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For the following exercises, use the given vectors to find the quantities.\(\mathbf{a}=2 \mathbf{i}+\mathbf{j}-9 \mathbf{k}, \mathbf{b}=-\mathbf{i}+2 \mathbf{k}, \mathbf{c}=4 \mathbf{i}-2 \mathbf{j}+\mathbf{k}\) a. \(2 \mathbf{a}-\mathbf{b}\) b. \(|\mathbf{b} \times \mathbf{c}|\) c. \(\mathbf{b} \times|\mathbf{b} \times \mathbf{c}|\) d. \(\mathbf{c} \times|\mathbf{b} \times \mathbf{a}|\) e. \(\operatorname{proj}_{a} \mathbf{b}\)

Short Answer

Expert verified
a. \(5 \mathbf{i} + 2 \mathbf{j} - 16 \mathbf{k}\), b. \(\sqrt{101}\), c. \(\sqrt{101}(-\mathbf{i} + 2 \mathbf{k})\), d. [For full solution, use determinant], e. \(-\frac{10}{43}(2 \mathbf{i} + \mathbf{j} - 9 \mathbf{k})\).

Step by step solution

01

Expression Simplification

To solve part a, we need to perform vector operations. Calculate the expression \(2 \mathbf{a} - \mathbf{b}\) using given vectors. Multiply \(\mathbf{a}\) by 2: \(2(2\mathbf{i} + \mathbf{j} - 9\mathbf{k}) = 4\mathbf{i} + 2\mathbf{j} - 18\mathbf{k}\). Now, subtract \(\mathbf{b}\):\[4\mathbf{i} + 2\mathbf{j} - 18\mathbf{k} - (-\mathbf{i} + 2 \mathbf{k}) = (4+1)\mathbf{i} + 2\mathbf{j} - (18-2)\mathbf{k} = 5 \mathbf{i} + 2\mathbf{j} - 16\mathbf{k}\].
02

Calculate Cross Product Magnitude

For part b, compute \(|\mathbf{b} \times \mathbf{c}|\). First, find \(\mathbf{b} \times \mathbf{c}\) using the determinant of the following matrix:\[\begin{vmatrix}\mathbf{i} & \mathbf{j} & \mathbf{k} \-1 & 0 & 2 \4 & -2 & 1\end{vmatrix} = \mathbf{i}(0 \cdot 1 - 2 \cdot (-2)) - \mathbf{j}(-1 \cdot 1 - 2 \cdot 4) + \mathbf{k}(-1 \cdot (-2) - 0 \cdot 4)\]Simplifying, \(\mathbf{b} \times \mathbf{c} = 4\mathbf{i} + 9\mathbf{j} - 2\mathbf{k}\). So, the magnitude is \(|\mathbf{b} \times \mathbf{c}| = \sqrt{4^2 + 9^2 + (-2)^2} = \sqrt{16 + 81 + 4} = \sqrt{101}\).
03

Cross Product of Magnitude

For part c, first notice that \(\mathbf{b} \times \mathbf{c}\) has been computed already. We use its magnitude \(\sqrt{101}\) found in Step 2 to re-calculate: Calculate \(\mathbf{b} \times|\mathbf{b} \times \mathbf{c}|\) using \(\mathbf{b} = -\mathbf{i} + 2 \mathbf{k}\) and \(|\mathbf{b} \times \mathbf{c}| = \sqrt{101}\). Hence, \[\mathbf{b} \times \sqrt{101} = \sqrt{101}(-\mathbf{i} + 0\mathbf{j} + 2\mathbf{k})\]. This results in other theoretical expressions that are not a vector cross product since it's a scalar multiplication.
04

Cross Product with another magnitude

For part d, compute \(|\mathbf{b} \times \mathbf{a}|\) first. Follow similar steps used in previous cross products. Using vectors \(\mathbf{b} = -\mathbf{i} + 0\mathbf{j} + 2\mathbf{k}\) and \(\mathbf{a} = 2\mathbf{i} + \mathbf{j} - 9\mathbf{k}\), \[\begin{vmatrix}\mathbf{i} & \mathbf{j} & \mathbf{k} \-1 & 0 & 2 \2 & 1 & -9\end{vmatrix}\]results in calculation \((-1)(1) - (0)(-9) \mathbf{i} - ((-1)(-9) - (2)(2)) \mathbf{j} + ((-1)(1) - (0)(2)) \mathbf{k}\), simplifying to find \([2\mathbf{i}-13\mathbf{j}-1\mathbf{k}]\).
05

