Chapter 5: Problem 43
Integration by Substitution In Exercises \(43-46,\) use the specified substitution to find or evaluate the integral. $$ \begin{array}{l}{\int \sqrt{e^{t}-3} d t} \\ {u=\sqrt{e^{t}-3}}\end{array} $$
Short Answer
Step by step solution
Substitution
Derive equation
Substituting \(dt\)
Simplify the New Integral
Evaluate the Integral
Substitute \(u\) back in
Final Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Indefinite Integrals
Indefinite integrals represent the family of all antiderivatives of a function. When we look at the expression \(\int f(x)\, dx\), what we are really searching for is a function F(x) whose derivative equals f(x). The primary reason we call this an \'indefinite integral\' is because the solution is not a single function, but an infinite set of functions that differ by a constant, which we denote as C, known as the constant of integration. Therefore, the general solution to an indefinite integral takes the form F(x) + C, where F(x) is any antiderivative of f(x). The process of finding this function requires a solid comprehension of derivative calculus, as it often involves reversing differentiation operations.
Exponential Functions
Exponential functions are characterized by the presence of an exponent that is a variable. One of the most common bases for exponential functions is the mathematical constant e, approximately equal to 2.71828. The function \(e^x\) has a unique property where its derivative is also \(e^x\), making it a particularly important function in calculus. This property simplifies both differentiation and integration processes involving exponentials. In our integration by substitution exercise, \(e^t\) plays a crucial role and understanding how exponential functions behave is essential to solve the integral successfully.
U-substitution
The method of u-substitution is a technique used to simplify integrals by substituting part of the integral with a new variable (typically u), making the integral easier to evaluate. This is analogous to the common strategy in algebra where we make a substitution to simplify an expression or an equation. In the calculus context, u-substitution often requires us to take the derivative of our substitution to substitute for dt, as shown in the given exercise. Once we simplify the integral in terms of u and find the antiderivative, we must remember to substitute back in terms of the original variable to complete the problem.
Derivative Calculus
Derivative calculus, often simply called differentiation, is a fundamental concept in calculus that measures how a function changes as its input changes. It provides a precise way to analyze the rate of change or the slope of the curve of a function at any point. In the context of our integration exercise, we use derivative calculus to find an expression for dt, which allows us to perform the u-substitution correctly. Seeing as the derivative of \(e^t\) is itself, we use this knowledge to solve for dt and then proceed with the substitution and integration. Derivative calculus is not just about calculating slopes; it's an invaluable tool for solving a variety of problems in mathematics and science.