Chapter 5: Problem 69
Use Stokes' theorem to evaluate \(\iint_{S} \operatorname{curl} \mathbf{F} \cdot d S\).\(\mathbf{F}(x, y, z)=y \mathbf{i}-x \mathbf{j}+2 \mathbf{k}\), where \(S\) is the upper half of the unit sphere
Short Answer
Expert verified
The integral \( \iint_{S} \operatorname{curl} \mathbf{F} \cdot d S \) is 0.
Step by step solution
01
Understand Stokes' Theorem
Stokes' theorem relates a surface integral of the curl of a vector field over a surface to a line integral of the vector field along the boundary of the surface. Mathematically, it is given by: \[ \iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S} = \oint_{C} \mathbf{F} \cdot d\mathbf{r} \] where \( C \) is the boundary of the surface \( S \).
02
Identify the Surface and Its Boundary
The surface \( S \) is the upper half of the unit sphere defined by \( x^2 + y^2 + z^2 = 1 \). Its boundary, \( C \), is a circle at \( z = 0 \) with equation \( x^2 + y^2 = 1 \).
03
Parametrize the Boundary
The curve \( C \) can be parameterized using standard polar coordinates on the circle: \( \mathbf{r}(t) = \cos t \mathbf{i} + \sin t \mathbf{j} \), where \( t \) ranges from \( 0 \) to \( 2\pi \). The differential element is \( d\mathbf{r} = (-\sin t \mathbf{i} + \cos t \mathbf{j}) \, dt \).
04
Evaluate the Line Integral
Substitute \( \mathbf{F}(x, y, z) = y \mathbf{i} - x \mathbf{j} + 2 \mathbf{k} \) and \( d\mathbf{r} \) into the line integral: \[ \oint_{C} \mathbf{F} \cdot d\mathbf{r} = \int_0^{2\pi} (\sin t \cos t + \cos t \sin t) \, dt = \int_0^{2\pi} 0 \, dt = 0. \]
05
Conclusion Using Stokes' Theorem
By applying Stokes' theorem, since the line integral around the boundary \( C \) is zero, the surface integral of the curl of \( \mathbf{F} \) over the surface \( S \) is also zero: \[ \iint_{S} \operatorname{curl} \mathbf{F} \cdot d\mathbf{S} = 0. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Surface Integral
A surface integral enables us to compute the "waffle-like" accumulation of properties like flux or force through a defined surface. In essence, it involves the summing of quantities across an entire surface. Unlike traditional integrals that work along a line or through a volume, surface integrals stretch across two-dimensional surfaces.
To understand Stokes' Theorem through the lens of a surface integral, visualize a vector field like a gentle wind across a hilly landscape. The surface integral calculates how much of the wind is flowing through the surface, akin to measuring water flowing through a net. The surface here refers to the upper half of a sphere—a seamless boundary where the outside world interacts with the interior.
To understand Stokes' Theorem through the lens of a surface integral, visualize a vector field like a gentle wind across a hilly landscape. The surface integral calculates how much of the wind is flowing through the surface, akin to measuring water flowing through a net. The surface here refers to the upper half of a sphere—a seamless boundary where the outside world interacts with the interior.
- It's represented mathematically as \( \iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S} \).
- Here, \( \operatorname{curl} \mathbf{F} \) captures the rotation of the field \( \mathbf{F} \), while \( d\mathbf{S} \) stands for the infinitesimally small elements of area on the surface.
- The integration over the entire surface aggregates these elements to reach a cumulative total.
Curl of a Vector Field
The curl is an operation in vector calculus that describes the rotation of a vector field. Think of it as examining how 'twisty' or turbulent the field is at a given point. It is a critical measure, especially in fields like electromagnetism and fluid dynamics, to understand the nature of the flow or field behavior.
For a vector field \( \mathbf{F} = y \mathbf{i} - x \mathbf{j} + 2 \mathbf{k} \), the curl is obtained through a specific vector differentiation process. The resulting vector field describes the rotation at any point in space:
For a vector field \( \mathbf{F} = y \mathbf{i} - x \mathbf{j} + 2 \mathbf{k} \), the curl is obtained through a specific vector differentiation process. The resulting vector field describes the rotation at any point in space:
- To calculate the curl, you would use the cross-product of the del operator (∇) with the vector field \( \mathbf{F} \).
- The resulting vector field is \( \operatorname{curl} \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ y & -x & 2 \end{vmatrix}\).
- This results in a new vector that indicates the axis around which the rotation occurs and the magnitude of this rotation.
Line Integral
A line integral, unlike a traditional integral, takes into account the path or curve in space along which the integration is performed. It's like adding up small pieces of work done or energy accumulated along a path, making it essential in physics and engineering.
In the context of Stokes' Theorem, a line integral translates the behavior of a field at the boundary of a surface into a tangible, calculable form:
In the context of Stokes' Theorem, a line integral translates the behavior of a field at the boundary of a surface into a tangible, calculable form:
- The line integral is represented as \( \oint_{C} \mathbf{F} \cdot d\mathbf{r} \), where \( C \) is the closed path or boundary of the surface.
- In the exercise, the path \( C \) is a circle at the equator of a hemisphere, easily parameterized using trigonometric functions for accurate computation.
- During the exercise, substituting the vector field and the curve into the line integral yielded zero, indicating no change across the boundary's path.