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In Exercises 73-75, verify the rule by differentiating. Let \(a>0.\) $$\int \frac{d u}{\sqrt{a^{2}-u^{2}}}=\arcsin \frac{u}{a}+C$$

Short Answer

Expert verified
The derivative of the integral expression \(\int \frac{d u}{\sqrt{a^{2}-u^{2}}}\) equals the integrand \(\frac{a}{\sqrt{a^2 - u^2}}\), thus the rule has been verified.

Step by step solution

01

Apply arcsin derivative formula

The derivative of the right side of the equation is to be found. The derivative of the arcsine function \(y = \arcsin(x)\) is \(\frac{1}{\sqrt{1 - x^{2}}}\). Applying this derivative with the chain rule produced by \(u\) over \(a\), we have \(\frac{1}{\sqrt{1 - (u/a)^2}}\) * \(\frac{1}{a}\). This simplifies to \(\frac{a}{\sqrt{a^2 - u^2}}\).
02

Apply derivative of a constant

The derivative of any constant is zero. Therefore, the derivative of \(C\) is \(0\).
03

Combine the results

Combining the results of the derivative from Step 1 and Step 2. The overall derivative is \(\frac{a}{\sqrt{a^2 - u^2}}\) + \(0 = \frac{a}{\sqrt{a^2 - u^2}}\) Thus, after taking the derivative of the right side of the equation, its value equals to the value of the integrand on the left side of given equation. This confirms the rule.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus that allows us to find the rate at which a function is changing at any given point. This process involves finding the derivative of the function. A derivative can be thought of as the slope of the tangent line to the graph of the function at a particular point.

To differentiate a function means to calculate its derivative. This helps to understand how the function behaves. Differentiation is used in various fields such as physics, engineering, and economics to analyze changing quantities. One crucial aspect of differentiation is applying it consistently with various rules, such as the product rule, quotient rule, and chain rule, which we will discuss further.
Arcsine Function
The arcsine function, denoted as \( \arcsin(x) \), is the inverse of the sine function for which it assigns an angle to a given sine value. It is used to find the angle whose sine is a particular value.

The range of the arcsine function is \([-\frac{\pi}{2}, \frac{\pi}{2}]\), meaning it only outputs angles within this interval. Differentiating the arcsine function is particularly useful in various integration problems and is governed by a specific derivative formula:
  • The derivative of \( \arcsin(x) \) is \( \frac{1}{\sqrt{1-x^{2}}} \).
This derivative formula is derived using implicit differentiation and the Pythagorean identity. Understanding this can be very beneficial when working through integral calculus problems that involve inverse trigonometric functions.
Chain Rule
The chain rule is a critical technique in calculus for finding the derivative of composite functions. A composite function is essentially a function within another function. The chain rule states that if you have a function \( y = f(g(x)) \), the derivative \( \frac{dy}{dx} \) is found by multiplying the derivative of the outer function by the derivative of the inner function.

In formulaic terms, if \( y = f(g(x)) \), then:
  • \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \)
This means you first take the derivative of the outer function with respect to the inner function, and then multiply it by the derivative of the inner function. The chain rule is particularly useful when dealing with functions that contain nested expressions, such as the arcsine function, where applying the chain rule enables us to differentiate effectively.
Integration Formula
An integration formula provides a structured method for finding the antiderivative of functions. This is often necessary when reversing the process of differentiation, especially in definite and indefinite integrals.

The given exercise provides an integration formula involving the arcsine function:
  • \( \int \frac{du}{\sqrt{a^2-u^2}} = \arcsin \frac{u}{a} + C \)
This tells us that when we integrate the function \( \frac{1}{\sqrt{a^2-u^2}} \), we obtain the arcsine of \( \frac{u}{a} \), plus a constant \( C \). This is essential in solving integrals that arise in geometry and physics where inverse trigonometric functions are involved.

The constant \( C \) is important because integration results in a family of functions, and \( C \) accounts for all the possible vertical shifts of this family. Mastering these formulas helps to solve complex integrals effectively in various applications.

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