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Writing Functions In Exercises \(83-86,\) write an equation for a function that has the given graph. Line segment connecting \((3,1)\) and \((5,8)\)

Short Answer

Expert verified
The equation of the line segment connecting the points (3,1) and (5,8) is \(y = 3.5x - 9.5\)

Step by step solution

01

Determine the Slope

First, we're going to calculate the slope (m) of the line connecting the points (3,1) and (5,8). The formula to compute the slope is \(m = \frac{{y2 - y1}}{{x2 - x1}}\). Substituting the given points into this formula results in \( m = \frac{{8 - 1}}{{5 - 3}} = \frac{7}{2} = 3.5\) .
02

Write the Equation of the Line in Point-Slope Form

Using the point (3,1) and the calculated slope, the equation of the line can be written in point-slope form as \(y - y1 = m(x - x1)\), where \(m = 3.5\) (the slope) and \(x1 = 3, y1 = 1\) (the point). Substituting these values into the equation gives \(y - 1 = 3.5(x - 3)\).
03

Simplify the Equation

The above equation simplifies down to standard form after distributing \(3.5\) to \(x-3\), then isolating \(y\) on one side. So the equation \(y - 1 = 3.5x - 10.5\) simplifies down to \(y = 3.5x - 9.5\). This is the equation of the line connecting the points (3,1) and (5,8).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Calculation
When it comes to understanding linear equations, calculating the slope of a line is one of the fundamental concepts you need to grasp. The slope indicates how steep a line is and the direction it is heading on a graph. The standard formula for finding the slope when you're given two points is:
\begin{displaymath}m = \frac{{y_2 - y_1}}{{x_2 - x_1}}d\right.when dealing with simplifying the calculation.
In our exercise, the two points are \(3,1\) and \(5,8\). By substituting these points into our formula, we calculated the slope \(m\) as follows:
m = \frac{{8 - 1}}{{5 - 3}} = \frac{7}{2} = 3.5
A positive slope like 3.5 means our line is rising from left to right across the graph. The higher the number, the steeper the ascent; in this case, for every step we take to the right (increasing x), we go up 3.5 steps (increasing y).
Point-Slope Form
Once the slope is determined, the next step is to express the linear equation using the point-slope form, which is especially handy when you're given a slope and a single point on the line. The point-slope form of the equation of a line is given byy - y1 = m(x - x1)
where \(m\) is the slope and \(x1, y1\) is the known point on the line. In our example, with \(m = 3.5\) and the point being (3,1), our equation becomes:
y - 1 = 3.5(x - 3)
This equation is powerful because it directly incorporates both essential characteristics of a line - a point through which it passes, and its slope. It shows how the y-value on the line changes with x relative to a known point (3,1) on the line.
Linear Function
Conclusively, what we've been determining and manipulating is the equation of a linear function. A linear function is one where the relationship between x and y can be represented on a coordinate graph as a straight line. The equation we derived for the line through the points \(3,1\) and \(5,8\), which is \(y = 3.5x - 9.5\), is in its simplest form and is a perfect example of a linear function.
It's straightforward to recognize because its equation is often written in the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept, the point where the line crosses the y-axis. In this format, it's easy to plot the line on a graph and to understand how the value of y depends on the value of x.
Understanding a linear function's slope and y-intercept helps with graphing the line and also interpreting the rate at which something changes, making it a powerful concept in both mathematics and real-world applications.

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Most popular questions from this chapter

Beam Strength Students in a lab measured the breaking strength \(S\) (in pounds) of wood 2 inches thick, \(x\) inches high, and 12 inches long. The results are shown in the table. $$ \begin{array}{|c|c|c|c|c|c|}\hline x & {4} & {6} & {8} & {10} & {12} \\\ \hline s & {2370} & {5460} & {10,310} & {16,250} & {23,860} \\\ \hline\end{array} $$ (a) Use the regression capabilities of a graphing utility to find a quadratic model for the data. (b) Use a graphing utility to plot the data and graph the model. (c) Use the model to approximate the breaking strength when \(x=2\) . (d) How many times greater is the breaking strength for a 4 -inch-high board than for a 2 -inch-high board? (e) How many times greater is the breaking strength for a 12 -inch-high board than for a 6 -inch-high board? When the height of a board increases by a factor, does the breaking strength increase by the same factor? Explain.

Distance In Exercises \(83-86\) , find the distance between the point and line, or between the lines, using the formula for the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+\) \(C=0 .\) $$ =\frac{\left|A x_{1}+B y_{1}+C\right|}{\sqrt{A^{2}+B^{2}}} $$ Point: \((-2,1)\) Line: \(x-y-2=0\)

Falling Object In an experiment, students measured the speed \(s\) (in meters per second) of a falling object \(t\) seconds after it was released. The results are shown in the table. $$ \begin{array}{|c|c|c|c|c|c|}\hline t & {0} & {1} & {2} & {3} & {4} \\ \hline s & {0} & {11.0} & {19.4} & {29.2} & {39.4} \\ \hline\end{array} $$ (a) Use the regression capabilities of a graphing utility to find a linear model for the data. (b) Use a graphing utility to plot the data and graph the model. How well does the model fit the data? Explain. (c) Use the model to estimate the speed of the object after 2.5 seconds.

Distance Show that the distance between the point \(\left(x_{1}, y_{1}\right)\) and the line \(A x+B y+C=0\) is Distance \(=\frac{\left|A x_{1}+B y_{1}+C\right|}{\sqrt{A^{2}+B^{2}}}\)

The horsepower \(H\) required to overcome wind drag on a certain automobile is approximated by $$H(x)=0.002 x^{2}+0.005 x-0.029, \quad 10 \leq x \leq 100$$ where \(x\) is the speed of the car in miles per hour. (a) Use a graphing utility to graph \(H\) (b) Rewrite the power function so that \(x\) represents the speed in kilometers per hour. [Find \(H(x / 1.6) . ]\)

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