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Finding the Area of a Polar Region Between Two Curves In Exercises \(37-44\) , use a graphing utility to graph the polar equations. Find the area of the given region analytically. Inside \(r=3 \sin \theta\) and outside \(r=1+\sin \theta\)

Short Answer

Expert verified
The area of the region inside \(r = 3 \sin \theta\) and outside \(r = 1 + \sin \theta\) is \(2\pi\).

Step by step solution

01

Find intersecting points

To start, the intersecting points of the two curves must be found. This is done by setting the equations equal to each other and solving for \(\theta\), as such: \(3 \sin \theta = 1 + \sin \theta\). This gives us the solutions \(\theta = 0\) and \(\theta = \pi\).
02

Find the area using integration

Next, once the intersecting points have been found, one must use these values to set up the integral to find the area. The formula to find the area for polar coordinates is \(A = 1/2 \int^b_a (f(\theta))^2 - (g(\theta))^2 d\theta\), where \(f(\theta)\) is the larger curve and \(g(\theta)\) is the smaller curve. In this case, \(f(\theta) = 3 \sin \theta\) and \(g(\theta) = 1 + \sin \theta\), and the limits of integration are \(a = 0\) and \(b = \pi\). Plugging these values into the equation gives \(A = 1/2 \int^\pi_0 (3 \sin \theta)^2 - (1 + \sin \theta)^2 d\theta\).
03

Simplify the integral

To resolve the integral, the expressions within it should be squared and simplified. This gives \(A = 1/2 \int^\pi_0 (9 \sin^2 \theta) - (1 + 2\sin\theta + \sin^2\theta) d\theta = 1/2 \int^\pi_0 8\sin^2\theta - 2\sin\theta d\theta\).
04

Solve the integral

The remaining step is to solve the integral, which yields \(A = 1/2 [\int^\pi_0 8\sin^2\theta d\theta - \int^\pi_0 2\sin\theta d\theta]\). Solving these integrals gives \(A = 1/2 [8(\pi/2) - 2(1 - 1)] = 2\pi\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intersecting Points
When dealing with polar coordinates and trying to find the area between two curves, we must start by finding their intersecting points. This is because these points help us set the boundaries for our calculations. To find intersecting points, we equate the given polar equations to identify the angle(s) \(\theta\) where they intersect. In the example problem, the two polar equations are \(r = 3 \sin \theta\) and \(r = 1 + \sin \theta\). By setting them equal to each other: \(3 \sin \theta = 1 + \sin \theta\), and solving for \(\theta\), we arrive at the points \(\theta = 0\) and \(\theta = \pi\). These angles are crucial as they define the starting and ending bounds for our area calculations.
Integration
Integration is a mathematical technique used to find the area under a curve or between curves in various coordinate systems, including polar coordinates. Once we have the intersecting points, which serve as the limits of our integration, we can set up an integral to calculate the desired area. The formula for finding the area enclosed by two polar curves \(f(\theta)\) and \(g(\theta)\) over a range from \(a\) to \(b\) is:
  • \(A = \frac{1}{2} \int_{a}^{b} (f(\theta))^2 - (g(\theta))^2 \, d\theta\)
In our problem, \(f(\theta) = 3 \sin \theta\) is the larger curve, and \(g(\theta) = 1 + \sin \theta\) is the smaller one. The integration calculates the difference between the areas covered by these curves, yielding the area of the region they enclose.
Polar Equations
Polar equations describe curves in terms of a radius \(r\) and an angular coordinate \(\theta\). Unlike Cartesian coordinates, polar coordinates provide a way to model curves based on angles and distances from a central point. When working with polar equations, we express them as \(r = f(\theta)\), where the radius \(r\) depends on the angle \(\theta\).
  • For instance, in the given problem, we had \(r = 3 \sin \theta\) and \(r = 1 + \sin \theta\).
  • These represent two different curves that define the shapes and regions we're interested in.
Understanding polar equations' behavior is crucial for determining which curve is larger or smaller over a certain interval of \(\theta\). This knowledge enables correct setup of integration limits and expressions to find areas between such curves.
Limits of Integration
The limits of integration are values that define the start and end of the integration process. In the context of finding the area between polar curves, these limits correspond to the angles \(\theta\) at which the curves intersect.
  • In our example, the limits were found to be \(\theta = 0\) and \(\theta = \pi\).
  • These boundaries are critical because they determine the part of the curve over which you need to integrate.
Selecting incorrect limits could result in calculating the area over a wrong portion of the graph or even an entirely different region. Correctly identifying and applying the limits of integration ensures precise computation of the area between the polar curves.

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Most popular questions from this chapter

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