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Linear Approximation Use a graphing utility with a square window setting to zoom in on the graph of $$f(x)=4 \sqrt{x}+1$$ to approximate \(f^{\prime}(4) .\) Use the derivative to find \(f^{\prime}(4)\)

Short Answer

Expert verified
The derivative of the function \(f(x)\) at x=4, denoted as \(f^{\prime}(4)\), is 1.

Step by step solution

01

Graphing the Function

Firstly, use a graphing utility to plot the function \(f(x)=4 \sqrt{x}+1\). Now, zoom in on the graph around x=4 to visually estimate the slope of the function at this point.
02

Computing the Derivative

Next step is to find the derivative of the function analytically. Differentiating \(f(x)=4 \sqrt{x}+1\) with respect to x gives \(f^{\prime}(x)=2/\sqrt{x}\).
03

Evaluating the Derivative

Finally, substitute x=4 into the derivative computed in the previous step to find \(f^{\prime}(4)\). This results in \(f^{\prime}(4)=2/\sqrt{4}=1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Utility
Graphing utilities are powerful tools in mathematics, enabling students to visually explore complex functions and their characteristics. For the exercise involving the function f(x) = 4 \(\sqrt{x}\) + 1, a graphing utility can be particularly useful. By plotting the graph and using a square window setting, students can closely observe how the function behaves around a point of interest—in this case, x = 4.

When zooming in on the graph at this point, the utility provides a visual representation of the function's slope, or rate of change, at that specific value of x. This hands-on approach is a fundamental step for those beginning to understand the concept of derivatives, as it can help bridge the gap between abstract numerical derivatives and their tangible graphical representations.
Derivative
The derivative of a function at a point is a fundamental concept in calculus representing the slope of the tangent line at that point or the instantaneous rate of change of the function. Mathematically, we denote the derivative of f with respect to x as f'(x). In the exercise, determining the derivative of f(x) = 4 \(\sqrt{x}\) + 1 involves applying rules of differentiation to find an expression that can provide the slope at any point along the curve.

Understanding how to obtain this derivative analytically is essential, as it allows for precise calculations and a deeper comprehension of the function's behavior. As students progress in calculus, mastering derivatives becomes fundamental for solving a vast array of problems in both pure and applied mathematics.
Slope Estimation
Slope estimation is a technique to approximate the slope of a function's graph at a particular point when an exact analytic solution is not immediately available, or to gain a quick sense of the behavior of the function. In a graphical sense, slope estimation involves drawing a tangent line at the point of interest and estimating the 'rise over run' based on the graph itself.

The ability to estimate the slope visually from the graphing utility aids in comprehending the rate of change. While this method isn't as precise as analytical differentiation, it offers a quick and intuitive understanding which is critical when students are first introduced to the concept of derivatives or when they lack the means to compute it analytically.
Analytical Differentiation
Analytical differentiation is the process of finding the derivative of a function using the principles and rules of calculus, such as the power rule, product rule, chain rule, and others. It contrasts with numerical or graphical methods by providing an exact value for the derivative at any point. In our exercise, we apply analytical differentiation to the function f(x) = 4 \(\sqrt{x}\) + 1 to find its derivative, resulting in f'(x) = 2/\sqrt{x}.

With the derivative in hand, we can calculate the slope of the function at x = 4, giving us an exact value of f'(4) = 1. This method is crucial in various fields, from physics to economics, where precise calculations are necessary for understanding phenomena or making informed decisions.

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Most popular questions from this chapter

Finding a Higher-Order Derivative In Exercises \(99-102\) find the given higher- order derivative. $$ f^{\prime}(x)=x^{2}, \quad f^{\prime \prime}(x) $$

Roadway Design Cars on a certain roadway travel on a circular arc of radius \(r .\) In order not to rely on friction alone to overcome the centrifugal force, the road is banked at an angle of magnitude \(\theta\) from the horizontal (see figure). The banking angle must satisfy the equation \(r g \tan \theta=v^{2},\) where \(v\) is the velocity of the cars and \(g=32\) feet per second per second is the acceleration due to gravity. Find the relationship between the related rates \(d v / d t\) and \(d \theta / d t\) .

Sketching a Graph Sketch the graph of a differentiable function \(f\) such that \(f>0\) and \(f^{\prime}<0\) for all real numbers \(x\) . Explain how you found your answer.

A trough is 12 feet long and 3 feet across the top (see figure). Its ends are isosceles triangles with altitudes of 3 feet. (a) Water is being pumped into the trough at 2 cubic feet per minute. How fast is the water level rising when the depth \(h\) is 1 foot? (b) The water is rising at a rate of \(\frac{3}{8}\) inch per minute when \(h=2 .\) Determine the rate at which water is being pumped into the trough.

Moving Point In Exercises \(5-8,\) a point is moving along the graph of the given function at the rate \(d x / d t .\) Find \(d y / d t\) for the given values of \(x .\) $$ \begin{array}{l}{y=\tan x ; \frac{d x}{d t}=3 \text { feet per second }} \\\ {\begin{array}{llll}{\text { (a) } x=-\frac{\pi}{3}} & {\text { (b) } x=-\frac{\pi}{4}} & {\text { (c) } x=0}\end{array}}\end{array} $$

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