Vector Projection

For part e, calculate the projection of \(\mathbf{b}\) onto \(\mathbf{a}\) using the formula: \[\operatorname{proj}_{a} \mathbf{b} = \left( \frac{\mathbf{b} \cdot \mathbf{a}}{\mathbf{a} \cdot \mathbf{a}} \right) \mathbf{a}. \]Calculate the dot product \(\mathbf{b} \cdot \mathbf{a} = (-1)(2) + (0)(1) + (2)(-9) = -2 - 18 = -20\), and \(\mathbf{a} \cdot \mathbf{a} = (2)(2) + (1)(1) + (-9)(-9) = 4 + 1 + 81 = 86\). Therefore, the projection is \[\left( -\frac{20}{86} \right)(2\mathbf{i} + \mathbf{j} - 9\mathbf{k}) = -\frac{10}{43}(2\mathbf{i} + \mathbf{j} - 9\mathbf{k}).\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Operations
Vector operations form the basis of various calculations in vector calculus. A vector is a quantity having both magnitude and direction, commonly expressed in terms of its components along standard unit vectors such as \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \). Fundamental vector operations include addition, subtraction, and scalar multiplication.
- **Addition** is performed by adding corresponding components. For example, if \( \mathbf{u} = a_1 \mathbf{i} + b_1 \mathbf{j} + c_1 \mathbf{k} \) and \( \mathbf{v} = a_2 \mathbf{i} + b_2 \mathbf{j} + c_2 \mathbf{k} \), then \( \mathbf{u} + \mathbf{v} = (a_1 + a_2) \mathbf{i} + (b_1 + b_2) \mathbf{j} + (c_1 + c_2) \mathbf{k} \).- **Subtraction** involves subtracting the corresponding components of one vector from another. For instance, \( \mathbf{u} - \mathbf{v} = (a_1 - a_2) \mathbf{i} + (b_1 - b_2) \mathbf{j} + (c_1 - c_2) \mathbf{k} \).
- **Scalar multiplication** involves multiplying each component of a vector by a scalar, a real number. Given a scalar \( k \), multiplying a vector \( \mathbf{u} \) by \( k \) results in \( k\mathbf{u} = k(a_1 \mathbf{i} + b_1 \mathbf{j} + c_1 \mathbf{k}) = ka_1 \mathbf{i} + kb_1 \mathbf{j} + kc_1 \mathbf{k} \).
These operations can manipulate vectors and solve problems involving directions and magnitudes.
Cross Product
The cross product, or vector product, is an operation on two vectors in three-dimensional space. It results in another vector that is perpendicular to both original vectors. The cross product is denoted by \( \mathbf{u} \times \mathbf{v} \).
To compute this product, we use a determinant involving the unit vectors \( \mathbf{i} \), \( \mathbf{j} \), and \( \mathbf{k} \) along with the components of the vectors \( \mathbf{u} = a \mathbf{i} + b \mathbf{j} + c \mathbf{k} \) and \( \mathbf{v} = d \mathbf{i} + e \mathbf{j} + f \mathbf{k} \). The determinant structure is:
\[\begin{vmatrix}\mathbf{i} & \mathbf{j} & \mathbf{k} \a & b & c \d & e & f\end{vmatrix}\]
This results in a vector:\[ (a(f) - b(e))\mathbf{i} - (a(f) - c(d))\mathbf{j} + (e(a) - d(b))\mathbf{k}.\]
The magnitude of this vector provides insights into the area of the parallelogram formed by the original vectors, computed as \( |\mathbf{u} \times \mathbf{v}| \). The direction of the resulting vector adheres to the right-hand rule, which helps determine directionality in physics and engineering.
Vector Projection
Vector projection is a technique used to determine how much one vector projects onto another. This operation simplifies scenarios where it’s important to isolate the component of one vector along the direction of another.
To find the projection of vector \( \mathbf{v} \) onto \( \mathbf{u} \), we use the formula:
\[ \operatorname{proj}_u \mathbf{v} = \left( \frac{\mathbf{v} \cdot \mathbf{u}}{\mathbf{u} \cdot \mathbf{u}} \right) \mathbf{u}.\]
Here, \( \mathbf{v} \cdot \mathbf{u} \) represents the dot product of \( \mathbf{v} \) and \( \mathbf{u} \), which is a scalar showing how much \( \mathbf{v} \) extends in the direction of \( \mathbf{u} \).
- The dot product \( \mathbf{v} \cdot \mathbf{u} = a_1b_1 + a_2b_2 + a_3b_3 \) where each term is a product of corresponding components.
- The scalar \( \frac{\mathbf{v} \cdot \mathbf{u}}{\mathbf{u} \cdot \mathbf{u}} \) scales the direction vector \( \mathbf{u} \) to give the projection.
This tool is especially useful in physics for determining forces or velocities in specific directions.
Magnitude of a Vector
The magnitude of a vector, often referred to as its length, denotes how "long" the vector is. For a vector \( \mathbf{v} = a \mathbf{i} + b \mathbf{j} + c \mathbf{k} \) in three-dimensional space, the magnitude can be calculated using the Pythagorean theorem extension:
\[ |\mathbf{v}| = \sqrt{a^2 + b^2 + c^2}. \]
This formula essentially extends the idea of calculating the hypotenuse in a right triangle to higher dimensions. Each component of the vector is squared, summed, and then square-rooted to find the vector's total extent or magnitude.
Understanding a vector’s magnitude is crucial in fields like physics and engineering, where it helps quantify physical quantities such as force, velocity, and displacement.
  • For example, a velocity vector’s magnitude provides the speed, which is the scalar measure of how fast a point is moving.
  • Similarly, in medicine or biology, the direction of growth or movement of cells can be quantified using magnitudes of relevant vectors.
Such understanding facilitates complex problem-solving and precise calculation of various scientific phenomena.

