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Deciding Whether an Equation Is a Function In Exercises \(47-50\) , determine whether \(y\) is a function of \(x .\) $$ x^{2}+y=16 $$

Short Answer

Expert verified
No, y is not a function of x in the equation \(x^{2}+y=16\)

Step by step solution

01

Express y in terms of x

To isolate y, we can start by subtracting \(x^{2}\) from both sides of equation which will give us: \(y=16-x^{2}\)
02

Determine whether y is a function of x by visual observation

The equation \(y=16-x^{2}\) represents a parabola that opens downwards. A vertical line could cross the equation more than once, thus y is not a function of x in this equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Functions of x
Understanding whether an expression represents a function of x is crucial in calculus. A function, in mathematical terms, is a relationship between two variables, usually x and y, where each input (x-value) is associated with a unique output (y-value). When determining if an equation like \(y = 16 - x^2\) is a function of \(x\), we aim to figure out if every \(x\) corresponds to a single \(y\).

To visualize the concept, consider that for every hour in a day (our input, or \(x\)), there's a specific temperature (output, or \(y\)) recorded. If at any point two different temperatures were recorded at the same hour, this relation wouldn't qualify as a function. Similarly, when we isolate \(y\) in our equation, resulting in \(y = 16 - x^2\), we are setting the stage to investigate this one-to-one relationship between \(x\) and \(y\). Calculus revolves around functions, as it deals with continuous change and the rates at which these changes occur, so identifying functions is a foundational skill.
Parabola
A parabola is a specific type of curve found in geometry and algebra. It is the graph of a quadratic function, which has the general form \(y = ax^2 + bx + c\). This form is recognizable by the squared \(x\)—the hallmark of quadratic relationships.

In the equation \(y = 16 - x^2\), we notice that the coefficient of \(x^2\) is negative, which means the parabola opens downwards. If you imagine a U-shaped curve, it's like turning that U upside down. Graphically, the parabola will have a maximum point, known as the vertex, where it peaks before sloping back down. The shape of a parabola carries meaningful implications in physics and engineering, often representing the trajectory of projectiles under uniform gravitational force. In the context of functions, the parabola's shape can also inform us about whether the quadratic relationship is a function based on how it interacts with vertical lines—a key consideration when using the vertical line test.
Vertical Line Test
The vertical line test is a quick visual way to determine if a curve is a graph of a function of \(x\). Imagine drawing vertical lines (up and down) across a graph. If any vertical line crosses the graph more than once, then the curve does not represent a function. This is because, at some \(x\)-value, there would be more than one corresponding \(y\)-value, violating the definition of a function.

Applying this test to the equation \(y = 16 - x^2\), which we determined graphs a downward-opening parabola, we find that vertical lines will indeed intersect the curve in two places. This means there are certain \(x\)-values that correspond to two different \(y\)-values. So, despite having a beautifully symmetrical curve, our equation fails the vertical line test and hence \(y\) is not a function of \(x\) in this case. Understanding this test is essential for students because it provides a simple graphical method to check the function-ness of a relation without requiring extensive calculations.

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Most popular questions from this chapter

Apartment Rental \(A\) real estate office manages an apartment complex with 50 units. When the rent is \(\$ 780\) per month, all 50 units are occupied. However, when the rent is \(\$ 825,\) the average number of occupied units drops to 47 . Assume that the relationship between the monthly rent \(p\) and the demand \(x\) is linear. (Note: The term demand refers to the number of occupied units.) (a) Write a linear equation giving the demand \(x\) in terms of the rent \(p .\) rent \(p .\) (b) Linear extrapolation Use a graphing utility to gredict the demand equation and use the trace feature to predict the number of units occupied when the rent is raised to \(\$ 855\) . (c) Linear interpolation Predict the number of units occupied when the rent is lowered to \(\$ 795 .\) Verify graphically.

Finding the Domain and Range of a Function In Exercises \(11-22,\) find the domain and range of the function. $$ f(x)=\frac{3}{x} $$

Proof Prove that the product of two even (or two odd) functions is even.

Choosing a Job As a salesperson, you receive a monthly salary of \(\$ 2000\) , plus a commission of 7\(\%\) of sales. You are offered a new job at \(\$ 2300\) per month, plus a commission of 5\(\%\) of sales. (a) Write linear equations for your monthly wage \(W\) in terms of your monthly sales \(s\) for your current job and your job offer. (b) Use a graphing utility to graph each equation and find the point of intersection. What does it signify? (c) You think you can sell \(\$ 20,000\) worth of a product per month. Should you change jobs? Explain.

Sketching a Graph of a Function In Exercises \(33-40\) , sketch a graph of the function and find its domain and range. Use a graphing utility to verify your graph. $$ g(x)=\frac{4}{x} $$

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