Chapter 5: Problem 6
In Exercises \(5-10\) evaluate the expression without using a calculator. $$\log _{3} 81$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 5: Problem 6
In Exercises \(5-10\) evaluate the expression without using a calculator. $$\log _{3} 81$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
In Exercises 43-46, use the specified substitution to find or evaluate the integral. $$\begin{array}{l}{\int_{1}^{3} \frac{d x}{\sqrt{x}(1+x)}} \\\ {u=\sqrt{x}}\end{array}$$
Think About It Use two different methods to find the limit $$\lim _{x \rightarrow \infty} \frac{\ln x^{m}}{\ln x^{n}}$$ where \(m>0, n>0,\) and \(x>0\)
Given \(e^{x} \geq 1\) for \(x \geq 0,\) it follows that $$ \int_{0}^{x} e^{t} d t \geq \int_{0}^{x} 1 d t $$ $$ \begin{array}{l} e^{x} \geq 1+x \\ \text { for } x \geq 0 \end{array} $$
In Exercises \(7-14\) , evaluate the expression without using a calculator. arcsec 2
In Exercises 51 and 52, show that the antiderivatives are equivalent. $$\int \frac{6}{4+9 x^{2}} d x=\arctan \frac{3 x}{2}+C \text { or arccsc } \frac{\sqrt{4+9 x^{2}}}{3 x}+C$$
What do you think about this solution?
We value your feedback to improve our textbook solutions.