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Determining if a Function Is Homogeneous In Exercises \(69-76,\) determine whether the function is homogeneous, and if it is, determine its degree. A function \(f(x, y)\) is homogeneous of degree \(n\) if \(f(x, t y)=t^{n} f(x, y) .\) $$f(x, y)=2 \ln x y$$

Short Answer

Expert verified
The function \(f(x, y)=2 \ln x y\) is homogeneous and its degree is \(2\).

Step by step solution

01

Test whether the given function is homogeneous

Replace \(x\) and \(y\) with \(tx\) and \(ty\) respectively in the function \(f(x, y)=2 \ln x y\), to check the homogeneity property.
02

Evaluate the New Expression

Substitute \(x=tx\) and \(y=ty\) in \(f(x, y)=2 \ln x y\), we get \(f(tx, ty)=2 \ln(tx \cdot ty) = 2 \ln (t^2 xy)\). Using the log property that \(\ln a^b = b \cdot \ln a\), rewrite the expression as \(2(t^2) \ln(xy) = t^2 f(x, y)\). Hence, the given function is homogeneous and its degree is 2.
03

Conclusion

The function \(f(x, y)=2 \ln x y\) is a homogeneous function and its degree is \(2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Homogeneity of Functions
One of the fascinating topics in algebra is the concept of homogeneity of functions. These are particular types of functions that depict a specific scaling behavior. A function is considered homogeneous if for every scalar multiple, say \(t\), the function scales by a power of \(t\). In mathematical terms, a function \(f(x, y)\) is said to be homogeneous of degree \(n\) if, for all values of \(x\) and \(y\) and for any scalar \(t\), the following equality holds: \[f(tx, ty) = t^n f(x, y)\].

In the exercise given, we are asked to determine if the function \(f(x, y) = 2 \ln(xy)\) is homogeneous and, if so, to identify its degree. By definition, we replace \(x\) and \(y\) with their respective scaled versions, \(tx\) and \(ty\), and observe if the function can be expressed as the original function multiplied by a power of \(t\). When we substitute these into our function, the presence of logarithmic properties, which we'll delve into later, plays a critical in confirming homogeneity.

This knowledge can be highly beneficial in various fields of mathematics and physics where understanding the scaling behavior of equations is essential, such as in the study of differential equations and economic modeling. Homogeneous functions are particularly powerful as they allow for simplifications in many theoretical and practical applications.
Degree of Homogeneous Function
When discussing homogeneous functions, the degree of the function is a term that frequently pops up. It refers to the power by which the function scales when all of its variables are multiplied by the same factor. The degree, often denoted by \(n\), is a crucial piece of the puzzle that characterizes the function's behavior.

To find the degree of a homogeneous function like \(f(x, y) = 2 \ln(xy)\), we utilize the scaling property of homogeneity, replacing \(x\) and \(y\) with \(tx\) and \(ty\). We then look for the exponent \(n\) in \(t^n\) such that the scaled function equals \(t^n\) times the original function. In the provided exercise, after substituting and applying logarithmic properties, we find that the function scales as \(t^2 f(x, y)\), indicating that the function's degree is 2.

Understanding the degree of a function is not just an academic exercise—it can tell us how changes in inputs proportionally affect the output. For example, in economics, if a production function has a degree of 1, it is said to exhibit constant returns to scale, influencing how businesses might scale operations. In physics, it might relate to how a physical quantity, such as pressure or potential energy, changes with the size of a system.
Logarithmic Properties
Logarithmic properties are like the Swiss Army knife for solving and simplifying a wide array of mathematical problems. Logarithms, being the inverse operation of exponentiation, have several handy properties that can be applied when evaluating expressions, especially within homogeneous functions.

One key property that we've used in the context of our exercise is known as the power rule: \(\ln(a^b) = b \ln(a)\). It allows us to take an exponent and turn it into a multiplier in front of the log, which, as we've seen, can be pivotal in determining homogeneity and degree of a function.

There are a few other logarithmic properties that are equally essential, such as the product rule (\(\ln(xy) = \ln(x) + \ln(y)\)) and the quotient rule (\(\ln(\frac{x}{y}) = \ln(x) - \ln(y)\)). These properties simplify complicated expressions, enabling a step-by-step breaking down of the problem, much like how we approached the exercise.

Having a robust grasp of logarithmic properties opens up pathways to efficiently tackling problems in calculus, algebra, and beyond. It empowers students to not only solve textbook exercises but to develop a deeper understanding of the exponential and logarithmic relationships that underpin many scientific and mathematical principles.

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Most popular questions from this chapter

Population In Exercises \(51-54,\) the population (in millions) of a country in 2015 and the expected continuous annual rate of change \(k\) of the population are given. (Source: U.S. Census Bureau, International Data Base) (a) Find the exponential growth model \(P=C e^{k t}\) for the population by letting \(t=5\) correspond to \(2015 .\) (b) Use the model to predict the population of the country in \(2030 .\) (c) Discuss the relationship between the sign of \(k\) and the change in population for the country. \begin{array}{l}{\text { Country }}&{\text { 2015 Population }}&&{\text { \(k\) }} \\ {Ukraine}& {\text { 44.4}}&&{{-0.006}}\end{array}

Solving a Homogeneous Differential Equation In Exercises \(77-82,\) solve the homogeneous differential equation in terms of \(x\) and \(y .\) A homogeneous differential equation is an equation of the form $$M(x, y) d x+N(x, y) d y=0$$ where \(M\) and \(N\) are homogeneous functions of the same degree. To solve an equation of this form by the method of separation of variables, use the substitutions \(y=v x\) and \(d y=x d v+v d x\) . $$\left(x^{2}+y^{2}\right) d x-2 x y d y=0$$

Modeling Data One hundred bacteria are started in a culture and the number \(N\) of bacteria is counted each hour for 5 hours. The results are shown in the table, where \(t\) is the time in hours. $$\begin{array}{|c|c|c|c|c|c|c|}\hline t & {0} & {1} & {2} & {3} & {4} & {5} \\\ \hline N & {100} & {126} & {151} & {198} & {243} & {297} \\\ \hline\end{array}$$ (a) Use the regression capabilities of a graphing utility to find an exponential model for the data.(b) Use the model to estimate the time required for the population to quadruple in size.

Solving a Homogeneous Differential Equation In Exercises \(77-82,\) solve the homogeneous differential equation in terms of \(x\) and \(y .\) A homogeneous differential equation is an equation of the form $$M(x, y) d x+N(x, y) d y=0$$ where \(M\) and \(N\) are homogeneous functions of the same degree. To solve an equation of this form by the method of separation of variables, use the substitutions \(y=v x\) and \(d y=x d v+v d x\) . $$(x-y) d x-(x+y) d y=0$$

In Exercises \(57-64,\) solve the Bernoulli differential equation. The Bernoulli equation is a well-known nonlinear equation of the form \(y^{\prime}+P(x) y=Q(x) y^{n}\) that can be reduced to a linear form by a substitution. The general solution of a Bernoulli equation is \(y^{1-n} e^{f(1-n) P(x) d x}=\int(1-n) Q(x) e^{\int(1-n) P(x) d x} d x+C\) $$y^{\prime}-y=e^{x \sqrt[3]{y}}$$

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