/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 84 Finding a Value Find a value of ... [FREE SOLUTION] | 91Ó°ÊÓ

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Finding a Value Find a value of \(x\) such that $$\int_{1}^{x} \frac{1}{t} d t$$ is equal to (a) \(\ln 5\) and (b) \(1 .\)

Short Answer

Expert verified
(a) \(x = 5\), (b) \(x = e\).

Step by step solution

01

- Use the Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus tells us that if a function \(f\) is continuous on the interval \([a, b]\) and \(F\) is an antiderivative of \(f\) on \([a, b]\), then \(\int_{a}^{b} f(t)dt = F(b) - F(a)\). Here, the function \(f\) is \(\frac{1}{t}\) which is equivalent to \(t^{-1}\). The antiderivative \(F(t)\) of \(\frac{1}{t}\) is \(\ln |t|\). So the integral simplifies to: \[\int_{1}^{x} \frac{1}{t} dt = \ln|x| - \ln|1|\] which simplifies to \[\ln|x|\]. So the expression \(\int_{1}^{x} \frac{1}{t} dt\) is equal to \(\ln(x)\).
02

- Solve for \(x\) when the integral is equal to \(\ln 5\)

Set \(\ln(x) = \ln(5)\) and solve for \(x\). Since the function \(f(x) = \ln(x)\) is a strictly increasing function, if \(\ln(a) = \ln(b)\) then \(a\) must be equal to \(b\). So, \(x = 5\).
03

- Solve for \(x\) when the integral is equal to \(1\)

Set \(\ln(x) = 1\) and solve for \(x\). To do this, use the property that \(e^{ln(x)} = x\). So, \(x = e\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite Integrals
Indefinite integrals are a fundamental concept in calculus, representing the antiderivative of a function. They are used to find the general form of an antiderivative, which is a function whose derivative is the original function. Unlike definite integrals, no limits of integration are specified, so the result includes a constant of integration, often denoted as 'C'.

For example, when looking at the function \( f(t) = \frac{1}{t} \), the antiderivative is found using the power rule for integration and is equal to \( \ln|t| + C \). The 'C' represents any constant because the derivative of a constant is zero, which means that it won't affect the differentiation process.

An essential property to remember is that the derivative of an indefinite integral of a function is the original function itself. This concept is directly connected to the Fundamental Theorem of Calculus.
Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is the logarithm to the base 'e', where 'e' is an irrational and transcendental number approximately equal to 2.71828. This special logarithmic function is the inverse operation of raising 'e' to a power.

For instance, \( \ln(e^x) = x \) and \( e^{\ln(x)} = x \). These properties are highly useful in solving equations involving \( \ln(x) \), as seen in the example problem. If an integral evaluates to \( \ln(5) \), one can conclude that the argument of the \( \ln \) function is 5, provided that \( x \) is positive, to avoid the complexity of a logarithm of a negative number.
Integration Properties
The integration process adheres to specific properties that are utilized to solve integrals more efficiently. Some critical properties include:
  • Linearity: The integral of a sum is the sum of the integrals, and a constant can be factored out of an integral.
  • The Power Rule: When integrating terms like \( t^n \), unless \( n = -1 \), the result is \( \frac{t^{n+1}}{n+1} \) plus a constant.
  • Logarithmic Integration: Integrating \( \frac{1}{t} \) or \( t^{-1} \) directly provides the natural logarithm of the absolute value of \( t \) plus a constant.
  • Definite vs. Indefinite: While indefinite integrals give a general form with a constant of integration, definite integrals evaluate the antiderivative at specific limits, resulting in a specific numerical value.

These properties, especially the last one, were crucial in solving the exercise presented. By understanding that the definite integral from 1 to \( x \) of \( \frac{1}{t} \) dt evaluates to \( \ln|x| - \ln|1| \) because of the Fundamental Theorem of Calculus, we find the expression simplifies further to \( \ln|x| \) due to the logarithm of 1 being zero.

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Most popular questions from this chapter

Finding an Indefinite Integral In Exercises \(69-76,\) find the indefinite integral. $$\int x\left(5^{-x^{2}}\right) d x$$

An object is projected upward from ground level with an initial velocity of 500 feet per second. In this exercise, the goal is to analyze the motion of the object during its upward flight. (a) If air resistance is neglected, find the velocity of the object as a function of time. Use a graphing utility to graph this function. (b) Use the result of part (a) to find the position function and determine the maximum height attained by the object. (c) If the air resistance is proportional to the square of the velocity, you obtain the equation $$\frac{d v}{d t}=-\left(32+k v^{2}\right)$$ (d) Use a graphing utility to graph the velocity function \(v(t)\) in part \((c)\) for \(k=0.001 .\) Use the graph to approximate the time \(t_{0}\) at which the object reaches its maximum height. (e) Use the integration capabilities of a graphing utility to approximate the integral $$\int_{0}^{t_{0}} v(t) d t$$ where \(v(t)\) and \(t_{0}\) are those found in part (d). This is the approximation of the maximum height of the object. (f) Explain the difference between the results in parts (b) and (e).

Evaluating a Definite Integral In Exercises \(77-80\) , evaluate the definite integral. Use a graphing utility to verify your result. $$\int_{1}^{3}\left(4^{x+1}+2^{x}\right) d x$$

In Exercises 51 and 52, show that the antiderivatives are equivalent. $$\int \frac{3 x^{2}}{\sqrt{1-x^{6}}} d x=\arcsin x^{3}+C \text { or arccos } \sqrt{1-x^{6}}+C$$

Indeterminate Forms Show that the indeterminate forms \(0^{0}, \infty^{0},\) and \(1^{\infty}\) do not always have a value of 1 by evaluating each limit. $$ (a) \lim _{x \rightarrow 0^{+}} x^{(\ln 2) /(1+\ln x)}$$ $$ (b) \lim _{x \rightarrow \infty^{+}} x^{(\ln 2) /(1+\ln x)}$$ $$ (c) \lim _{x \rightarrow 0}(x+1)^{(\ln 2) / x}$$

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