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Evaluate the limits at the indicated values of \(x\) and \(y\). If the limit does not exist, state this and explain why the limit does not exist. $$ \lim _{(x, y) \rightarrow(0,0)} \ln \left(x^{2}+y^{2}\right) $$

Short Answer

Expert verified
The limit does not exist because \( \ln(x^2 + y^2) \rightarrow -\infty \) as \((x, y) \rightarrow (0,0)\).

Step by step solution

01

Understanding the Limit Expression

We need to evaluate the limit of the function \( \ln(x^2 + y^2) \) as \((x, y)\) approaches \((0, 0)\). The function is a natural logarithm of the sum of squares of \(x\) and \(y\).
02

Assessing the Inside Function's Behavior

As \((x, y)\) approaches \((0, 0)\), both \(x^2\) and \(y^2\) approach \(0\). Thus, \(x^2 + y^2\) approaches \(0\).
03

Considering the Logarithm's Domain

The natural logarithm function, \( \ln(z) \), is only defined for positive \(z\). As \(x^2 + y^2\) approaches \(0\), it becomes positive but very small. Approaching \(0\) from the right, \( \ln(x^2 + y^2) \) becomes very negative.
04

Concluding on the Limit

As \(x^2 + y^2\) approaches \(0\), \( \ln(x^2 + y^2) \rightarrow -\infty \). This implies the limit does not exist because the function goes to negative infinity instead of converging to a real number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, commonly denoted as \( \ln(x) \), is a fundamental concept in calculus and analysis. It is the inverse function of the exponential function, and is only defined for positive numbers. This means you cannot take the natural logarithm of zero or a negative number, as these values do not exist on the real number line for this function.
In practice, \( \ln(x) \) transforms multiplication into addition, a property that makes it extremely useful for simplifying expressions. For example, \( \ln(a \times b) = \ln(a) + \ln(b) \). This concept becomes crucial when you evaluate limits involving natural logarithms because understanding its domain helps determine if the limit is approachable or not.
In the context of this exercise, knowing that \( \ln(x^2 + y^2) \) is undefined if \( x^2 + y^2 \leq 0 \) helps us quickly anticipate potential issues near points where \( x^2 + y^2 \rightarrow 0 \). Understanding this nuance is key to evaluating the behavior of limits in multivariable calculus.
Limit Evaluation
Evaluating a limit means determining what value a function approaches as its inputs approach a certain point. In multivariable calculus, we deal with limits where the inputs, like \( (x, y) \), approach a specific point, such as \( (0, 0) \).
For the function \( \ln(x^2 + y^2) \), the inputs \( (x, y) \) simultaneously approach \( (0, 0) \). It's important to check the behavior of the function's inputs. Specifically, determine how \( x^2 + y^2 \) behaves since its limit directly influences the behavior of \( \ln(x^2 + y^2) \).
As you calculate the limit, it helps to visualize or sketch how the points move in space. With \( x = 0 \) and \( y \to 0 \) or \( y = 0 \) and \( x \to 0 \), \( x^2 + y^2 \) approaches zero. Through this approach, you can effectively predict whether the function will converge to a specific number or diverge, as it does in this exercise.
Function Behavior
Understanding the behavior of underlying functions helps to anticipate the outcome of complex limit problems. Here, we examine the behavior of \( x^2 + y^2 \) as it affects the function \( \ln(x^2 + y^2) \).
Both \( x^2 \) and \( y^2 \) will be non-negative, and their sum approaches zero as \( x \) and \( y \) do. However, \( x^2 + y^2 \) itself never becomes negative or zero; it only approaches zero from the positive side. Thus, even when very small, it is still positive.
This minuscule positive value results in the natural logarithm output becoming a very large negative number. As \( x^2 + y^2 \) gets increasingly smaller, \( \ln(x^2 + y^2) \) gets more and more negative, potentially reaching negative infinity if you let \( x^2 + y^2 \to 0 \, (\text{from above}) \). This behavior is indicative of a function diverging, which guides us to the conclusion that the limit does not exist.
Indeterminate Form
Indeterminate forms occur when applying basic limit laws yields an ambiguous result, often necessitating further analysis. In multivariable calculus, recognizing these forms is crucial to proper limit evaluation.
In this problem, as \( (x, y) \to (0, 0) \), the expression \( x^2 + y^2 \rightarrow 0 \). Because the natural logarithm function can't handle zero directly, the form becomes indeterminate in terms of conventional evaluation as it leans toward \( \ln(0) \).
While tackling such forms, one technique is reconciling what effectively happens numerically or historically for smaller values close to zero. In particular, determining the extent by which the logarithm descends when considering values close to zero—as in this case—might reveal whether we genuinely enter indeterminacy or whether the function leans towards a polarity, such as positive or negative infinity.
By identifying that \( \ln(x^2 + y^2) \rightarrow -\infty \), we see not an answer in specific finite terms, but rather an indication that the limit does not truly resolve to a number, qualifying this as a typical non-convergent form.

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Most popular questions from this chapter

Find parametric equations for the normal line to the surface at the indicated point. (Recall that to find the equation of a line in space, you need a point on the line, \(P_{0}\left(x_{0}, y_{0}, z_{0}\right)\), and a vector \(\mathbf{n}=\langle a, b, c\rangle\) that is parallel to the line. Then the equation of the line is \(\left.x-x_{0}=a t, y-y_{0}=b t, z-z_{0}=c t .\right)\) $$ -3 x+9 y+4 z=-4, P(1,-1,2) $$

For the following exercises, use Lagrange multipliers to find the maximum and minimum values for the functions with the given constraints. A machinist is constructing a right circular cone out of a block of aluminum. The machine gives an error of \(5 \%\) in height and \(2 \%\) in radius. Find the maximum error in the volume of the cone if the machinist creates a cone of height \(6 \mathrm{~cm}\) and radius \(2 \mathrm{~cm}\).

The centripetal acceleration of a particle moving in a circle is given by \(a(r, v)=\frac{v^{2}}{r}\), where \(v\) is the velocity and \(r\) is the radius of the circle. Approximate the maximum percent error in measuring the acceleration resulting from errors of \(3 \%\) in \(v\) and \(2 \%\) in \(r\). (Recall that the percentage error is the ratio of the amount of error over the original amount. So, in this case, the percentage error in \(a\) is given by \(\left.\frac{d a}{a} .\right)\)

Find the equation for the tangent plane to the surface at the indicated point. $$ h(x, y)=\ln \sqrt{x^{2}+y^{2}}, P(3,4) $$

For the following exercises, use the method of Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraints. $$ f(x, y, z)=x^{2}+y^{2}+z^{2}, x^{4}+y^{4}+z^{4}=1 $$

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