/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 In Exercises 13-16, find each li... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 13-16, find each limit, if it exists. (a) $$\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 x^{2}+1}$$ (b) $$\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 x^{3 / 2}+1}$$ (c) $$\lim _{x \rightarrow \infty} \frac{5 x^{3 / 2}}{4 \sqrt{x}+1}$$

Short Answer

Expert verified
Therefore, the limit of the first function is 0, the limit of the second function is \(\frac{5}{4}\), and the limit of the third function is infinity.

Step by step solution

01

Find limit of the first function

To find the limit of the first ratio as \(x \rightarrow \infty\), we divide every term in the function by the highest power of \(x\) in the denominator, which is \(x^2\). So our function becomes: \[ \lim_{x \rightarrow \infty} \frac{5x^{3/2}/ x^2}{4x^2/x^2 + 1/x^2} \]. This simplifies to \[ \lim_{x \rightarrow \infty} \frac{5/\sqrt{x}}{4 + 1/x^2} \]. As \(x \rightarrow \infty\), \(5/\sqrt{x}\) and \(1/x^2\) both approach 0. So: \[ \lim_{x \rightarrow \infty} \frac{5/\sqrt{x}}{4 + 1/x^2} = \frac{0}{4 + 0} = 0\]. Therefore, the limit of the first function is 0.
02

Find limit of the second function

For the second function, which is \[ \lim_{x \rightarrow \infty} \frac{5x^{3 / 2}}{4x^{3 / 2} + 1} \], we again divide every term in the function by the highest power of \(x\) in the denominator, which is \(x^{3/2}\). So our function becomes: \[ \lim_{x \rightarrow \infty} \frac{5x^{3/2}/x^{3/2}}{4x^{3/2}/x^{3/2} + 1/x^{3/2}} = \lim_{x \rightarrow \infty} \frac{5}{4 + 1/\sqrt{x}} \]. As \(x \rightarrow \infty\), \(1/\sqrt{x}\) approaches 0. So: \[ \lim_{x \rightarrow \infty} \frac{5}{4 + 1/\sqrt{x}} = \frac{5}{4 + 0} = \frac{5}{4} \]. Therefore, the limit of the second function is \(\frac{5}{4}\).
03

Find limit of the third function

To find the limit of the third function, which is \[ \lim_{x \rightarrow \infty} \frac{5x^{3 / 2}}{4\sqrt{x} + 1} \], we divide every term in the function by the highest power of \(x\) in the denominator, which is \(\sqrt{x}\). So our function becomes: \[ \lim_{x \rightarrow \infty} \frac{5x^{3/2}/\sqrt{x}}{4\sqrt{x}/\sqrt{x} + 1/\sqrt{x}} = \lim_{x \rightarrow \infty} \frac{5\sqrt{x}}{4 + 1/\sqrt{x}} \]. As \(x \rightarrow \infty\), \(1/\sqrt{x}\) approaches 0 and \(\sqrt{x}\) becomes infinity. So: \[ \lim_{x \rightarrow \infty} \frac{5\sqrt{x}}{4 + 1/\sqrt{x}} = \frac{5\cdot \infty}{4 + 0} = \infty\]. Therefore, the limit of the third function is \(\infty\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinity
Infinity is a concept that represents a quantity without bound or end. In mathematical terms, when we say a limit approaches infinity, it means the value grows larger and larger without stopping.
As we analyze the behavior of functions as the variable approaches infinity, we are essentially looking at how function values trend towards a limitless state.
Infinity is not a number but a concept. It helps us understand the behavior of functions that grow indefinitely. For instance, in the exercise, when dealing with the limits, we are often observing what happens to expressions like \(\frac{1}{x}\) as \(x\) goes to infinity. This value diminishes to zero, providing crucial insight into the asymptotic behavior.
Rational Functions
Rational functions are algebraic expressions formed by the ratio of two polynomials. An example is \(\frac{5x^{3/2}}{4x^2+1}\), where both the numerator and the denominator are polynomials.
Analyzing rational functions often involves understanding their behavior as the variable grows. Such analysis includes simplifying, finding limits, or evaluating at specific points.
  • The degree of the polynomial helps determine the behavior and limits of the rational function as variables tend towards infinity.
  • Simplification, as per steps in the solution, involves dividing by the highest power of \(x\) in the denominator.

This process requires understanding how terms in the numerator and denominator compare in magnitude as \(x\) becomes very large.
Asymptotic Behavior
Asymptotic behavior analyzes how a function behaves as the variable approaches a particular value, often infinity. It describes the trends and tendencies of a function, essentially showcasing how it grows or declines.
Such behavior is crucial when studying limits. Functions may approach a particular line (an asymptote) but never actually reach it.
In our exercises, asymptotic behavior is observed by simplifying rational expressions and determining how they behave as \(x\) approaches infinity. This helps predict whether the function converges to a finite value, diverges, or approaches zero.
  • For example, the asymptotic behavior of \(\frac{5\sqrt{x}}{4+1/\sqrt{x}}\) indicates that as \(x\) becomes extremely large, the function value trends towards infinity, showcasing the divergence to infinity.
Simplification
Simplification is a technique used to make mathematical expressions easier to evaluate or understand. In the case of limits involving polynomials, it typically involves reducing the complexity by canceling out common terms or factors.
In our exercises, simplification is key to finding limits. Here’s a simple approach:
  • Identify the highest degree or power of \(x\) in the denominator.
  • Divide each term by this power across the function.

This process often results in terms that approach zero or a simplified expression, making it easier to evaluate the limit as \(x\) approaches infinity. For example, simplifying \(\frac{5x^{3/2}/x^{3/2}}{4x^{3/2}/x^{3/2} + 1/x^{3/2}}\) helps us directly evaluate the expression to determine its long-term behavior or limit.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Minimum Distance, consider a fuel distribution center located at the origin of the rectangular coordinate system (units in miles; see figures). The center supplies three factories with coordinates \((4,1),(5,6),\) and \((10,3) .\) A trunk line will run from the distribution center along \((10,3) .\) A trunk line will run from the distribution center along the line \(y=m x,\) and feeder lines will run to the three factories. The objective is to find \(m\) such that the lengths of the feeder lines are minimized. Minimize the sum of the absolute values of the lengths of the vertical feeder lines (see figure) given by $$S_{2}=|4 m-1|+|5 m-6|+|10 m-3|$$ Find the equation of the trunk line by this method and then determine the sum of the lengths of the feeder lines. (Hint: Use a graphing utility to graph the function S2 and approximate the required critical number.)

\(\begin{array}{l}{\text { Prove that if } f \text { and } g \text { are positive, increasing, and concave }} \\ {\text { upward on the interval }(a, b), \text { then } f g \text { is also concave upward }} \\ {\text { on }(a, b) .}\end{array}\)

Slant Asymptote In Exercises \(71-76,\) use a graphing utility to graph the function and determine the slant asymptote of the graph analytically. Zoom out repeatedly and describe how the graph on the display appears to change. Why does this occur? $$f(x)=\frac{2 x^{3}}{x^{2}+1}$$

The Mean Value Theorem can be applied to \(f(x)=\tan x\) on the interval \([0, \pi / 4] .\)

Finding a Solution In Exercises \(65-68\) , use the Intermediate Value Theorem and Rolle's Theorem to prove that the equation has exactly one real solution. \(2 x-2-\cos x=0\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.