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Determine whether Rolle's Theorem can be applied to \(f\) on the closed interval \([a, b] .\) If Rolle's Theorem can be applied, find all values of \(c\) in the open interval \((a, b)\) such that \(f^{\prime}(c)=0 .\) If Rolle's Theorem cannot be applied, explain why not. \(f(x)=(x-1)(x-2)(x-3), \quad[1,3]\)

Short Answer

Expert verified
Yes, Rolle's Theorem can be applied as all conditions of the theorem are satisfied. The value of \(c\) for which \(f'(c) = 0\) on the interval (1,3) is \(c = 1 + \sqrt{3/3}\).

Step by step solution

01

Verify the conditions for Rolle's Theorem

Check if the given function \(f(x) = (x - 1)(x - 2)(x - 3)\) is continuous on the closed interval [1,3] and differentiable on the open interval (1,3). It's a polynomial function, so it is both continuous and differentiable for all real numbers. Then, check if \(f(1) = f(3)\). Calculating, \(f(1) = (1 - 1)(1 - 2)(1 - 3) = 0\) and \(f(3) = (3 - 1)(3 - 2)(3 - 3) = 0\). So, \(f(1) = f(3)\). Thus, all conditions for Rolle's Theorem are satisfied here.
02

Find the derivative of the function

Using the product rule, the derivative of the function is: \(f'(x) = (x-2)(x-3) + (x-1)(x-3) + (x-1)(x-2) = 3x^2 - 12x + 11 \).
03

Solve the equation \(f'(c) = 0\)

According to Rolle's Theorem, there exists at least one \(c\) in the interval (1,3) such that \(f'(c) = 0\). So, we set \(f'(c) = 0\), which implies \(3c^2 - 12c + 11 = 0\). Solving this quadratic equation yields two roots \(c = 1 + \sqrt{3/3}\) and \(c = 1 - \sqrt{3/3}\), with only \(c = 1 + \sqrt{3/3}\) lying in the open interval (1,3). So, there is one such \(c\) that satisfies Rolle's Theorem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuous Function
A continuous function is one that can be drawn without lifting your pencil from the paper. This means there are no breaks, holes, or jumps in the graph. In mathematical terms, a function \( f(x) \) is continuous on an interval \([a, b]\) if it is continuous at every point in that interval.

Polynomials, like \(f(x) = (x-1)(x-2)(x-3)\), are continuous everywhere because they have no discontinuities. This makes polynomial functions straightforward to work with when checking conditions for theorems like Rolle's.

For Rolle's Theorem, checking that our function is continuous on a closed interval \([1, 3]\) establishes the first requirement. Continuous functions ensure smoothness, vital for transitioning into differentiability.
Differentiable Function
Differentiability relates to the smoothness of a function's graph. If a function is differentiable at a point, it means it has a well-defined tangent at that point. In simpler terms, you can calculate the slope of the curve precisely.

For polynomial functions, like the one in our exercise, differentiability is guaranteed everywhere. This is because polynomial functions don't have sharp corners or vertical tangents.

Rolle's Theorem requires the function to be differentiable on the open interval \((1, 3)\). Since our function is differentiable everywhere, this condition is easily met. Differentiability ensures we can apply calculus tools like derivatives, which are needed in finding where the slope of the function equals zero.
Polynomial Function
Polynomial functions are algebraic expressions that involve sums of powers of variables with coefficients. In general, a polynomial function can be written as \(f(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_0\). Here, \(a_n, a_{n-1}, ..., a_0\) are coefficients, and \(n\) is a non-negative integer representing the degree of the polynomial.

The function given in our exercise, \(f(x) = (x-1)(x-2)(x-3)\), is a cubic polynomial. Cubic polynomials have one or more bends in their graphs.

Polynomial functions are not only continuous and differentiable but also easy to handle computationally. This makes them ideal candidates for applying theorems like Rolle's. They allow us to explore solutions and roots simply and effectively.
Quadratic Equation
A quadratic equation is a second-degree polynomial equation of the form \(ax^2 + bx + c = 0\). The solutions to this equation are called the roots and can be found using various methods, such as factoring, completing the square, or the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

In our solution, we derived a quadratic equation from the derivative: \(3c^2 - 12c + 11 = 0\). Solving this equation gives us the critical points where the derivative is zero. These points are where the function's slope changes direction, an essential aspect of understanding the behavior of the function on the interval.

Solving the quadratic equation can sometimes tell us about the unique or multiple points satisfying certain conditions, like in Rolle's Theorem, where the slope of the tangent is zero within a certain range.

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Most popular questions from this chapter

Comparing Functions In Exercises 83 and \(84,\) (a) use a graphing utility to graph \(f\) and \(g\) in the same viewing window, (b) verify algebraically that \(f\) and \(g\) represent the same function, and (c) zoom out sufficiently far so that the graph appears as a line. What equation does this line appear to have? (Note that the points at which the function is not continuous are not readily seen when you zoom out.) $$ \begin{array}{l}{f(x)=\frac{x^{3}-3 x^{2}+2}{x(x-3)}} \\\ {g(x)=x+\frac{2}{x(x-3)}}\end{array} $$

Numerical, Graphical, and Analytic Analysis An exercise room consists of a rectangle with a semicircle on each end. A 200 -meter running track runs around the outside of the room. (a) Draw a figure to represent the problem. Let \(x\) and \(y\) represent the length and width of the rectangle. (b) Analytically complete six rows of a table such as the one below. (The first two rows are shown.) Use the table to guess the maximum area of the rectangular region. $$ \begin{array}{|c|c|c|}\hline \text { Length, } x & {\text { Width, } y} & {\text { Area, } x y} \\ \hline 10 & {\frac{2}{\pi}(100-10)} & {(10) \frac{2}{\pi}(100-10) \approx 573} \\ \hline 20 & {\frac{2}{\pi}(100-20)} & {(20) \frac{2}{\pi}(100-20) \approx 1019} \\ \hline\end{array} $$ (c) Write the area \(A\) as a function of \(x\) . (d) Use calculus to find the critical number of the function in part (c) and find the maximum value. (e) Use a graphing utility to graph the function in part (c) and verify the maximum area from the graph.

Sketching a Graph In Exercises \(59-74\) , sketch the graph of the equation using extrema, intercepts, symmetry, and asymptotes. Then use a graphing utility to verify your result. $$ y=\frac{x}{\sqrt{x^{2}-4}} $$

Proof In Exercises \(95-98\) , use the definition of limits at infinity to prove the limit. $$ \lim _{x \rightarrow-\infty} \frac{1}{x-2}=0 $$

Find, with explanation, the maximum value of \(f(x)=x^{3}-3 x\) on the set of all real numbers \(x\) satisfying \(x^{4}+36 \leq 13 x^{2}\)

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