve an equation of this form by the method of separation of variables, use the substitutions \(y=v x\) and \(d y=x d v+v d x\) . $$(2 x+3 y) d x-x d y=0$$

Short Answer

Expert verified
Solution to the homogeneous differential equation is \(y = 3x ln|x| + Cx\)

Step by step solution

01

Recognizing the differential equation

The differential equation provided is \((2x + 3y)dx - xdy = 0\). It is a homogeneous differential equation. Note that it can be written as \((2x dx + 3y dx) - xdy = 0\). This clearly indicates the form \(M(x, y)dx + N(x, y)dy = 0\) where \(M(x, y) = 2x + 3y\) and \(N(x, y) = -x\)
02

Apply substitution

Since this is a homogeneous differential equation, the substitutions \(y = vx\) and \(dy = xdv + vdx\) are applied. Plugging these into the above equation we get: \((2x + 3vx)dx - x(xdv + vdx) = 0\). This equation can be further simplified and arranged into: \(3vdx = x^2 dv\)
03

Separate variables

Arrange the equation so that all terms involving \(v\) are on one side and terms involving \(x\) are on the other. This gives: \(\frac{dv}{dx} = \frac{3v}{x}\)
04

Integrate to find v

Integrate the above equation to find \(v\). The integral of the left side is \(v\), while the integral of the right side is \(3 ln|x|\). Hence, \(v = 3 ln|x| + C\) where \(C\) is the constant of integration
05

Substitute back for y

Substitute back \(v = \frac{y}{x}\) into the above equation to get the solution in terms of \(x\) and \(y\): \(y = 3x ln|x| + Cx\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
Solving differential equations often involves breaking down a complex equation into simpler components using the separation of variables technique. This method is particularly useful for homogeneous differential equations, where variables can be isolated and solved individually. If you have an equation of the form \(M(x, y) dx + N(x, y) dy = 0\), the goal is to rearrange it to separate the terms involving 'x' from those involving 'y'.

Typically, you start by expressing one variable in terms of another using substitutions. This helps to isolate the variables on either side of an equation. For instance, substituting \(y = vx\) and \(dy = x dv + v dx\) in your given differential equation allows you to manipulate the equation to have terms involving \(v\) and \(x\) separated. Once that's done, the equation becomes manageable, making the integration process feasible. Through this tailored separation, each variable can be independently integrated, making the solution process clearer and more systematic.
Substitution Method
The substitution method is a strategic approach used in solving complex differential equations by making suitable substitutions to simplify the problem. In the context of homogeneous differential equations, substitutions like \(y = vx\) are applied to transform the equation.

This substitution method is invaluable because it converts an otherwise challenging equation into a more familiar and solvable form. By introducing \(v\) as a new variable representing the ratio \(\frac{y}{x}\), we take advantage of the equation's homogeneity. The resulting equation, thanks to this substitution, allows easy manipulation and separates the dependencies of \(x\) and \(v\).

Substituting \(dy\) with \(x dv + v dx\) follows naturally, capturing the derivative's behavior under the new substitution. This forms the backbone of transforming the overall complex differential equation into an integrable format, paving the way for further steps in solving the problem.
Integration
Integration is a fundamental process in mathematics that involves finding a function given its derivative, effectively reversing differentiation. For differential equations, once you separate variables and employ suitable substitutions, integration becomes the next key step.

In the context of our differential equation, after substituting and separating variables, we arrived at \(\frac{dv}{dx} = \frac{3v}{x}\). This now needs to be integrated with respect to its respective variable. Solving the right side involves integrating the natural logarithm, leading to results like \(3 \ln|x|\). The solution represents an antiderivative reflecting the original equation's behavior.

Adding a constant of integration, denoted by \(C\), is crucial, acknowledging potential variations in initial conditions or particular solutions. Through integration, not only do we solve the separated differential equation, but we also reach closer to expressing the solution in terms of the original variables \(x\) and \(y\).
Differential Equations
Differential equations serve as a mathematical tool to describe relationships involving rates of change, capturing how quantities evolve over time or space. They come in various forms and complexities, often relating different functions and their derivatives.

A homogeneous differential equation, like the one addressed here, typically exhibits scalable properties, meaning if \(x\) and \(y\) are scaled equally, the equation does not change. This characteristic enables us to apply methods like separation of variables and substitution effectively.

The general form \(M(x, y) dx + N(x, y) dy = 0\) offers a structure to discern these equations' solvability. Solving these is integral in fields like physics, engineering, and beyond, as they model real-world systems where change is constant. By mastering differential equations, we gain deeper insights into dynamic systems and their behavior.

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Most popular questions from this chapter

In Exercises \(57-64,\) solve the Bernoulli differential equation. The Bernoulli equation is a well-known nonlinear equation of the form \(y^{\prime}+P(x) y=Q(x) y^{n}\) that can be reduced to a linear form by a substitution. The general solution of a Bernoulli equation is \(y^{1-n} e^{f(1-n) P(x) d x}=\int(1-n) Q(x) e^{\int(1-n) P(x) d x} d x+C\) $$y^{\prime}-y=y^{3}$$

In Exercises 47 and \(48,\) (a) use a graphing utility to graph the slope field for the differential equation, (b) find the particular solutions of the differential equation passing through the given points, and (c) use a graphing utility to graph the particular solutions on the slope field in part (a). \(\begin{array}{ll}{\text { Differential Equation }} & {\text { Points }} \\\ {\frac{d y}{d x}-\frac{1}{x} y=x^{2},} & {(-2,4),(2,8)}\end{array}\)

True or False? In Exercises 67 and \(68,\) determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If prices are rising at a rate of 0.5\(\%\) per month, then they are rising at a rate of 6\(\%\) per year.

Population Growth When predicting population growth, demographers must consider birth and death rates as well as the net change caused by the difference between the rates of immigration and emigration. Let \(P\) be the population at time \(t\) and let \(N\) be the net increase per unit time resulting from the difference between immigration and emigration. So, the rate of growth of the population is given by $$\frac{d P}{d t}=k P+N$$ where \(N\) is constant. Solve this differential equation to find \(P\) as a function of time, when at time \(t=0\) the size of the population is \(P_{0} .\)

In Exercises 65 and \(66,\) determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. \(y^{\prime}+x \sqrt{y}=x^{2}\) is a first-order linear differential equation.

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