Chapter 1: Problem 103
Free-Falling Object In Exercises 103 and 104 , use the position function \(s(t)=-4.9 t^{2}+200\) , which gives the height (in meters) of an object that has fallen for \(t\) seconds from a height of 200 meters. The velocity at time \(t=a\) seconds is given by \(\lim _{t \rightarrow a} \frac{s(a)-s(t)}{a-t}\) Find the velocity of the object when \(t=3\)
Short Answer
Step by step solution
Identify the functions and variables
Substitute the values into the formula for velocity
Find the limit
Calculate the velocity
Interpret the result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Velocity Calculation
Position Function
- The coefficient of \(t^2\) is related to the gravitational force.
- The constant term indicates the starting height.
Limit of a Function
- This tells us exactly what the velocity is at that moment.
- Limits allow us to define instantaneous behavior precisely.
Derivative
- The negative sign indicates direction (downward).
- The resulting expression provides velocity at any given time \(t\).