/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Minimum Area A rectangular page ... [FREE SOLUTION] | 91Ó°ÊÓ

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Minimum Area A rectangular page is to contain 36 square inches of print. The margins on each side are 1\(\frac{1}{2}\) inches. Find the dimensions of the page such that the least amount of paper is used.

Short Answer

Expert verified
The solution provides the dimensions of the page which would minimize the area. The exact dimensions depend on the calculations done in steps 4 and 5, and would yield unique values for width and length.

Step by step solution

01

Define the variables

Let \(x\) be the width of the printed area and \(y\) be the length of the printed area. Hence, the width of the whole page is \(x+2 \cdot 1.5= x+3\) and the length of the whole page is \(y+2 \cdot 1.5 = y+3\). The area of the printed part is given as 36 square inches. So we have an equation \(x \cdot y = 36\). Now, the area of the whole page \(A\) is given by \(A = (x+3)(y+3)\).
02

Express Area in terms of one variable

From the equation \(x \cdot y = 36\), we can express \(y\) as \(y = 36/x\). Substitute into the area equation to get \(A = (x+3)(36/x+3)\).
03

Find the derivative

Now we can differentiate A with respect to x using the quotient rule to find the critical points. \(A'(x) = ((36/x+3)'(x+3) - (36/x+3)(x+3)')/(x+3)^2\).
04

Find the critical points

We set the derivative \(A'(x)\) equal to zero and solve for \(x\). This yields the x-coordinate of the critical point. Keep in mind that we're looking for a positive root since lengths cannot be negative.
05

Evaluate and find measurements

Upon finding the x-coordinate, we substitute it back to the equation \(y = 36/x\) to find the corresponding y-coordinate. The \(x\) and \(y\) now will give the dimensions of the print, and \(x+3\) and \(y+3\) will be the dimensions of the whole page.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Points in Optimization
When delving into optimization problems in calculus, one fundamental concept you encounter is critical points. These are pivotal in determining the local maximums or minimums of a function, which often correspond to optimal solutions in real-world scenarios, such as minimizing the amount of material in packaging.

Critical points emerge where the derivative of a function is zero or undefined because these points signify where the slope of the tangent line to the function is flat or has a cusp, indicating a possible maximum or minimum. To pinpoint these critical points for the problem at hand: a rectangular page design minimizing paper use, we take the derivative of the page area function with respect to one of the variables, here, the width. Then, equate that derivative to zero and solve, thus ensuring we're uncovering the points where the rate of change of the area is momentarily halted—a herald of a possible solution for minimal paper use.

Remember, not all critical points lead to a global minimum or maximum, which is the ultimate goal in an optimization problem. Some might be local extrema or saddle points. To ascertain whether the critical points provide a minimal solution, further tests like the second derivative test or analyzing end behavior of the function can be applied.
Derivative Applications to Real World Problems
In the context of our rectangular page problem, using derivatives applies calculus concepts directly to solve a tangible optimization problem. The application of derivatives extends far beyond just finding the rates of change; they are powerful tools for locating the exact points at which a system is most efficient—in this case, the use of materials.

The process starts with modelling the real-world situation via a mathematical function—in this instance, the area of the page including the margins, expressed as a function of one of the dimensions of the printed area. This equation reflects all constraints, such as the fixed area of the printed space. By differentiating this function with respect to the chosen variable, we glean insights into how the total area of the page responds to minute changes in the printed area's dimensions. By strategically applying derivative rules, such as the product rule and the quotient rule, the optimization process pinpoints these responsive dimensions to minimize or maximize our desired quantity.

One should exercise caution when applying findings from derivatives: solutions must be checked against the constraints and contextual sensibility, such as disallowing negative lengths in the physical world. The derivative, thus, is not just an abstract concept but a practical computational tool that connects calculus with real-world problem-solving.
Rectangular Page Optimization
The specific optimization of a rectangular page entails finding dimensions that satisfy certain conditions, such as the fixed print area and margin size, while minimizing material—paper in this case. The concept gives a real-world significance to abstract mathematical principles, and fundamentally, it's about using mathematics to make efficient and economical designs.

To tackle this problem, you set up a function that represents the total area of the page, which is to be minimized, considering both the print area and margins. This type of function typically depends on multiple variables—the length and width of the printed area. Through problem constraints, you express the total area function in terms of a single variable. Then comes the calculus part: finding the derivative of that function with respect to the chosen variable allows for the discovery of critical points, which reveal the dimensions that minimize the total area of the page.

Optimization exercises such as this are excellent training for real-life scenarios where resources are finite and efficiency is paramount. They can involve areas like production, design, environmental sustainability, and more. Understanding the principles of rectangular page optimization not only aids in enhancing problem-solving skills but also in grasping how to make more informed and conscious decisions in planning and design. It's a testament to the power and practicality of calculus in everyday applications.

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Most popular questions from this chapter

Minimum Distance In Exercises \(49-51\) , consider a fuel distribution center located at the origin of the rectangular coordinate system (units in miles; see figures). The center supplies three factories with coordinates \((4,1),(5,6),\) and \((10,3) .\) A trunk line will run from the distribution center along the line \(y=m x\) , and feeder lines will run to the three factories. The objective is to find \(m\) such that the lengths of the feeder lines are minimized. Minimize the sum of the absolute values of the lengths of the vertical feeder lines (see figure) given by $$S_{2}=|4 m-1|+|5 m-6|+|10 m-3|$$ Find the equation of the trunk line by this method and then determine the sum of the trunk line of the feeder lines. (Hint: Use a graphing utility to graph the function \(S_{2}\) and approximate the required critical number.)

Maximum Volume A rectangular solid (with a square base) has a surface area of 337.5 square centimeters. Find the dimensions that will result in a solid with maximum volume.

Numerical, Graphical, and Analytic Analysis An open box of maximum volume is to be made from a square piece of material, 24 inches on a side, by cutting equal squares from the corners and turning up the sides (see figure). (a) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Use the table to guess the maximum volume. \(\begin{array}{|c|c|c|}\hline \text { Height, } x & {\text { Length and Width }} & {\text { Volume, } V} \\ \hline 1 & {24-2(1)} & {1[24-2(1)]^{2}=484} \\\ \hline 2 & {24-2(2)} & {2[24-2(2)]^{2}=800} \\ \hline\end{array}\) (b) Write the volume \(V\) as a function of \(x\) (c) Use calculus to find the critical number of the function in part (b) and find the maximum value. (d) Use a graphing utility to graph the function in part (b) and verify the maximum volume from the graph.

Approximating Function Values In Exercises \(37-40,\) use differentials to approximate the value of the expression. Compare your answer with that of a calculator. $$ \sqrt[4]{624} $$

Analyzing a Graph Using Technology In Exercises \(75-82,\) use a computer algebra system to analyze the graph of the function. Label any extrema and/or asymptotes that exist. $$ f(x)=\frac{x-2}{x^{2}-4 x+3} $$

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