Chapter 5: Problem 134
If \(f(x)=g(x) e^{x},\) then the only zeros of \(f\) are the zeros of \(g\)s.
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Chapter 5: Problem 134
If \(f(x)=g(x) e^{x},\) then the only zeros of \(f\) are the zeros of \(g\)s.
These are the key concepts you need to understand to accurately answer the question.
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In Exercises 51 and 52, show that the antiderivatives are equivalent. $$\int \frac{6}{4+9 x^{2}} d x=\arctan \frac{3 x}{2}+C \text { or arccsc } \frac{\sqrt{4+9 x^{2}}}{3 x}+C$$
Calculus History InL'Hopital's 1696 calculus textbook, he illustrated his rule using the limit of the function $$f(x)=\frac{\sqrt{2 a^{3} x-x^{4}}-a \sqrt[3]{a^{2} x}}{a-\sqrt[4]{a x^{3}}}$$ as \(x\) approaches \(a, a>0 .\) Find this limit.
Think About It Use a graphing utility to graph \(f(x)=\sin x\) and \(g(x)=\arcsin (\sin x)\) (a) Explain why the graph of \(g\) is not the line \(y=x\) . (b) Determine the extrema of \(g\) .
Proof \(\quad\) Graph \(y_{1}=\frac{x}{1+x^{2}}, y_{2}=\arctan x,\) and \(y_{3}=x\) on \([0,10] .\) Prove that \(\frac{x}{1+x^{2}} <\arctan x< x\) for \(x >0\)
In Exercises 73-75, verify the rule by differentiating. Let \(a>0.\) $$\int \frac{d u}{u \sqrt{u^{2}-a^{2}}}=\frac{1}{a} \operatorname{arcsec} \frac{|u|}{a}+C$$
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