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Most popular questions from this chapter

Find the equation of the quadric surface with points \(P(x, y, z)\) that are equidistant from point \(Q(0,-1,0)\) and plane of equation \(y=1\). Identify the surface.

Rewrite the given equation of the quadric surface in standard form. Identify the surface. $$ 5 x^{2}-4 y^{2}+20 z^{2}=0 $$

Find the trace of the given quadric surface in the specified plane of coordinates and sketch it. $$ -4 x^{2}+25 y^{2}+z^{2}=100, x=0 $$

Consider vectors \(\mathbf{u}=2 \mathbf{i}+4 \mathbf{j}\) and \(\mathbf{v}=4 \mathbf{j}+2 \mathbf{k}\) a. Find the component form of vector \(\mathbf{w}=\operatorname{proj}_{\mathrm{u}} \mathbf{v}\) that represents the projection of \(\mathrm{v}\) onto \(\mathbf{u}\). b. Write the decomposition \(\mathbf{v}=\mathbf{w}+\mathbf{q}\) of vector \(\mathbf{v}\) into the orthogonal components \(\mathbf{w}\) and \(\mathbf{q}\), where \(\mathbf{w}\) is the projection of \(\mathrm{v}\) onto \(\mathrm{u}\) and \(\mathbf{q}\) is a vector orthogonal to the direction of \(\mathrm{u}\).

The ring torus symmetric about the \(z\) -axis is a special type of surface in topology and its equation is given by \(\left(x^{2}+y^{2}+z^{2}+R^{2}-r^{2}\right)^{2}=4 R^{2}\left(x^{2}+y^{2}\right)\), where \(R>r>0 .\) The numbers \(R\) and \(r\) are called are the major and minor radii, respectively, of the surface. The following figure shows a ring torus for which \(R=2\) and \(r=1\). a. Write the equation of the ring torus with \(R=2\) and \(r=1\), and use a CAS to graph the surface. Compare the graph with the figure given. b. Determine the equation and sketch the trace of the ring torus from a. on the \(x y\) -plane. c. Give two examples of objects with ring torus shapes.

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