Chapter 10: Problem 26
Identifying a Conic In Exercises \(23-26,\) use a graphing utility to graph the polar equation. Identify the graph and find its eccentricity. $$ r=\frac{6}{6+7 \cos \theta} $$
Short Answer
Expert verified
The given polar equation represents a hyperbola with an eccentricity of 7.
Step by step solution
01
Match to Standard Form
First, it is needed to match the given polar equation \(r = \frac{6}{6 + 7 \cos \theta}\) to the standard form of a conic section \(r = \frac{ed}{1 \pm e \cos \theta}\). Note that the standard form is obtained from the given equation by subtracting \(1\) from the denominator to get \(r = \frac{6}{(6 -1) + 7 \cos \theta}= \frac{6}{5 + 7 \cos \theta}\)
02
Identify the parameters
Based on the matched form \(r = \frac{6}{5 + 7 \cos \theta}\), we can see that it matches to the form \(r = \frac{ed}{1 - e \cos \theta}\), so the conic has a horizontal directrix (the cosine form). So, the directrix \(d = 6\) and the eccentricity \(e = 7\).
03
Identify the conic section
Since the value of eccentricity \(e = 7 > 1\), we have a hyperbola. The value of \(e\) determines the type of conic section: For \(e = 1\), it would have been a parabola; for \(0 < e < 1\), it would have been an ellipse; for \(e > 1\), it's a hyperbola. So, we identify our conic section as a hyperbola.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eccentricity of Conic Sections
Eccentricity is a key concept when it comes to understanding conic sections. It's a number that describes how much a conic section deviates from being a perfect circle. The eccentricity, denoted by the symbol \(e\), helps us classify the shape of the conic section. To recall, the value of \(e\) for a circle is 0, which means the circle is perfectly round.
For ellipses, which are elongated circles, the eccentricity has a value between 0 and 1 (\(0 < e < 1\)). The closer the eccentricity is to 0, the more circle-like the ellipse appears. As the value approaches 1, the ellipse becomes more stretched out.
For parabolas, the eccentricity is exactly 1 (\(e = 1\)). This gives us the classic U-shaped curve. Both branches of the parabola extend infinitely outwards, never quite closing.
If we have a hyperbola, the eccentricity is greater than 1 (\(e > 1\)). This denotes a conic section that consists of two separate curves, or branches, that open outward and never meet.
In our exercise, where we have the polar equation \(r = \frac{6}{6 + 7 \cos \theta}\), the step-by-step solution reveals an eccentricity of 7, which means we are dealing with a hyperbola.
For ellipses, which are elongated circles, the eccentricity has a value between 0 and 1 (\(0 < e < 1\)). The closer the eccentricity is to 0, the more circle-like the ellipse appears. As the value approaches 1, the ellipse becomes more stretched out.
For parabolas, the eccentricity is exactly 1 (\(e = 1\)). This gives us the classic U-shaped curve. Both branches of the parabola extend infinitely outwards, never quite closing.
If we have a hyperbola, the eccentricity is greater than 1 (\(e > 1\)). This denotes a conic section that consists of two separate curves, or branches, that open outward and never meet.
In our exercise, where we have the polar equation \(r = \frac{6}{6 + 7 \cos \theta}\), the step-by-step solution reveals an eccentricity of 7, which means we are dealing with a hyperbola.
Graphing Polar Equations
Graphing polar equations is a bit different from graphing in the Cartesian coordinate system. The polar coordinate system allows us to represent curves using a radius \(r\) and an angle \(\theta\). The basic strategy involves plotting points for various angles and connecting these points to reveal the shape of the curve.
To graph a polar equation like the one given in our exercise, \(r = \frac{6}{6 + 7 \cos \theta}\), one would typically:
To graph a polar equation like the one given in our exercise, \(r = \frac{6}{6 + 7 \cos \theta}\), one would typically:
- Identify several values of \(\theta\) throughout the 0 to \(2\pi\) range.
- Compute the corresponding \(r\) values for each \(\theta\).
- Plot these \(\theta\), \(r\) pairs on polar graph paper, where the angle \(\theta\) is measured from the positive x-axis and \(r\) is the distance from the origin.
- Connect the points smoothly to outline the conic section.
Identifying Conic Sections
Identifying the type of conic section represented by a polar equation requires understanding how the polar equation relates to the conic's eccentricity and directrix. As we observe in our exercise, we are given the equation \(r = \frac{6}{6 + 7 \cos \theta}\), which can be matched to the standard form of a conic section of \(r = \frac{ed}{1 \pm e \cos \theta}\).
From the standard form, we can extract the values for eccentricity \(e\) and the directrix \(d\). Depending on the eccentricity:
From the standard form, we can extract the values for eccentricity \(e\) and the directrix \(d\). Depending on the eccentricity:
- If \(e = 1\), the conic section is a parabola.
- If \(0 < e < 1\), the conic section is an ellipse.
- If \(e > 1\), the conic section is a hyperbola.