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Finding an Indefinite Integral In Exercises \(1-20\) , find the indefinite integral. $$ \int \frac{x+5}{\sqrt{9-(x-3)^{2}}} d x $$

Short Answer

Expert verified
The indefinite integral of \(\int \frac{x+5}{\sqrt{9-(x-3)^{2}}} dx\) is \(3\arctan{\frac{x-3}{\sqrt{9-(x-3)^{2}}}} + 2\sqrt{9-(x-3)^{2}} + C\).

Step by step solution

01

Identifying Variables

Notice from the integral that we have \(a = 1\), \(b = 5\), \(c = 3\), and \(d = 3\). By comparing the equation with the standard form we are able to determine the values.
02

Apply the Arctangent Formula

The formula used to solve these types of integrals is \(c(a \arctan {\frac{x-d}{\sqrt{c^{2}-(x-d)^{2}}}} + \frac{b-d}{\sqrt{c^{2}-(x-d)^{2}}}}+ C\). Now plug the values for a, b, c, and d and strictly follow order of operations.
03

Simplify the Result

Solving and simplifying the arctangent equation we obtain \(3\arctan{\frac{x-3}{\sqrt{9-(x-3)^{2}}}} + 2\sqrt{9-(x-3)^{2}} + C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integral Calculus
Integral calculus is a fundamental part of mathematics, primarily concerned with the process of integration, which is the opposite operation of differentiation. It allows us to find quantities like areas, volumes, and accumulations, which are not readily offered by simple geometry or algebra.

When we work with indefinite integrals, as seen in the provided exercise, it's all about finding the antiderivative of a function. The antiderivative is a function whose derivative is the original function. In this case, the function \( \frac{x+5}{\sqrt{9-(x-3)^{2}}} \) is integrated to find its antiderivative. The indefinite integral, represented as \( \int f(x)dx \) without limits, is a general expression of all antiderivatives of the function.

The constant of integration, denoted by 'C', is added at the end because when differentiating, constants disappear, and we must account for all the possible functions that can result in the original function after differentiation.
Arctangent Formula
The arctangent formula is a powerful tool in solving integrals involving trigonometric functions. In the context of the exercise, it is particularly used when dealing with functions that resemble the derivative of the arctangent function, which is \( \frac{1}{1+x^{2}} \).

In integration, the arctangent formula is used when we encounter an expression in the format of \( \frac{1}{\sqrt{a^{2} - x^{2}}} \) where 'a' is a constant. The formula typically takes the form \( \arctan{\frac{x}{\sqrt{a^{2} - x^{2}}} } \) plus a constant of integration.

In our exercise, the presence of the square root in the denominator \( \sqrt{9-(x-3)^{2}} \) signals that the arctangent formula might be necessary to simplify the integral and reach the solution effectively.
Antiderivative
An antiderivative is a function that reverses the process of differentiation, effectively reconstructing the original function from its derivative. It is key to solving indefinite integrals, as each indefinite integral seeks an antiderivative of the given function.

In the case of our exercise, finding the antiderivative involves recognizing the integral structure and accordingly applying the appropriate technique and formulas to integrate the function. Since integration can be more art than science, identifying the correct approach, such as substitution, integration by parts, or using special formulas like the arctangent formula, is crucial.

The result, which includes the constant of integration, represents a family of functions, all of which would yield the same derivative, thus showcasing the 'indefinite' aspect of such integrals.
Order of Operations
The order of operations is a rule that tells us the sequence in which to tackle the different parts of a mathematical expression. In calculus, particularly in integration, respecting this hierarchy is crucial for reaching the correct answer.

The standard order is parentheses or brackets first, exponents (like squares and square roots) second, multiplication and division third, and finally, addition and subtraction. This rule is taught through the acronym PEMDAS or BODMAS in some regions.

When solving the exercise's integral, after applying the arctangent formula, one must simplify the expression carefully by following the order of operations. It ensures all operations within the square roots and arctan function are resolved accurately before finalizing the integration process.

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Most popular questions from this chapter

Chemical Reactions Chemicals \(A\) and \(B\) combine in a 3 -to- 1 ratio to form a compound. The amount of compound \(x\) being produced at any time \(t\) is proportional to the unchanged amounts of \(A\) and \(B\) remaining in the solution. So, when 3 kilograms of \(A\) is mixed with 2 kilograms of \(B\) , you have $$\frac{d x}{d t}=k\left(3-\frac{3 x}{4}\right)\left(2-\frac{x}{4}\right)=\frac{3 k}{16}\left(x^{2}-12 x+32\right)$$ One kilogram of the compound is formed after 10 minutes. Find the amount formed after 20 minutes by solving the equation $$\int \frac{3 k}{16} d t=\int \frac{d x}{x^{2}-12 x+32}$$

Modeling Data A valve on a storage tank is opened for 4 hours to release a chemical in a manufacturing process. The flow rate \(R\) (in liters per hour) at time \(t\) (in hours) is given in the table. $$ \begin{array}{|c|c|c|c|c|c|}\hline t & {0} & {1} & {2} & {3} & {4} \\ \hline R & {425} & {240} & {118} & {71} & {36} \\ \hline\end{array} $$ (a) Use the regression capabilities of a graphing utility to find a linear model for the points \((t, \ln R) .\) Write the resulting equation of the form \(\ln R=a t+b\) in exponential form. (b) Use a graphing utility to plot the data and graph the exponential model. (c) Use the definite integral to approximate the number of liters of chemical released during the 4 hours.

Use a computer algebra system to find the linear approximation \(P_{1}(x)=f(a)+f^{\prime}(a)(x-a)\) and the quadratic approximation \(P_{2}(x)=f(a)+f^{\prime}(a)(x-a)+\frac{1}{2} f^{\prime \prime}(a)(x-a)^{2}\) of the function \(f\) at \(x=a\) . Sketch the graph of the function and its linear and quadratic approximations. \(f(x)=\arctan x, \quad a=0\)

Find any relative extrema of the function. \(f(x)=\arctan x-\arctan (x-4)\)

(a) Use a graphing utility to evaluate arcsin (arcsin 0.5) and \(\arcsin (\arcsin 1) .\) (b) Let \(f(x)=\arcsin (\arcsin x)\) Find the values of \(x\) in the interval \(-1 \leq x \leq 1\) such that \(f(x)\) is a real number.

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