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Finding a Limit In Exercises \(11-30\) , find the limit (if it exists). If it does not explain why. $$\lim _{x \rightarrow 1^{+}} f(x), \text { where } f(x)=\left\\{\begin{array}{ll}{x,} & {x \leq 1} \\ {1-x,} & {x>1}\end{array}\right.$$

Short Answer

Expert verified
The limit of \(f(x)\) as \(x\) approaches \(1^{+}\) is \(0\).

Step by step solution

01

Identify the Active Part of the Piecewise Function

Figure out which part of the function is relevant when \(x\) approaches \(1^{+}\), which is the limit from the right. In this case, since \(x>1\), the part of the function we're interested in is \(f(x) = 1 - x\).
02

Plug in the Limit Value

Substitute \(1\) into the equation \(f(x) = 1 - x\). This will give us the output of the function as \(x\) approaches \(1\) from the right.
03

Determine the Limit

Since this is a simple linear function, the value of the function at \(x = 1\) from the right side will be the limit. Therefore, we calculate \(1 - 1 = 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Functions
Piecewise functions are a type of function that behave differently based on the input value. They are defined by multiple sub-functions, each applying to a certain "piece" of the entire domain. These pieces or segments are determined by conditions specified for the input variable, usually denoted as "x".

In the given exercise, the function \( f(x) \) is piecewise, meaning it is split into two parts: \( x \) for \( x \leq 1 \) and \( 1-x \) for \( x > 1 \). This reflects real-world scenarios where different processes might control an outcome based on circumstances.

Understanding the working mechanism of each piece is crucial to tackling problems involving piecewise functions. We decide which piece is "active" based on the conditions given for the input. This is especially important when calculating limits, where knowing how the function behaves at a boundary or transition point is necessary.
Right-Hand Limit
A right-hand limit focuses on the behavior of a function as the input approaches a particular value from the right. In other words, we consider values slightly greater than the point of interest to determine limits from this direction.

Mathematically, this is notated as \( \lim_{x \to c^+} f(x) \). It represents the value that \( f(x) \) approaches as \( x \) gets closer to "c" from values greater than "c".

In the exercise provided, our task is to find \( \lim_{x \rightarrow 1^{+}} f(x) \). Because we are dealing with a piecewise function, we examine the piece where \( x > 1 \), thus focusing on the part \( f(x) = 1 - x \). By substituting \( x = 1 \) and observing values from the right, we can efficiently determine the function's behavior at \( x = 1 \).
Linear Functions
Linear functions are among the simplest types of functions. They are represented by equations that form straight lines when graphed on a coordinate plane. Their general form is \( f(x) = ax + b \), where "a" is the slope and "b" is the y-intercept.

These functions have continuous and predictable behavior, which makes them easy to analyze when finding limits. Since they don't contain any jumps or breaks, evaluating their limits as \( x \) approaches any point often involves straightforward substitution.

In our exercise, one of the pieces of the piecewise function is \( 1 - x \), a linear function. By directly substituting \( x = 1 \) into this linear portion, we smoothly arrive at the limit without complex calculations. Linear functions' simplicity ensures efficiency and precision in limit evaluations, especially when dealing with piecewise functions which might otherwise be complex.

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Most popular questions from this chapter

True or False? In Exercises 65-68, determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The graph of a function cannot cross a vertical asymptote.

Proof (a) Given that $$\lim _{x \rightarrow 0}(3 x+1)(3 x-1) x^{2}+0.01=0.01$$ prove that there exists an open interval \((a, b)\) containing 0 such that \((3 x+1)(3 x-1) x^{2}+0.01>0\) for all \(x \neq 0\) in \((a, b) .\) (b) Given that $$\lim _{x \rightarrow c} g(x)=L,$$ where \(L>0,\) prove that there exists an open interval \((a, b)\) containing \(c\) such that \(g(x)>0\) for all \(x \neq c\) in \((a, b) .\)

True or False? In Exercises \(115-120\) , determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false.. $$\lim _{x \rightarrow 0} \frac{|x|}{x}=1$$

In Exercises 101 and \(102,\) use the position function\(s(t)=-16 t^{2}+500,\) which gives the height (in feet) of an object that has fallen for \(t\) seconds from a height of 500 feet. The velocity at time \(t=a\) seconds is given by $$\lim _{t \rightarrow a} \frac{s(a)-s(t)}{a-t}$$ A construction worker drops a full paint can from a height of 500 feet. How fast will the paint can be falling after 2 seconds?

Inventory Management The number of units in inventory in a small company is given by $$N(t)=25\left(2\left[\frac{t+2}{2}\right]-t\right)$$ where \(t\) is the time in months. Sketch the graph of this function and discuss its continuity. How often must this company replenish its inventory?

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