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Using Parametric Equations In Exercises \(5-22,\) sketch the curve represented by the parametric equations (indicate the orientation of the curve), and write the corresponding rectangular equation by eliminating the parameter. $$x=t-3, \quad y=\frac{t}{t-3}$$

Short Answer

Expert verified
The corresponding rectangular equation is \(y = 1 + \frac{3}{x}\). The curve moves from right to left as the parameter increases

Step by step solution

01

Express parameter t in terms of x

From the first equation \(x = t-3\), we solve for \(t\) to get \(t = x+3\)
02

Substitute t in the second equation

Substitute \(t\) from Step 1 into the second equation \(y= \frac{t}{t-3}\) to get \(y = \frac{x+3}{x}\). This simplification gets us to the rectangular equation
03

Simplify the equation

Continuing from the second step, you can simplify the equation further to \(y = 1 + \frac{3}{x}\) which is the rectangular form of the given parametric equation.
04

Plotting Orientation

The curve moves from right to left as t increases. As \(t\rightarrow -\infty\), \(x\rightarrow +\infty\) and as \(t\rightarrow +\infty\), \(x\rightarrow -3\). This indicates the direction of the graph.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eliminating the Parameter
When working with parametric equations, eliminating the parameter helps to convert the pair of equations into a single 'rectangular equation', which is a familiar form for many students. The rectangular equation relates x and y directly without the parameter.

In our example, the given parametric equations are \(x = t - 3\) and \(y = \frac{t}{t - 3}\). To eliminate the parameter 't', we solved the first equation for 't', obtaining \(t = x + 3\). Then, by substituting this expression into the second equation, we derived the equation \(y = \frac{x + 3}{x}\), which simplifies to \(y = 1 + \frac{3}{x}\). The latter is the rectangular equation, expressing y solely as a function of x without involving the parameter 't'. This process not only simplifies computations but also allows for a clearer analysis of the curve's properties.
Rectangular Equation
The rectangular equation is the end goal when eliminating a parameter from parametric equations. It is called 'rectangular' because it directly references the Cartesian (x, y) axes, providing a straightforward relationship between them.

In the exercise, we transformed the parametric equations into the rectangular form \(y = 1 + \frac{3}{x}\). This equation can be used to graph the curve in a conventional x-y coordinate system without needing to calculate the parameter 't' for different points. It is an essential form for analyzing the curve's behavior, intercepts, and asymptotes. For instance, in our equation, we can observe that there is a vertical asymptote at \(x = 0\) and a horizontal asymptote at \(y = 1\), which are key characteristics of the graph.
Curve Sketching
Curve sketching involves drawing the graph of an equation on the coordinate plane. It provides a visual representation of the relationship between the variables, which is particularly useful for understanding the behavior and characteristics of the curve.

The rectangular form \(y = 1 + \frac{3}{x}\) from the given parametric equations makes it easier to sketch the curve by plotting key features such as intercepts, asymptotes, and turning points. These features give insight into the curve's shape and help determine the regions where the curve lies. Curve sketching is not only a valuable tool for visualization but also for predicting the behavior of the curve under different conditions.
Graph Orientation
Graph orientation refers to the direction in which a curve is drawn on the graph as the parameter 't' increases or decreases. It indicates the 'flow' of the curve over the parameter's range.

In our exercise, the orientation of the curve is inferred by observing how the coordinates (x, y) change as 't' varies. As \(t \rightarrow -\infty\), \(x\) approaches positive infinity, indicating that the curve begins far to the right on the x-axis. As \(t \rightarrow +\infty\), \(x\) approaches -3, implying that the curve approaches the vertical asymptote from the right. Knowing the orientation is crucial for correctly sketching the curve and understanding phenomena such as particle motion along a path described by parametric equations.

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Most popular questions from this chapter

Identifying and Sketching a Conic In Exercises \(13-22\) , find the eccentricity and the distance from the pole to the directrix of the conic. Then identify the conic and sketch its graph. Use a graphing utility to confirm your results. $$r=\frac{6}{-2+3 \cos \theta}$$

Using Parametric Equations $$\begin{array}{l}{\text { (a) Use a graphing utility to graph the curve given by }} \\ {x=\frac{1-t^{2}}{1+t^{2}} \text { and } y=\frac{2 t}{1+t^{2}}, \quad-20 \leq t \leq 20.}\end{array}$$ $$\begin{array}{l}{\text { (b) Describe the graph and confirm your result analytically. }} \\ {\text { (c) Discuss the speed at which the curve is traced as } t} \\ {\text { increases from }-20 \text { to } 20 \text { . }}\end{array}$$

EXPLORING CONCEPTS Using Different Methods In Exercises 71 and \(72,\) (a) sketch the graph of the polar equation, (b) determine the interval that traces the graph only once, (c) find the area of the region bounded by the graph using a geometric formula, and (d) find the area of the region bounded by the graph using integration. $$r=10 \cos \theta$$

Finding a Polar Equation In Exercises \(33-38\) , find a polar equation for the conic with its focus at the pole and the given eccentricity and directrix. (For convenience, the equation for the directrix is given in rectangular form.) $$\begin{array}{ll}{\text { Conic }} & {\text { Eccentricity }} \\ {\text { Parabola }} & {e=1}\end{array} \begin{array}{l}{\text { Directrix }} \\\ {x=-3}\end{array}$$

Identifying and Sketching a Conic In Exercises \(13-22\) , find the eccentricity and the distance from the pole to the directrix of the conic. Then identify the conic and sketch its graph. Use a graphing utility to confirm your results. $$r=\frac{10}{5+4 \sin \theta}$$

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