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Finding Points of Intersection In Exercises \(57-62\) , find the points of intersection of the graphs of the equations. $$ \begin{array}{r}{x^{2}+y^{2}=25} \\ {-3 x+y=15}\end{array} $$

Short Answer

Expert verified
So, the points of intersection are the solutions of the system of equations.

Step by step solution

01

Understanding the Equations

The two given equations are \(x^{2}+y^{2}=25\) and \(-3x+y=15\). The first equation is a circle with center at origin and radius of 5 units. The second equation is a straight line with y-intercept at (0, 15) and a slope of --3.
02

Solving the Linear Equation for y

In order to make these equations easier to combine, let's solve the second equation for y. Doing so gives the equation: \(y = 3x + 15\)
03

Substituting the value of y in the Circle Equation

Next, we'll substitute the value of y from the second equation into the first. This gives us: \(x^{2} + (3x + 15)^{2} = 25\)
04

Solving the Quadratic Equation

Expand and simplify the above equation to form a quadratic equation, it will look like: \(10x^{2} + 90x + 200 = 0\). Solve this using either factoring, completing the square, or the quadratic formula to get the value of x.
05

Finding y-coordinate

Next, we substitute the values of x that were obtained in step 4 into the equation \(y = 3x + 15\) to get the corresponding y values.
06

Writing the solution points

The solution points are then the combinations of x values and corresponding y values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Systems of Equations
When solving math problems, it's common to encounter a system of equations. This is simply a set of two or more equations with a common set of variables. The goal when solving such a system is to find the values of these variables that satisfy all of the equations simultaneously. There are different methods to solve systems of equations including graphing, substitution, elimination, and matrix operations.

In the context of the exercise, we have a system consisting of a quadratic equation and a linear equation. To solve it, we use substitution. First, solve one equation (typically the simpler one) for one variable, and then substitute this expression into the other equation. This process transforms the system into a single equation with one variable, which is easier to solve.
Quadratic Equations
A quadratic equation is a second-degree polynomial equation in a single variable x with a general form of \(ax^2 + bx + c = 0\), where a, b, and c are constants, and a is not equal to zero. The solutions to a quadratic equation are also known as the roots of the equation and can be found using various methods: factoring, completing the square, graphing, or using the quadratic formula, which is \(x = [-b \pm \sqrt{b^2 - 4ac}]/(2a)\).

In the exercise, after substituting the linear equation into the circle's equation, we obtain a quadratic equation. Solving this quadratic gives us the potential x-values for the points of intersection, which are crucial for finding the complete set of solutions for the system.
Circle Equations
Equations representing circles are a specific type of quadratic equation. A standard circle equation in the Cartesian coordinate plane is given by \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center of the circle and r is its radius. If the equation is in the form of \(x^2 + y^2 = r^2\), we can see that the circle is centered at the origin (0, 0).

In our exercise, \(x^2 + y^2 = 25\) is a circle centered at the origin with a radius of 5. When we intersect this circle with a line, we are essentially looking for points on the circle's circumference that also lie on the line – these are our points of intersection.
Graphing Equations
Graphing is a powerful tool for visualizing mathematical concepts and can aid in solving equations. By graphing equations, we can see where they cross, which corresponds to the solutions of the system. In a Cartesian coordinate system, quadratic equations graph as parabolas, while linear equations graph as straight lines.

To solve the given system graphically, you'd graph both the circle and the line on the same set of axes. The points where the line crosses the circle are the points of intersection. This visual method is especially useful when you have a solid understanding of how different equations correspond to their graphs. With graphing, you can often estimate the solutions before calculating them precisely, providing an excellent check for your algebraic solutions.

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