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In Exercises 53–56, find a set of parametric equations for the rectangular equation that satisfies the given condition. $$ y=4 x+1, t=-1 \text { at the point }(-2,-7) $$

Short Answer

Expert verified
The parametric equations for the line are \(x = t - 1\) and \(y = 4t - 3\).

Step by step solution

01

Write the parametric equations

Broadly, any line can be parameterized, but for a line given by \(y = mx + c\), a common parameterization exists. This involves treating x as the parameter t, resulting in: \(x = t\) and \(y = mt + c\).
02

Substitute the slope and Y-intercept from the given equation

Substitute \(m = 4\) and \(c = 1\) into these general forms: \(x = t\) and \(y = 4t + 1\)
03

Adjust the t-values

At this point, we have a valid set of parametric equations, however they do not satisfy the condition that t = -1 at point (-2, -7). To ensure the condition holds, we can adjust the parametric equations for x and y by adding a time shift. Given that when t = -1, x = -2 and y = -7, we adjust the t-values by subtracting 1, in order to shift the t = -1 to t = 0: \(x = t - 1\) and \(y = 4(t - 1) + 1\)
04

Simplify the equations

Simplify these equations to get the final parametric equations: \(x = t - 1\) and \(y = 4t - 4 + 1 = 4t - 3\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus, a foundational element of modern mathematics, involves the study of rates of change and accumulated quantities. In the context of parametric equations, calculus provides tools for analyzing curves in the plane in terms of a parameter, usually denoted as 't'. This allows for a comprehensive understanding of motion and change over time, as parametric equations often describe the path of an object through space.

Through differentiation and integration, calculus unveils information about the velocity, acceleration, length, and area under the curve of parametrically defined functions. For example, to find the slope at any point on a curve described by parametric equations, we can differentiate the parametric equations with respect to 't' and then take the derivative of y with respect to x.
Rectangular to Parametric Form
Converting an equation from rectangular to parametric form is essentially re-expressing a relationship between x and y into a pair of relationships between each of x and y with a third variable, typically 't'. This process is incredibly useful for simplifying the representation of curves that are otherwise complicated to describe in the traditional y=f(x) format.

The most straightforward method, as seen in the provided exercise, involves setting x equal to 't' or another function of 't', and then expressing y in terms of the same parameter. This enables the construction of a more dynamic view, useful for animations, graphics, and solving problems related to motion and time.
Slope and Intercept
The slope and intercept are integral parts of the equation of a line in the rectangular (traditional algebraic) form y = mx + b, where 'm' is the slope and 'b' is the y-intercept. The slope defines the steepness and direction of the line, while the y-intercept signifies the point where the line crosses the y-axis.

When translating this into parametric equations, the slope informs how y changes with respect to x (or 't' in our case), and the intercept informs the starting point or offset of the line. In the context of parameterization, the slope becomes the coefficient of 't' when expressing 'y' as a function of the parameter 't'.
Line Parameterization
Line parameterization is the process of representing a line with parametric equations using a parameter 't'. This parameter often corresponds to time in practical applications, allowing the position on the line to be expressed as a function of time.

To parameterize a line given by the slope-intercept form, one typically sets 'x' equal to 't' plus any necessary horizontal shift, and 'y' is set as 'mt' plus any necessary vertical shift and the intercept. If a specific point on the line corresponds to a particular 't' value, as in the exercise provided, the parameterization must be adjusted so that substituting this 't' value yields the coordinates of that point.

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Most popular questions from this chapter

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