Chapter 5: Problem 32
Find \(\operatorname{div} \mathbf{F}\), given that \(\mathbf{F}=\nabla f\), where \(f(x, y, z)=x y^{3} z^{2}\)
Short Answer
Expert verified
The divergence \( \operatorname{div} \mathbf{F} = 2xy(3z^2 + y^2) \).
Step by step solution
01
Understand the Problem
We are given a scalar function \( f(x, y, z) = xy^3z^2 \) and need to find the divergence of the vector field \( \mathbf{F} = abla f \). The divergence of a vector field is represented by \( \operatorname{div} \mathbf{F} = abla \cdot \mathbf{F} \). Since \( \mathbf{F} = abla f \), \( \operatorname{div} \mathbf{F} \) is also the Laplacian of \( f \).
02
Find the Gradient of f
The gradient of the function \( f \), denoted by \( abla f \), is \[ abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z} \right). \]Calculating each partial derivative gives:- \( \frac{\partial f}{\partial x} = y^3z^2 \)- \( \frac{\partial f}{\partial y} = 3xy^2z^2 \)- \( \frac{\partial f}{\partial z} = 2xy^3z \)Thus, \( abla f = (y^3z^2, 3xy^2z^2, 2xy^3z) \).
03
Calculate the Divergence
The divergence of a vector field \( \mathbf{F} = (F_1, F_2, F_3) \) is given by:\[ \operatorname{div} \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z}. \]Substitute \( \mathbf{F} = (y^3z^2, 3xy^2z^2, 2xy^3z) \) to find:- \( \frac{\partial}{\partial x}(y^3z^2) = 0 \)- \( \frac{\partial}{\partial y}(3xy^2z^2) = 6xyz^2 \)- \( \frac{\partial}{\partial z}(2xy^3z) = 2xy^3 \)Therefore, \( \operatorname{div} \mathbf{F} = 0 + 6xyz^2 + 2xy^3 = 2xy(3z^2 + y^2) \).
04
Interpret the Result
The final result obtained for the divergence \( \operatorname{div} \mathbf{F} = 2xy(3z^2 + y^2) \) represents a scalar field that describes how much \( \mathbf{F} \) spreads out from each point. Since \( \mathbf{F} = abla f \), it reflects the rate of change of the gradient's direction of the given scalar function.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient
The gradient is a critical concept in vector calculus. It transforms a scalar function into a vector field, which tells us the direction of the steepest ascent. A scalar function, like the one given in your exercise, denotes a single value at each point in space. In our case, the function is defined as
- \(f(x, y, z) = xy^3z^2\)
- \( \frac{\partial f}{\partial x} = y^3z^2 \)
- \( \frac{\partial f}{\partial y} = 3xy^2z^2 \)
- \( \frac{\partial f}{\partial z} = 2xy^3z \)
- \(abla f = (y^3z^2, 3xy^2z^2, 2xy^3z)\).
Scalar Function
A scalar function assigns a single real number to every point in space, providing a "density" or "intensity" at that point. Examples of scalar functions can include temperature, pressure, or, as in our exercise, a polynomial function that depends on x, y, and z. The given function is:
- \(f(x, y, z) = xy^3z^2\).
Laplacian
The Laplacian is a powerful operator in vector calculus that tells us about the curvature or spread of a scalar field. It is defined as the divergence of the gradient of a scalar function. In simpler terms, it measures how much the function's value "spreads out" around a point.
- Mathematically, for a scalar function \(f\), its Laplacian \(\Delta f\) is given by:\[\Delta f = abla \cdot abla f.\]
- \(\operatorname{div} \mathbf{F} = 2xy(3z^2 + y^2)\).