/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Finding the Value of the Derivat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Finding the Value of the Derivative at Relative Extrema In Exercises \(1-6,\) find the value of the derivative (if it exists) at each indicated extremum. $$ f(x)=\cos \frac{\pi x}{2} $$

Short Answer

Expert verified
The value of the derivative at each indicated extremum is 0.

Step by step solution

01

Derive the function

The derivative of \(f(x)=\cos \frac{\pi x}{2}\) can be found using the chain rule. Derivative of \(\cos u\) is \(-\sin u\), and derivative of \(u = \frac{\pi x}{2}\) is \(\frac{\pi}{2}\). Thus, the derivative \(f'(x)\) of the function is \(f'(x) = -\sin\left(\frac{\pi x}{2}\right) \cdot \frac{\pi}{2}\)
02

Determine the points where the derivative is zero

Set \(f'(x)\) equal to zero to find the extrema points. \(-\sin\left(\frac{\pi x}{2}\right) \cdot \frac{\pi}{2} = 0\). For any \(x\), \(\sin(\frac{\pi x}{2})= 0\) when \(x = 2n\) where \(n\) is an integer.
03

Evaluate derivative at these points.

Evaluate \(f'(x)\) at the points \(x =2n\). As the derivative \(f'(x)\) is a continuous function, the value of the derivative at these points is 0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
Understanding the Chain Rule is crucial when dealing with composite functions. A composite function is a function made up of two or more functions, such as having a function nested within another. When you need to take the derivative of such a function, the Chain Rule comes to the rescue.

The Chain Rule states that if you have a composite function, say, \( g(f(x)) \), the derivative of this composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In other words, \( g'(f(x)) \times f'(x) \). This allows you to systematically take derivatives of complex expressions by breaking them down into simpler parts.
Derivative of Cosine
When working with trigonometric functions like cosine, it's important to know how to differentiate them. The derivative of the cosine function is quite straightforward. If you have \(f(x) = \text{cos}(x)\), its derivative is \(f'(x) = -\text{sin}(x)\).

It's a common mistake to forget the negative sign, but it is crucial for correct calculations. The negative sign indicates that the sine function, which represents the rate of change of the cosine function, decreases as the cosine function increases.
Finding Critical Points
Critical points of a function are where its derivative is zero or undefined. These points are essential in studying the function's behavior, as they could indicate potential relative extrema - where the function reaches local maximums or minimums.

To find the critical points, you first derive the function and then solve for where the derivative equals zero. In the context of our exercise, setting \(f'(x) = -\text{sin}(\frac{\text{pi} x}{2}) \times \frac{\text{pi}}{2} = 0\) implies we need to find where the sine function equals zero. For the sine function, this occurs when its argument is an integer multiple of \(\text{pi}\). Hence, we determine that \(x = 2n\), for any integer \(n\), are the critical points of the given function.
Extrema of a Function
Extrema refers to the maximums and minimums of a function. There are two types: absolute (or global) extrema, which are the highest and lowest points on the entire graph of the function, and relative (or local) extrema, which are the highest and lowest points within a specific range of the domain.

Identifying extrema is fundamental in optimization problems and in understanding the overall shape of a graph. To find relative extrema, one normally looks at critical points, as they indicate where the rate of change (slope) of the function is zero. In the exercise provided, after finding the critical points, we determine that the value of the derivative at these points is zero, suggesting potential relative extrema at these locations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describing Terms When using differentials, what is meant by the terms propagated error, relative error, and percent error?

Minimum Distance Sketch the graph of \(f(x)=2-2 \sin x\) on the interval \([0, \pi / 2]\) (a) Find the distance from the origin to the \(y\) -intercept and the distance from the origin to the \(x\) -intercept. (b) Write the distance \(d\) from the origin to a point on the graph of \(f\) as a function of \(x\) . Use your graphing utility to graph \(d\) and find the minimum distance. (c) Use calculus and the zero or root feature of a graphing utility to find the value of \(x\) that minimizes the function \(d\) on the interval \([0, \pi / 2] .\) What is the minimum distance?

Modeling Data The average typing speeds \(S\) (in words per minute) of a typing student after \(t\) weeks of lessons are shown in the table. $$ \begin{array}{|c|c|c|c|c|c|c|}\hline t & {5} & {10} & {15} & {20} & {25} & {30} \\ \hline S & {28} & {56} & {79} & {90} & {93} & {94} \\\ \hline\end{array} $$ A model for the data is \(S=\frac{100 t^{2}}{65+t^{2}}, t>0\) (a) Use a graphing utility to plot the data and graph the model. (b) Does there appear to be a limiting typing speed? Explain.

Approximating Function Values In Exercises \(37-40,\) use differentials to approximate the value of the expression. Compare your answer with that of a calculator. $$ \sqrt{99.4} $$

Comparing Functions In Exercises 83 and \(84,\) (a) use a graphing utility to graph \(f\) and \(g\) in the same viewing window, (b) verify algebraically that \(f\) and \(g\) represent the same function, and (c) zoom out sufficiently far so that the graph appears as a line. What equation does this line appear to have? (Note that the points at which the function is not continuous are not readily seen when you zoom out.) $$ \begin{array}{l}{f(x)=\frac{x^{3}-3 x^{2}+2}{x(x-3)}} \\\ {g(x)=x+\frac{2}{x(x-3)}}\end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.