Chapter 2: Problem 66
Using the Alternative Form of the Derivative In Exercises \(65-74,\) use the alternative form of the derivative to find the derivative at \(x=c\) (if it exists). $$ g(x)=x^{2}-x, \quad c=1 $$
Short Answer
Expert verified
The derivative of the function \(g(x) = x^{2}-x\) at \(x = 1\) is \(1\).
Step by step solution
01
Identify the function and the point c
In this case, the function \(g(x) = x^{2}-x\). The point \(c\) given is 1.
02
Substitute into formula
Substitute \(x^{2}-x\) as \(f(x)\) and 1 as \(c\) into the alternative form of the derivative formula \( f'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} \). This yields: \[ f'(1) = \lim_{x \to 1} \frac{(x^{2}-x) - (1^{2}-1)}{x - 1} \]
03
Simplify
Simplify the above expression to get: \[ f'(1) = \lim_{x \to 1} \frac{x^{2}-x}{x - 1} - 0 \]. Further Simplify to get: \[ f'(1) = \lim_{x \to 1} \frac{x(x-1)}{x - 1} \]. Considering the fact \[(x - 1)\] in both numerator and denominator cancel each other out if \(x≠1\). We get: \[ f'(1) = \lim_{x \to 1} x \]
04
Compute the limit
Now we need to compute the limit. The limit of \(x\) as \(x\) approaches 1 is 1. Hence, we have \(f'(1) = 1\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Alternative Form of the Derivative
The alternative form of the derivative is a powerful tool for finding the derivative of a function at a specific point. Instead of using the standard definition, which focuses on a general point, the alternative form is more convenient for calculating derivatives at an exact value of \(x=c\). This method allows us to pinpoint the slope of the tangent line to the curve at that particular point, thus providing a deeper understanding of how the function behaves there.
- The formula to use is \( f'(c) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c} \).
- Here, \(f'(c)\) represents the derivative of \(f(x)\) at \(x=c\).
Limit Process
The limit process is central to understanding derivatives, and it plays a crucial role in the alternative form of the derivative. The concept of a limit is concerned with finding the value that a function approaches as input gets arbitrarily close to some point.
- In our exercise, we computed \( \lim_{x \to 1} \frac{(x^{2}-x) - (1^{2}-1)}{x - 1} \).
- This expression calculates the instantaneous rate of change at \(x=1\), examining what happens to the value of the function and its corresponding slope as \(x\) nears 1.
Simplification
Simplification is a fundamental part of solving calculus problems involving derivatives. Once the derivative's expression is formed based on the limit definition, simplifying the expression helps make the limit computation straightforward.
- From \( \frac{(x^{2}-x)}{x - 1} \), we recognized \((x-1)\) as a common factor, which allowed us to simplify the expression by cancelling it with the denominator, provided \(x eq 1\).
- This simplifies to \( \lim_{x \to 1} x \).
Calculus Problem Solving
Problem-solving in calculus hinges on a mix of determination, methodological understanding, and logical thinking. The journey from recognizing a function's point of interest to finding its derivative involves several strategic steps:
- First, accurately identify the function and the specific point \(c\).
- Second, substituting the function into the appropriate formula, such as the alternative form for finding the derivative.
- Third, simplify where possible to make the mathematical work more manageable.
- Finally, solve the problem by computing any limits and finalizing the derivative's value.