Chapter 5: Problem 75
Find the outward flux of vector field \(\mathbf{F}=x y^{2} \mathbf{i}+x^{2} y \mathbf{j}\) across the boundary of annulus \(R=\left\\{(x, y): 1 \leq x^{2}+y^{2} \leq 4\right\\}=\\{(r, \theta): 1 \leq r \leq 2,0 \leq \theta \leq 2 \pi\\}\) using a computer algebra system.
Short Answer
Expert verified
The outward flux across the boundary is zero.
Step by step solution
01
Understand the Concept of Outward Flux
The outward flux of a vector field \( \mathbf{F} \) across a closed curve is the integral of the normal component of \( \mathbf{F} \) over the curve. In mathematical terms, it is given by \( \oint_{C} \mathbf{F} \cdot d\mathbf{r} \), where \( C \) is the closed boundary of the region. For an annulus, we typically use Green's Theorem to convert a line integral around the boundary into a double integral over the region.
02
Green's Theorem Application
Green's Theorem states that \( \oint_{C} \mathbf{F} \cdot d\mathbf{r} = \iint_{R} (abla \times \mathbf{F}) \cdot \mathbf{k} \, dA \), where \( dA \) is the area element and \( \mathbf{k} \) is the unit vector normal to the plane. Calculate \( abla \times \mathbf{F} \) for \( \mathbf{F}=x y^{2} \mathbf{i}+x^{2} y \mathbf{j} \). Because the vector field is two-dimensional, \( abla \times \mathbf{F} = \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \mathbf{k} \). Here, \( N = x^2 y \) and \( M = x y^2 \).
03
Compute Partial Derivatives
Find the partial derivatives: \( \frac{\partial N}{\partial x} = 2xy \) and \( \frac{\partial M}{\partial y} = 2xy \). Substitute these into \( abla \times \mathbf{F} = (\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y})\mathbf{k} = (2xy - 2xy)\mathbf{k} = 0 \cdot \mathbf{k} \).
04
Set Up and Solve the Double Integral
Since \( abla \times \mathbf{F} \) is zero, \( \iint_{R} (abla \times \mathbf{F}) \cdot \mathbf{k} \, dA = \iint_{R} 0 \, dx \, dy = 0 \), where \( R \) is the annular region defined by \( 1 \leq r \leq 2 \) and \( 0 \leq \theta \leq 2 \pi \).
05
Conclusion
Based on Green's Theorem, the outward flux of \( \mathbf{F} \) across the boundary of the annulus is the double integral over the area of \( R \), which evaluates to zero. Thus, the outward flux of \( \mathbf{F} \) across the boundary of the annulus \( R \) is zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Green's Theorem
Green's Theorem is a vital tool in calculus, particularly when it comes to transforming the challenging line integrals into the more manageable double integrals. Green's Theorem relates a closed line integral around a simple curve to a double integral over the enclosed plane region. Essentially, it converts the circulation of a vector field around a closed path into the sum of its curls over the corresponding region. In formula form, Green's Theorem is stated as:\[\oint_{C} \mathbf{F} \cdot d\mathbf{r} = \iint_{R} (abla \times \mathbf{F}) \cdot \mathbf{k} \, dA\]Where:
- \( \oint_{C} \mathbf{F} \cdot d\mathbf{r} \) is the line integral around curve \( C \).
- \( abla \times \mathbf{F} \) is the curl of the vector field \( \mathbf{F} \).
- \( \mathbf{k} \) is the unit vector perpendicular to the plane of the region.
- \( dA \) is a small element of area in region \( R \).
Vector Field
A vector field is a construction in mathematics that associates a vector to every point in a subset of space. Visualize it as a collection of arrows with a specific magnitude and direction, laid out across a region. For instance, wind speed and direction in weather maps or magnetic fields can be represented as vector fields.In the exercise, the vector field is given by:\[ \mathbf{F} = x y^{2} \mathbf{i} + x^{2} y \mathbf{j} \]This equation means:
- \( \mathbf{i} \) and \( \mathbf{j} \) are the unit vectors in the x-direction and y-direction, respectively.
- The field's components vary according to the position in the plane, controlled by the \( x \) and \( y \) coordinates.
Double Integral
The double integral is a way to accumulate quantities over a two-dimensional area. It helps us in computing total mass, charge, or flux by summing up small contributions from each region.In terms of mathematical representation, a double integral over a region \( R \) is written as:\[ \iint_{R} f(x, y) \, dx \, dy \]
- \( R \) is the region over which we are integrating.
- \( f(x, y) \) is the function whose values we are adding together. In some contexts, this could represent density or a similar quantity.