Chapter 4: Problem 51
The solid \(E\) bounded by \(z=10-2 x-y\) and situated in the first octant is given in the following figure. Find the volume of the solid.
Short Answer
Expert verified
The volume of the solid is \( \frac{250}{3} \).
Step by step solution
01
Understand the Boundary Conditions
The solid is bounded by the plane equation \(z = 10 - 2x - y\). It is situated in the first octant, meaning all coordinates \((x, y, z)\) are positive. Additionally, the plane must intersect all axes in non-negative points.
02
Identify the Intersection Points
The plane intersects the \(x\)-axis where \(z = 0\) and \(y = 0\), giving the point \( (5, 0, 0) \) by solving \( 10 - 2x = 0 \). It intersects the \(y\)-axis where \(z = 0\) and \(x = 0\), giving the point \( (0, 10, 0) \) by solving \( 10 - y = 0 \). It intersects the \(z\)-axis at \( (0, 0, 10) \) by setting \(x = 0\) and \(y = 0\).
03
Establish the Limits for Integration
Since the solid is in the first octant under the plane, we include limits from 0 to these intersections: \(0 \leq x \leq 5\), \(0 \leq y \leq 10 - 2x\), and \(0 \leq z \leq 10 - 2x - y\).
04
Set Up the Triple Integral
To calculate the volume, we integrate \(1\) over the region defined by the above limits: \[ V = \int_{0}^{5} \int_{0}^{10-2x} \int_{0}^{10-2x-y} 1 \, dz \, dy \, dx \]
05
Perform the Integration Over z
Integrating with respect to \(z\):\[ \int_{0}^{10-2x-y} 1 \, dz = 10 - 2x - y \]
06
Perform the Integration Over y
Substitute the result from the previous step into the next integral:\[ \int_{0}^{10-2x} (10 - 2x - y) \, dy = [ (10-2x)y - \frac{y^2}{2} ]_{0}^{10-2x} \]Evaluating this gives:\[ (10-2x)(10-2x) - \frac{(10-2x)^2}{2} = \frac{(10-2x)^2}{2} \]
07
Perform the Integration Over x
Integrate the result concerning \(x\):\[ \int_{0}^{5} \frac{(10 - 2x)^2}{2} \, dx \]\[ = \frac{1}{2} \int_{0}^{5} (100 - 40x + 4x^2) \, dx \]\[ = \frac{1}{2} \left( 100x - 20x^2 + \frac{4x^3}{3} \right)_{0}^{5} \]
08
Calculate the Final Volume
Evaluate the expression:\[ \frac{1}{2} \left( 100(5) - 20(5)^2 + \frac{4(5)^3}{3} \right) = \frac{1}{2} (500 - 500 + \frac{500}{3}) = \frac{1}{2} \left( \frac{500}{3} \right) \]\[ = \frac{250}{3} \]
09
Present the Final Result
The volume of the solid in the first octant bounded by the plane \(z = 10 - 2x - y\) is \( \frac{250}{3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Triple Integral
A triple integral is a mathematical tool used to calculate the volume of a three-dimensional region. You can think of it as an extension of double integrals, which are used to find the area under a curve in a 2D space. In the context of computing volume, a triple integral sums up infinitely small volumes in a three-dimensional object. By integrating over three variables usually denoted by \( x, y, \text{ and } z \), we obtain the total volume.The general form of a triple integral is:
- \( \int \int \int f(x, y, z) \, dz \, dy \, dx \).
- Here, \( f(x, y, z) \) is the function representing the density at each point, but often it is simply \( 1 \) when finding the volume.
- The limits of integration correspond to the boundary constraints of the region.
First Octant
The first octant is a crucial concept in three-dimensional geometry. It pertains to the portion of space where all three coordinates \( x, y, \text{ and } z \) are positive. Visualize a 3D Cartesian coordinate system divided by three mutually perpendicular planes—the \( xy \)-plane, \( yz \)-plane, and \( zx \)-plane—intersecting each at the origin. These planes divide space into eight sections or 'octants'.
- The first octant is found in the positive direction of all three axes: \( x > 0, y > 0, \text{ and } z > 0 \).
- This region is essential for problems involving spatial geometry, as it establishes a zone where all points have non-negative coordinates.
Plane Equation Intersection
A plane equation in three dimensions is typically expressed as \( z = ax + by + c \), which describes a flat surface in space. Finding where a plane intersects the axes provides critical information about a region's boundaries and constraints. Understanding these intersection points helps to establish limits for integration.
- For the \( x\)-axis, set \( y = 0 \) and \( z = 0 \). Solve the equation to find where the plane crosses.
- For the \( y\)-axis, set \( x = 0 \) and \( z = 0 \), then solve for \( y \).
- For the \( z\)-axis, set \( x = 0 \) and \( y = 0 \). This directly gives the \( z \) intersection.
- Point \( (5, 0, 0) \) on the \( x\)-axis,
- Point \( (0, 10, 0) \) on the \( y\)-axis, and
- Point \( (0, 0, 10) \) on the \( z\)-axis.