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Volume of a Cone Use the disk method to verify that the volume of a right circular cone is \(\frac{1}{3} \pi r^{2} h,\) where \(r\) is the radius of the base and \(h\) is the height.

Short Answer

Expert verified
The volume of a right circular cone, using the disc method and calculated using integration, is given by the formula: \(V = \frac{1}{3} \pi r^{2} h\).

Step by step solution

01

Identify the Function Representing the Radius

The line segment from the tip of the cone (vertex) to any point on the base circle represents the radius, which we can consider as a function \(f(x) = \frac{r}{h}x\). Here, \(x\) represents a generic disc located at a height \(x\) in the cone.
02

Apply the Disc Method

The volume \(V\) of the solid obtained by revolving the radius about the \(x\)-axis using the disk method is represented by the integral \(\pi \int_{a}^{b} [f(x)]^{2} dx\), where \(a\) is the lowest value and \(b\) is the highest value along \(x\) and \(f(x)\) represents the function being integrated. So, in our case, this becomes, \(V = \pi \int_{0}^{h} [\frac{r}{h}x]^{2} dx.\)
03

Compute the Integral

Rewriting the integral: \(V = \pi \int_{0}^{h} [\frac{r^{2}}{h^{2}}x^{2}] dx\). Using the power rule for integration which state that the integral of \(x^n\) with respect to \(x\) is \(\frac{x^{n+1}}{n+1}\), the integral becomes: \(V = \pi \frac{r^{2}}{h^{2}} \left[\frac{x^{3}}{3}\right]_{0}^{h}\). When we substitute the upper limit \(h\), and then subtract the lower limit \(0\), we get the formula of the volume of the cone, which is \(V = \frac{1}{3} \pi r^{2} h\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Disk Method
The disk method is a powerful tool for finding the volume of solids of revolution, which are figures created when a planar area is revolved around a line, known as the axis of revolution. Imagine slicing the solid into thin disks perpendicular to the axis. Each disk's volume can be approximated by a cylinder's volume formula, \( V = \text\rc{pi} r^2h \), where \( r \) is the radius and \( h \) is the height of the disk, here representing an extraordinarily thin slice of the solid.

Applying the disk method involves integrating the area of these circular disks across the interval you're interested in. In the case of a cone, each disk has a radius that changes depending on its distance from the vertex, forming a linear relationship that we can express as a function in terms of \( x \) along the height of the cone. This method elegantly handles the continuously changing radius and thereby enables the precise calculation of the cone's volume.

Visualizing the Disk Method

When using the disk method for a cone, visualize the radius of each disk growing linearly from the apex to the base as you move along the cone's height. The collection of these disks, when summed up, will describe the volume of the cone.
Integral Calculus
Integral calculus is a branch of mathematics focused on determining the accumulation of quantities and the areas under curves. It is the inverse process of differentiation, where, instead of finding the rate of change, we are summing up small pieces to determine the whole.

For example, when calculating the volume of a right circular cone, integral calculus allows us to sum up the infinitely many thin disks' volumes that make up the cone. The definite integral is the tool we use here, which gives the total accumulation of our variable of interest—in this case, the volume—over a specific interval, represented as the limits of integration from the base to the tip of the cone.

The integral calculus not only provides the algebraic means to calculate volumes but also strengthens conceptual understanding by offering a geometric visualization of the problem at hand. It connects small, simple shapes we can calculate to the complex volume of the entire solid.
Solids of Revolution
Solids of revolution are a class of three-dimensional objects obtained by rotating a two-dimensional plane area around an axis. The resulting solid thus has a symmetry around that axis. Common examples include spheres, cylinders, and cones.

In the context of a right circular cone, we consider it as a solid of revolution formed by rotating a right-angled triangle around one of its two shorter sides, the one opposite the right angle. This rotation sweeps out the cone's volume. Calculating the volume of such shapes relies on the ability to break down the solid into infinitesimally thin slices—disks or washers—whose volumes can be integrated over the axis of revolution.

By understanding the concept of solids of revolution, students can apply similar techniques to find volumes for a variety of shapes, making this an incredibly versatile method in mathematics and engineering alike.
Power Rule for Integration
The power rule for integration is a fundamental rule in calculus used for finding the antiderivative of a power function. The rule states that for any real number \( n \) (except \( -1 \)), the integral of \( x^n \) with respect to \( x \) is \( \frac{x^{n+1}}{n+1} \) plus a constant of integration (in the case of indefinite integrals).

When applying the power rule to the volume of a cone problem, it simplifies the process significantly. Since the cross-sectional area of a disk at height \( x \) is proportional to \( x^2 \) (due to the radius function we've defined), integrating this area along the height of the cone by applying the power rule provides us directly with the formula for the volume of the cone, \( V = \frac{1}{3} \pi r^2h \).

Understanding the power rule empowers students to tackle a wide variety of integration problems with confidence, making it one of the essential tools in a student's calculus toolkit.

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