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Using Trigonometric Substitution In Exercises \(9-12\) , find the indefinite integral using the substitution \(x=5\) sec \(\theta\) . $$ \int \frac{\sqrt{x^{2}-25}}{x} d x $$

Short Answer

Expert verified
The integral \(\int \frac{\sqrt{x^{2}-25}}{x} d x = 5(\frac{\sqrt{x^2 - 25}}{5} - \sec^{-1} (\frac{x}{5})) + C\).

Step by step solution

01

Substitution

Substitute \(x=5 \sec \theta\). This gives the integral as \(\int \frac{\sqrt{(5\sec \theta)^{2}-25}}{5\sec \theta} d(5\sec \theta)\). Derivative of \(5\sec \theta\) will be \(5\sec \theta \tan \theta\). Replace \(dx\) with \(5\sec \theta \tan \theta d\theta\). So, the integral becomes \(\int \frac{\sqrt{(5\sec \theta)^{2}-25}}{5\sec \theta} \cdot 5\sec \theta \tan \theta d\theta\). Simplifying the integral becomes \(\int 5\tan \theta \sqrt{\sec^2 \theta - 1} d \theta\).
02

Further simplifying the integral

Here notice that \(\sqrt{\sec^2 \theta - 1}\) is simply \(\tan \theta\). Because \(\tan^2 \theta = \sec^2 \theta - 1\), taking the square root of both sides gives \(\sqrt{\sec^2 \theta - 1} =\tan \theta\). Hence, the integral simplifies to \(\int 5\tan^2 \theta d \theta\).
03

Solving the integral

Finally, we can compute the integral. \(\int 5\tan^2 \theta d \theta = 5\int \tan^2 \theta d \theta\). The integral of \(\tan^2 \theta\) can be solved as \(\int \tan^2 \theta d \theta = \int (\sec^2 \theta - 1) d \theta = \tan \theta - \theta + C\). Multiplication gives us \(5\int \tan^2 \theta d \theta = 5(\tan \theta - \theta) + C\). Remembering that \(\tan \theta = \frac{\sqrt{x^2 - 25}}{5}\), we can substitute back \(5(\tan \theta - \theta) + C = 5(\frac{\sqrt{x^2 - 25}}{5} - \theta) + C.\)
04

Back-substitution

Last step is to substitute \(\theta\). The original substitution was \(x=5 \sec \theta\), so we can solve for \(\theta = \sec^{-1} (\frac{x}{5})\). Hence the final solution is \(5(\frac{\sqrt{x^2 - 25}}{5} - \sec^{-1} (\frac{x}{5})) + C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Indefinite Integral
The indefinite integral, often represented as \(\int f(x) dx\), is a fundamental concept in calculus that is closely associated with the antiderivative of a function. In practical terms, finding an indefinite integral means determining a function whose derivative is the given function \(f(x)\). One of the key uses of indefinite integrals is in finding the area under a curve.

When solving problems involving indefinite integrals, it is important to remember that the solution includes an arbitrary constant, often denoted as \(C\), since the derivative of a constant is zero. This constant represents the family of all antiderivatives of the function.

In the context of the exercise, the aim is to find the indefinite integral of a function resulting from a trigonometric substitution. This process transforms an algebraic expression into a trigonometric form that is easier to integrate, often revealing functions that we are familiar with and can easily integrate, such as \(\sec^2 \theta\) and \(\tan^2 \theta\).
Secant Function
The secant function, denoted as \(\sec(\theta)\), is one of the six fundamental trigonometric functions. It is the reciprocal of the cosine function, which means \(\sec(\theta) = \frac{1}{\cos(\theta)}\). The secant function has its own unique properties and can become particularly useful in solving integrals involving radical expressions.

Understanding Secant Function Behavior

The secant function, like all trigonometric functions, repeats its values in a periodic way and has a period of \(2\pi\). Unlike the cosine function, which ranges between -1 and 1, the secant function has a range of \( (-\infty, -1] \cup [1, \infty) \). This behavior must be taken into account as it may affect the domain of the integral when performing back-substitution.

It's essential to comprehend the secant function when utilizing trigonometric substitution in integration because it enables us to rewrite expressions like \(\sqrt{x^2 - a^2}\) in terms of \(\theta\), after which the integration becomes more straightforward.
Tangent Function
The tangent function, expressed as \(\tan(\theta)\), is another primary trigonometric function, defined as the ratio of the sine to the cosine function: \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}\). Tangent inherits the periodic properties of its sine and cosine components, with a period of \(\pi\) and a range of all real numbers.

Implementing the Tangent Function in Calculus

One of the powerful applications of the tangent function when dealing with integrals is seen in its relation to the secant function: \(\tan^2(\theta) = \sec^2(\theta) - 1\). This identity is useful to perform integrals that include square roots of secant functions after trigonometric substitution.

In the provided exercise, the square root involving the secant function is seamlessly converted into a simple tangent function square, \(\tan^2(\theta)\), which can be integrated directly. This is an excellent example of how knowledge of trigonometric identities helps in transforming complex-looking integrals into more manageable forms.

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Most popular questions from this chapter

Probability A nonnegative function \(f\) is called a probability density function if $$\int_{-\infty}^{\infty} f(t) d t=1$$ The probability that \(x\) lies between \(a\) and \(b\) is given by $$P(a \leq x \leq b)=\int_{a}^{b} f(t) d t$$ The expected value of \(x\) is given by $$E(x)=\int_{-\infty}^{\infty} t f(t) d t$$ In Exercises 79 and \(80,\) (a) show that the nonnegative function is a probability density function, (b) find \(P(0 \leq x \leq 4),\) and (c) find \(E(x) .\) $$ f(t)=\left\\{\begin{array}{ll}{\frac{2}{5} e^{-2 t / 5},} & {t \geq 0} \\\ {0,} & {t<0}\end{array}\right. $$

Evaluating an Improper Integral In Exercises \(33-48\) determine whether the improper integral diverges or converges. Evaluate the integral if it converges, and check your results with the results obtained by using the integration capabilities of a graphing utility. $$ \int_{0}^{1} x \ln x d x $$

Proof Prove that if \(f(x) \geq 0, \quad \lim _{x \rightarrow a} f(x)=0,\) and \(\lim _{x \rightarrow a} g(x)=\infty,\) then \(\lim _{x \rightarrow a} f(x)^{g(x)}=0 .\)

Compound Interest The formula for the amount \(A\) in a savings account compounded \(n\) times per year for \(t\) years at an interest rate \(r\) and an initial deposit of \(P\) is given by $$A=P\left(1+\frac{r}{n}\right)^{n t}$$ Use L'Hopital's Rule to show that the limiting formula as the number of compoundings per year approaches infinity is given by \(A=P e^{r t} .\)

Improper Integral Consider the integral $$\int_{0}^{3} \frac{10}{x^{2}-2 x} d x$$ To determine the convergence or divergence of the integral, how many improper integrals must be analyzed? What must be true of each of these integrals if the given integral converges?

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