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Evaluating a Limit In Exercises \(11-42,\) evaluate the limit, using L'Hopital's Rule if necessary. $$ \lim _{x \rightarrow \infty} \frac{x}{\sqrt{x^{2}+1}} $$

Short Answer

Expert verified
The limit as \(x\) approaches infinity of \(\frac{x}{\sqrt{x^{2}+1}}\) is \( \infty \)

Step by step solution

01

Check for Indeterminate Form

First, substitute \(x = \infty\) into the function: \[ \frac{\infty}{\sqrt{\infty^{2}+1}} = \frac{\infty}{\infty} \] This is an indeterminate form, so L'Hopital's Rule can be applied.
02

Apply L'Hopital's Rule

To apply L'Hopital's Rule, take the derivative of the numerator and the derivative of the denominator separately: The derivative of \(x\) is \(1\). The derivative of \(\sqrt{x^{2}+1}\) can be found using the chain rule to be \( \frac{x}{\sqrt{x^{2}+1}} \) . So, the function becomes: \[ \frac{1}{\frac{x}{\sqrt{x^{2}+1}}} \] This simplifies to: \[ \sqrt{x^{2}+1} \]
03

Evaluate the Limit

Finally, substitute \(x = \infty\) into this new function to find the limit: \[ \lim _{x \rightarrow \infty} \sqrt{x^{2}+1} = \infty \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Evaluating Limits
When we talk about evaluating limits, we're trying to understand the behavior of a function as the input approaches a certain value. For example, what happens to the value of a function as x approaches infinity or a specific number? It's a fundamental concept in calculus that helps us make predictions about functions in various scenarios. Sometimes, as in the exercise \[\lim _{x \rightarrow \infty} \frac{x}{\sqrt{x^{2}+1}}\] the limit is straightforward to evaluate directly by substitution — but not always.

Our job becomes more challenging when direct substitution leads to an indeterminate form like 0/0 or \(\infty/\infty\). This is where tools such as L'Hopital's Rule come in handy, allowing us to transform the limit into a form that we can evaluate more directly.
Indeterminate Forms
In calculus, an indeterminate form is an expression that does not have a clear and immediate limit. Common examples of indeterminate forms include 0/0, \(\infty/\infty\), \(\infty - \infty\), and more. They are called 'indeterminate' because the limit could potentially be any real number, infinity, or nonexistent depending on the behavior of the functions involved.

When we face an indeterminate form like \(\frac{\infty}{\infty}\) in our exercise, simply plugging in values will not yield a meaningful answer. To move forward, we use techniques like L'Hopital's Rule, which relies on the properties of derivatives to resolve these forms. It is important for students to recognize an indeterminate form before applying L'Hopital's Rule because it only applies in these specific cases.
Derivative Application
The application of derivatives is an important aspect of calculus, especially when dealing with limits and indeterminate forms. As seen in the exercise, L'Hopital's Rule uses derivatives to find limits of ratios of functions when direct substitution results in an indeterminate form. It simplifies the process by allowing us to focus on the rates of change rather than the functions themselves. To apply the rule correctly, we must calculate the derivative of the numerator and the derivative of the denominator independently.

In the given exercise, we applied the chain rule to find the derivative of the denominator, which in turn transformed the original indefinite expression into one that can be easily evaluated by substituting \(x = \infty\). Understand that whenever the derivatives of the numerator and the denominator are continuous and the limit of their ratio can be determined, L'Hopital's Rule is a reliable method for evaluating limits with indeterminate forms.

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Most popular questions from this chapter

Continuous Function In Exercises 101 and \(102,\) find the value of \(c\) that makes the function continuous at \(x=0\) . $$ f(x)=\left\\{\begin{array}{ll}{\left(e^{x}+x\right)^{1 / x},} & {x \neq 0} \\\ {c,} & {x=0}\end{array}\right. $$

Evaluating an Improper Integral In Exercises \(33-48\) determine whether the improper integral diverges or converges. Evaluate the integral if it converges, and check your results with the results obtained by using the integration capabilities of a graphing utility. $$ \int_{1}^{\infty} \frac{1}{x \ln x} d x $$

Comparison Test for Improper Integrals In some cases, it is impossible to find the exact value of an improper integral, but is important to determine whether the integral converges or diverges. Suppose the functions \(f\) and \(g\) are continuous and \(0 \leq g(x) \leq f(x)\) on the interval \([a, \infty) .\) It can be shown that if \(\int a_{a}^{\infty} f(x) d x\) converges, then \(\int_{a}^{\infty} g(x) d x\) also converges, and if \(\int_{a}^{\infty} g(x) d x\) diverges, then \(\int_{a}^{\infty} f(x) d x\) also diverges. This is known as the Comparison Test for improper integrals. (a) Use the Comparison Test to determine whether \(\int_{1}^{\infty} e^{-x^{2}} d x\) converges or diverges. (Hint: Use the fact that \(e^{-x^{2}} \leq e^{-x}\) for \(x \geq 1 . )\) (b) Use the Comparison Test to determine whether \(\int_{1}^{\infty} \frac{1}{x^{5}+1} d x\) converges or diverges. (Hint: Use the fact that \(\frac{1}{x^{5}+1} \leq \frac{1}{x^{5}}\) for \(x \geq 1 . )\)

True or False? In Exercises \(85-88\) , determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If the graph of \(f\) is symmetric with respect to the origin or the \(y\) -axis, then \(\int_{0}^{\infty} f(x) d x\) converges if and only if \(\int_{-\infty}^{\infty} f(x) d x\) converges.

True or False? In Exercises \(85-88\) , determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(f\) is continuous on \([0, \infty)\) and \(\int_{0}^{\infty} f(x) d x\) diverges, then \(\lim _{x \rightarrow \infty} f(x) \neq 0\)

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