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Finding Distance Using Two Methods In Exercises 1 and \(2,\) find the distance between the points using (a) the Distance Formula and (b) integration. $$ (1,2), \quad(7,10) $$

Short Answer

Expert verified
The distance between points (1,2) and (7,10) is 10 units.

Step by step solution

01

The Distance formula

The distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) in the plane can be calculated using the distance formula: \(d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\). Apply the formula to the points \((1,2)\) and \((7,10)\) with \(x_1=1, y_1=2, x_2=7,\) and \(y_2=10\). Substitute the values into the formula and compute the distance. The calculation will look like this: \(d=\sqrt{(7-1)^2+(10-2)^2}=\sqrt{(6^2)+(8^2)}=\sqrt{(36+64)}=\sqrt{100}=10\)
02

Integration

The second method involves evaluating the integral of the distance differential. The differential of distance is given by \(\|ds\|=\sqrt{dx^2+dy^2}\). However, our computation will simplify considerably if we choose to navigate the difference only in the x-axis. Hence, we calculate the integral \(\int_{1}^{7} \|dx\|\). The integral over this range will yield a result of \(7-1=6\). Since we know that the points are in a straight line, the distance would be the hypotenuse of the triangle formed by the points. Use the Pythagorean theorem \(a^2 + b^2 = c^2\), where \(a=6\) (horizontal distance) and \(b=8\) (vertical distance), and solve for \(c\), the hypotenuse(distance between the points) to confirm our result \(\sqrt{(6^2+8^2)}=\sqrt{(36+64)}=\sqrt{100}=10\). So by both methods, we arrive at the same answer. Hence the distance between the points \((1,2)\) and \((7,10)\) is 10 units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Distance between two points
In geometry, the distance between two points is a measure of the length of the straight line segment that connects them. To calculate this in a two-dimensional space, we typically use the distance formula, which is derived from the Pythagorean theorem.

For points \( (x_1, y_1) \) and \( (x_2, y_2) \), the distance formula \( d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \) is applied. Here, \( d \) represents the distance between the points. By substituting the coordinates of the given points into the formula and simplifying, we can find the exact distance. This formula works well for points in a coordinate plane and is valuable for a variety of applications, including navigation and computer graphics.
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry that relates the lengths of the sides of a right-angled triangle. It states that the square of the length of the hypotenuse \( c \) is equal to the sum of the squares of the lengths of the other two sides, often labeled \( a \) and \( b \) such that \( a^2 + b^2 = c^2 \).

The distance formula for two points is actually an application of the Pythagorean theorem. When you are plotting the two points on a Cartesian plane, you can imagine a right-angled triangle formed by drawing lines from each point to the same axis. Thus, the horizontal and vertical distances between the points serve as the legs \( a \) and \( b \) of the triangle, and the distance between the points is the hypotenuse \( c \). This theorem not only aids in distance calculation but also in various fields such as construction, astronomy, and navigation.
Integration method for distance
When discussing calculus, the integration method can be used to calculate the distance an object travels along a path. The distance differential \( ds \) can be expressed as \( \sqrt{dx^2+dy^2} \) for a small segment of the path, where \( dx \) and \( dy \) represent infinitesimally small changes in the x and y directions, respectively.

By integrating this differential over the path taken, we can calculate the total distance traveled. When the path is a straight line and we're only interested in horizontal or vertical distances, this simplifies to the absolute value of a single integral over one of the variables. In our problem, the integration method simplifies the problem by only considering the horizontal distance traveled, and the vertical distance can be added using the Pythagorean theorem to find the hypotenuse, which is the total distance between two points.
Differential of distance
In calculus, the concept of a differential helps us understand and compute changes in quantities. The differential of distance, denoted as \( ds \) or \( \|ds\| \), refers to an infinitesimal segment of distance. It's represented mathematically as \( \sqrt{dx^2+dy^2} \), which is akin to the distance formula but for an infinitesimally small piece of a curve.

This concept is particularly useful when calculating the length of a curve or the total distance traveled along a curvy path. To find the total length, we would integrate the differential of distance over the curve's domain. When used in conjunction with integration, this allows for precise calculations over more complex paths than straight lines between two points.

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