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Volume and Surface Area The radius of a spherical balloon is measured as 8 inches, with a possible error of 0.02 inch. (a) Use differentials to approximate the possible propagated error in computing the volume of the sphere. (b) Use differentials to approximate the possible propagated error in computing the surface area of the sphere. (c) Approximate the percent errors in parts (a) and (b).

Short Answer

Expert verified
The error in calculating the volume is approximately 0.3%, while the error in calculating the surface area is approximately 0.2%.

Step by step solution

01

Calculate the volume differential

The volume of a sphere is given by \( V = \frac{4}{3}πr^3 \). If \( r \) changes by a small amount \( δr \), the volume changes by a small amount \( δV \). These differentials are related by \( δV = V'(r)δr \), where \( V'(r) \) is the derivative of \( V \) with respect to \( r \). Differentiating the volume, we get \( V'(r) = 4πr^2 \). Substituting \( r = 8 \) and \( δr = 0.02 \), we get \( δV = 4π(8)^2(0.02) = 6.4π \) cubic inches.
02

Calculate the surface area differential

The surface area of a sphere is given by \( A = 4πr^2 \). If \( r \) changes by a small amount \( δr \), the area changes by a small amount \( δA \). These differentials are related by \( δA = A'(r)δr \), where \( A'(r) \) is the derivative of \( A \) with respect to \( r \). Differentiating the area, we get \( A'(r) = 8πr \). Substituting \( r = 8 \) and \( δr = 0.02 \), we get \( δA = 8π(8)(0.02) = 1.28π \) square inches.
03

Calculate the percent error for volume

The percent error is given by the formula \( 100 \times \frac{δV}{V} \). Substituting \( V = \frac{4}{3}π(8)^3 \) and \( δV = 6.4π \), the volume percent error is \( 100 \times \frac{6.4π}{\frac{4}{3}π(8)^3} = 0.3\% \).
04

Calculate the percent error for surface area

The percent error is given by the formula \( 100 \times \frac{δA}{A} \). Substituting \( A = 4π(8)^2 \) and \( δA = 1.28π \), the surface area percent error is \( 100 \times \frac{1.28π}{4π(8)^2} = 0.2\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volume of a Sphere
The volume of a sphere is an essential formula in geometry, often used when dealing with three-dimensional objects. The formula for the volume of a sphere is given by \[ V = \frac{4}{3}\pi r^3 \] where \( V \) stands for volume and \( r \) represents the radius of the sphere. Think of the radius as the distance from the center of the sphere to any point on its surface.
This formula highlights how the volume changes dramatically with a change in radius, as the radius is cubed. For example, increasing the radius will greatly increase the volume, showcasing the sensitivity of volume to changes in radius. When dealing with measurements where precision is key, such as determining possible errors, understanding this relationship becomes crucial.
Surface Area of a Sphere
The surface area of a sphere measures the total area that the surface of the sphere occupies. It is calculated using the formula \[ A = 4\pi r^2 \] where \( A \) is the surface area and \( r \) is the radius of the sphere. Here, the radius is squared, which means the surface area is sensitive to changes in the radius, but not as much as the volume.
Knowing the surface area is essential in many practical applications such as coating a spherical object with paint or calculating heat emissions from spherical objects. Changes in surface area due to changes in radius can be approximated using differentials, providing an insightful method to estimate errors associated with measurement.
Propagated Error
Propagated error is the error that results when a small change in measurement is carried through a mathematical formula or function. This is particularly useful for estimating errors in calculated results based on given measurements.
For the volume of a sphere, if the radius changes by a small amount \( \delta r \), the propagated error in the volume (\( \delta V \)) can be determined using the derivative of the volume formula: \[ \delta V = V'(r) \delta r = 4\pi r^2 \delta r \]
Similarly, for the surface area of the sphere, a small change \( \delta r \) results in a propagated error \( \delta A \), calculated by: \[ \delta A = A'(r) \delta r = 8\pi r \delta r \]
Understanding propagated errors helps in evaluating the reliability of measurements and calculations, and in ensuring greater accuracy in practical scenarios.
Percent Error Calculations
Percent error is a useful tool in determining the accuracy of a measurements in relation to its theoretical or actual value. It gives a snapshot of how significant an error is relative to the size of what you’re measuring.
For example, when calculating the percent error for the volume of a sphere, the formula used is: \[ \text{Percent Error for Volume} = 100 \times \frac{\delta V}{V} \] where \( \delta V \) is the propagated error in volume and \( V \) is the original volume.
For surface area, percent error is given by: \[ \text{Percent Error for Surface Area} = 100 \times \frac{\delta A}{A} \] This quantification allows for a clearer perspective on how errors affect overall calculations, especially when comparing different scenarios or determining the precision needed for specific applications.

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