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For the following exercises, find the level curves of each function at the indicated value of \(c\) to visualize the given function. $$ g(x, y)=e^{x y} ; c=\frac{1}{2}, 3 $$

Short Answer

Expert verified
The level curves are hyperbolas: \(xy = -\ln(2)\) for \(c = 1/2\), and \(xy = \ln(3)\) for \(c = 3\).

Step by step solution

01

Understand the Function

The given function is \( g(x, y) = e^{xy} \). This is a two-variable function involving the exponential of the product of \(x\) and \(y\).
02

Define Level Curves

Level curves are obtained by setting the function \( g(x, y) \) equal to a constant value \( c \). This results in an equation in terms of \( x \) and \( y \) only.
03

Level Curve for c = 1/2

For \( c = \frac{1}{2} \), set \( e^{xy} = \frac{1}{2} \). Taking the natural logarithm of both sides gives \( xy = \ln\left(\frac{1}{2}\right) \). This is one equation for the level curve.
04

Simplify Equation for c = 1/2

Using the property \( \ln\left(\frac{1}{2}\right) = -\ln(2) \), the equation becomes \( xy = -\ln(2) \). This represents a hyperbola.
05

Level Curve for c = 3

For \( c = 3 \), set \( e^{xy} = 3 \). Again, take the natural logarithm to get \( xy = \ln(3) \).
06

Identify Curve for c = 3

This equation, \( xy = \ln(3) \), also represents a hyperbola but at a different level than for \( c = \frac{1}{2} \). Both equations describe a family of hyperbolas centered at the origin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-variable functions
Two-variable functions are mathematical expressions that depend on two independent variables. In the case of the function given, \( g(x, y) = e^{xy} \), both \( x \) and \( y \) are the independent variables that influence the function's output. This means that the value of the function is determined by the product \( xy \).

Such functions are represented on a three-dimensional graph, where usually the two variables (\( x \) and \( y \)) define the horizontal plane, and the function value, \( g(x, y) \), projects onto the vertical axis.
  • Familiarize with how changing one or both variables affects the function value.
  • Understand how contour or level curves offer a two-dimensional perspective of the function's behavior.
These level curves occur where the function equals a constant value, \( c \), and help visualize how \( x \) and \( y \) interact to reach that value.
Exponential functions
Exponential functions are characterized by having a variable as an exponent. In the two-variable function \( g(x, y) = e^{xy} \), the expression involves the base \( e \) raised to the power of \( xy \).

One key property of exponential functions is their consistent growth rate. They increase rapidly because each increment in the exponent results in a proportional increase in the function's value.
  • Understand that exponential functions can model real-life growth scenarios such as population or cooling processes.
  • Recognize the logarithm as the inverse operation to exponentiation, which is useful in solving equations involving exponentials.
By setting the exponential function equal to a constant (like \( c = \frac{1}{2} \) or \( c = 3 \)), one can use logarithms to solve for the variable terms, further defining the level curves that are the focus of this problem.
Hyperbolas
Hyperbolas are a type of conic section, which appear as open curves that approach two intersecting asymptotes. When level curves of the exponential function \( e^{xy} \) are explored, certain values of \( c \) lead to equations of the form \( xy = \text{constant} \), which represent hyperbolas.

These hyperbolas occur because the equations take the form of \( xy = c \), describing curves symmetrical about both the \( x \)- and \( y \)-axes. They demonstrate how the values of \( x \) and \( y \) correlate inversely to maintain the equation.
  • The shape of a hyperbola is defined by the equation's constant; a negative constant results in hyperbolas positioned differently than a positive one.
  • The curves never intersect their asymptotes, elucidating how hyperbolas spread over the plane.
This concept explains why, in this exercise, the level curves for \( c = \frac{1}{2} \) and \( c = 3 \) transform into hyperbolas representing different levels of function values.

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