Chapter 5: Problem 29
Use Stokes' theorem to compute \(\iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S}\), where \(\mathbf{F}(x, y, z)=\mathbf{i}+x y^{2} \mathbf{j}+x y^{2} \mathbf{k}\) and \(S\) is a part of plane \(y+z=2\) inside cylinder \(x^{2}+y^{2}=1\) and oriented counterclockwise.
Short Answer
Expert verified
The integral is zero by Stokes' theorem.
Step by step solution
01
Understanding the exercise
We are given a vector field \( \mathbf{F}(x, y, z)=\mathbf{i}+x y^{2} \mathbf{j}+x y^{2} \mathbf{k}\) and the surface \( S \), which is part of the plane \( y+z=2 \) inside the cylinder \( x^{2}+y^{2}=1 \). We are tasked to use Stokes' theorem to calculate the surface integral \( \iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S}\).
02
Determine the Boundary Curve C
The boundary curve \( C \) is where the plane \( y+z=2 \) intersects the cylinder \( x^2 + y^2 = 1 \). By substituting \( z = 2 - y \) into the equation of the cylinder, we see that the boundary of \( C \) is described by the circle \( x^2 + y^2 = 1 \) with \( z = 2 - y \).
03
Compute Curl of \( \mathbf{F} \)
To compute \( \operatorname{curl} \mathbf{F} \), we use the formula \( abla \times \mathbf{F} \). Calculate each component: \( \operatorname{curl} \mathbf{F} = \left(\frac{\partial (xy^2)}{\partial y} - \frac{\partial (xy^2)}{\partial z}\right) \mathbf{i} + \left(\frac{\partial (1)}{\partial z} - \frac{\partial (xy^2)}{\partial x} \right) \mathbf{j} + \left(\frac{\partial (xy^2)}{\partial x} - \frac{\partial (1)}{\partial y} \right) \mathbf{k} = 0\mathbf{i} + (-y^2)\mathbf{j} + (y^2)\mathbf{k}\).
04
Apply Stokes' Theorem
Stokes' Theorem allows us to convert the surface integral into a line integral: \( \iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S} = \oint_{C} \mathbf{F} \cdot d\mathbf{r} \). Parameterize \( C \) with \( \mathbf{r}(t) = (\cos t, \sin t, 2 - \sin t) \), for \( t \in [0, 2\pi] \).
05
Evaluate the Line Integral
Differentiate the parameterization: \( \mathbf{r}'(t) = (-\sin t, \cos t, -\cos t) \). Compute \( \mathbf{F}(\mathbf{r}(t)) = \mathbf{i} + \cos t \sin^2 t \mathbf{j} + \cos t \sin^2 t \mathbf{k} \). The line integral becomes \( \oint_C \mathbf{F} \cdot d\mathbf{r} = \int_0^{2\pi} \left( \cos t \sin^2 t \right)(\cos t - \cos t) \, dt = 0 \).
06
Conclude solution
Since the line integral around \( C \) evaluates to zero, by Stokes' Theorem, the surface integral \( \iint_{S} \operatorname{curl} \mathbf{F} \cdot d \mathbf{S} \) is also zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Surface Integral
A surface integral is a powerful tool in vector calculus that allows us to integrate over a curved surface. Imagine a net or a sheet in three-dimensional space; a surface integral sums up the contributions from tiny pieces of this sheet, which are influenced by a vector field. The way the field lines pass through or along the surface determines the value of the surface integral. This means the surface integral helps us understand how a vector field interacts with a surface in space.
To compute a surface integral, you generally need:
- A surface, which can be flat (like a plane) or curved (like a part of a sphere).
- A vector field acting on the surface.
- The orientation of the surface, which tells you which way is 'up' or 'out' relative to the surface.
Vector Field
A vector field assigns a vector to every point in a space. If you imagine placing an arrow at every point in a region of space, showing the direction and magnitude of a force or velocity, this is similar to a vector field. These fields can be used to model various real-world phenomena such as wind patterns, magnetic fields, or the flow of water. The vector field in our exercise is given by:\[ \mathbf{F}(x, y, z) = \mathbf{i} + x y^2 \mathbf{j} + x y^2 \mathbf{k}\]This particular field involves components that change with the values of \(x\), \(y\), and \(z\), specifically emphasizing the role of \(y^2\). Understanding these components helps you understand how the field behaves as you move through different points in space, which is crucial when applying calculus theorems such as Stokes'.
Curl of a Vector Field
The curl of a vector field provides information about its rotational behavior. It tells you how much and in which direction the field is "spinning". For the vector field \(\mathbf{F}\), finding the curl involves taking derivatives and arranging them into a new vector. The formula for the curl of a vector field \((\mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k})\) is:\[abla \times \mathbf{F} = \left(\frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z}\right)\mathbf{i} + \left(\frac{\partial P}{\partial z} - \frac{\partial R}{\partial x}\right)\mathbf{j} + \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right)\mathbf{k}\]For our specific \(\mathbf{F}\), calculations show:\[abla \times \mathbf{F} = 0\mathbf{i} - y^2\mathbf{j} + y^2\mathbf{k}\]Understanding the curl is essential for applying Stokes' theorem, which connects this idea to the line integral along a boundary of a surface.
Line Integral
A line integral is a way of measuring how a vector field influences movement along a curve. Imagine walking along a path in a field of arrows, which each represent a tiny force or velocity at every step along your walk; the line integral gives the total effect all these arrows have as you move along that path. To compute a line integral, you must:
- Parameterize the path or curve you're integrating along.
- Evaluate the vector field at points along the curve.
- Integrate these values along the curve, accounting for the direction of movement.