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Tangent Lines The graph of \(f(x)=-\sin x\) has infinitely many tangent lines that pass through the origin. Use Newton's Method to approximate to three decimal places the slope of the tangent line having the greatest slope.

Short Answer

Expert verified
The slope of the tangent line from the origin that has the greatest slope on the curve of the function \(f(x)=-\sin x\) is approximately equal to the value of \(-\cos x\) evaluated at the x-coordinate found by Newton's Method.

Step by step solution

01

Find the derivative

The slope of the tangent at any point on the curve of a function is given by the derivative of the function. Differentiate the given function to obtain \(f'(x) = -\cos x\). This derivative function gives the slope of the tangent line to the function at any point x.
02

Find the slope

The question asks for the tangent from the origin, meaning the line passes through the point (0,0), to have maximum slope. The x-coordinate at which the slope is maximum can be found by setting the derivative equal to zero and solving for x. Doing this gives -\(\cos x = 0\), solving this equation gives x = \(\frac{\pi}{2}\) + k\(\pi\) where k is any integer. However, -\(\sin x\) has maximum values at -\(\pi\), -3\(\pi\), ... because the slope is positive there while we are looking for the maximum positive slope.
03

Apply Newton's Method

Newton's Method is iterative and can be used to approximate roots of equations. Start with an initial approximation for x, say x0 = -\(\frac{\pi}{2}\). The updated value can be calculated using the formula \(x_{1} = x_{0} - \frac{f'(x_{0})}{f''(x_{0})}\) where \(f''(x_{0})\) is the second derivative at \(x_{0}\). As \(f(x)=-sinx\), \(f''(x) = -\sin x\). Plugging in, the x-coordinate where slope is maximum will be approximated. Repeat the process by plugging \(x_{1}\) back into the formula until the difference between the new and old estimate is less than a predetermined precision level, say 0.001.
04

Determine the maximum slope

The maximum slope of the tangent line from the origin is the derivative evaluated at the approximation for x from Newton's Method.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Lines
A tangent line is a straight line that touches a curve at a single point without crossing it. This point of tangency is where the slope of the tangent line is equal to the slope of the curve. The equation of a tangent line to a curve at a given point provides valuable information about the behavior of the curve at that specific location.
The tangent line at any point \(x\) can be described by the formula \((y - f(x)) = f'(x)(x - x_0)\), where \(f'(x)\) is the derivative of the function, indicating the slope at \(x\).
Understanding tangent lines helps us visualize how the function changes, offering insights into its growth, decline, and other characteristics. In the context of this exercise, we seek a tangent line crossing an origin, aiming to find one with maximum positive slope.
Derivative
The derivative of a function is a mathematical tool that tells us how the function's output changes as its input changes. Basically, it gives us the slope of the function at any given point.
In our exercise, we start with the function \(f(x) = -\sin x\). Taking the derivative of this function gives us \(f'(x) = -\cos x\), which represents the slope of the curve at any point \(x\).
The formula for a derivative \(f'(x)\) is often called the "instantaneous rate of change." It shows us how the function behaves in an infinitesimally small neighborhood around the point \(x\).
Derivatives are useful in finding points of tangency, understanding function behavior, and solving optimization problems, like finding a maximum slope in this exercise.
Slope
Slope is the measure of how steep a line is. In terms of a curve, it tells us how rapidly the function increases or decreases. If a slope is positive, the function is rising; if negative, the function is falling.
In the context of tangent lines and derivatives, the slope at a particular point \(x\) on the curve is given by the derivative \(f'(x)\). For \(-\sin x\), the slope is \(-\cos x\).
A tangent from the origin to the curve \(f(x) = -\sin x\) is being analyzed for maximum slope—a crucial step because this tells us the line that is most rapidly climbing from the origin to touch the curve. This slope translates into the maximum positive value obtained using the derivative.
Iterative Approximation
Iterative approximation is a technique to find an increasingly accurate solution to a problem using repeated approximations. Newton's Method is a famous iterative process used to find roots of a function.
In our exercise, we apply Newton's Method to find the point with the maximum slope of the tangent line. Start with an initial guess, \(x_0\), then use the formula \(x_{n+1} = x_n - \frac{f'(x_n)}{f''(x_n)}\).
  • Begin with an initial guess, \(-\frac{\pi}{2}\).
  • Compute a successive approximation using the formula.
  • Continue iterations until the approximated value is sufficiently accurate, within a margin of 0.001.
This method converges quickly, providing an efficient solution to approximate the x-coordinate where the slope is maximum, thereby determining the line with the greatest slope from the origin.

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Most popular questions from this chapter

Highway Design In order to build a highway, it is necessary to fill a section of a valley where the grades (slopes) of the sides are 9\(\%\) and 6\(\%\) (see figure). The top of the filled region will have the shape of a parabolic arc that is tangent to the two slopes at the points \(A\) and \(B\) . The horizontal distances from \(A\) to the \(y\) -axis and from \(B\) to the \(y\) -axis are both 500 feet. (a) Find the coordinates of \(A\) and \(B\) (b) Find a quadratic function \(y=a x^{2}+b x+c\) for \(-500 \leq x \leq 500\) that describes the top of the filled region. (c) Construct a table giving the depths \(d\) of the fill for \(x=-500,-400,-300,-200,-100,0,100,200,300\) \(400,\) and 500 . (d) What will be the lowest point on the completed highway? Will it be directly over the point where the two hillsides come together?

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