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For the following exercises, the vectors a, b, and c are given. Determine the vectors (a?b)c and (a?c)b. Express the vectors in component form. $$ \mathbf{a}=\mathbf{i}+\mathbf{j}, \mathbf{b}=\mathbf{i}-\mathbf{k}, \mathbf{c}=\mathbf{i}-2 \mathbf{k} $$

Short Answer

Expert verified
\((\mathbf{a} \times \mathbf{b}) \times \mathbf{c} = -2\mathbf{i} - 3\mathbf{j} - \mathbf{k}; (\mathbf{a} \times \mathbf{c}) \times \mathbf{b} = -2\mathbf{i} - 3\mathbf{j} - 2\mathbf{k}."

Step by step solution

01

Calculate the Cross Product \( \mathbf{a} \times \mathbf{b} \)

The cross product \( \mathbf{a} \times \mathbf{b} \) involves vectors \( \mathbf{a} = \mathbf{i} + \mathbf{j} \) and \( \mathbf{b} = \mathbf{i} - \mathbf{k} \). The standard formula for the cross product \( \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 1 & 1 & 0 \ 1 & 0 & -1 \end{vmatrix} \) yields this determinant:\[ \mathbf{a} \times \mathbf{b} = \mathbf{i}(1 \cdot -1 - 0 \cdot 0) - \mathbf{j}(1 \cdot -1 - 0 \cdot 1) + \mathbf{k}(1 \cdot 0 - 1 \cdot 1) \]\[ = -\mathbf{i} + \mathbf{j} - \mathbf{k} \]. Therefore, \( \mathbf{a} \times \mathbf{b} = -\mathbf{i} + \mathbf{j} - \mathbf{k} \).
02

Calculate \((\mathbf{a} \times \mathbf{b}) \times \mathbf{c}\)

Now use the vector \( \mathbf{c} = \mathbf{i} - 2\mathbf{k} \) and cross product \( \mathbf{a} \times \mathbf{b} = -\mathbf{i} + \mathbf{j} - \mathbf{k} \).The cross product \( (\mathbf{a} \times \mathbf{b}) \times \mathbf{c} \) results in:\[ \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ -1 & 1 & -1 \ 1 & 0 & -2 \end{vmatrix} \]\[ = \mathbf{i}(1 \cdot -2 - 0 \cdot -1) - \mathbf{j}(-1 \cdot -2 - 1 \cdot 1) + \mathbf{k}(-1 \cdot 0 - 1 \cdot 1) \]\[ = -2\mathbf{i} - 3\mathbf{j} - \mathbf{k} \].
03

Calculate the Cross Product \(\mathbf{a} \times \mathbf{c}\)

Determine \( \mathbf{a} \times \mathbf{c} \) using vectors \( \mathbf{a} = \mathbf{i} + \mathbf{j} \) and \( \mathbf{c} = \mathbf{i} - 2\mathbf{k} \).The determinant:\[ \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 1 & 1 & 0 \ 1 & 0 & -2 \end{vmatrix} \] results in\[ \mathbf{i}(1 \cdot -2 - 0 \cdot 0) - \mathbf{j}(1 \cdot -2 - 0 \cdot 1) + \mathbf{k}(1 \cdot 0 - 1 \cdot 1) \]\[ = -2\mathbf{i} + 2\mathbf{j} - \mathbf{k} \].
04

Calculate \((\mathbf{a} \times \mathbf{c}) \times \mathbf{b}\)

Using \( (\mathbf{a} \times \mathbf{c}) = -2\mathbf{i} + 2\mathbf{j} - \mathbf{k} \) and vector \( \mathbf{b} = \mathbf{i} - \mathbf{k} \), calculate the cross product:\[ \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ -2 & 2 & -1 \ 1 & 0 & -1 \end{vmatrix} \]\[ = \mathbf{i}(2 \cdot -1 - -1 \cdot 0) - \mathbf{j}(-2 \cdot -1 - -1 \cdot 1) + \mathbf{k}(-2 \cdot 0 - 2 \cdot 1) \]\[ = -2\mathbf{i} - 3\mathbf{j} - 2\mathbf{k} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Algebra
Vector algebra is an important branch of mathematics that helps us understand and manipulate vectors, which are quantities having both magnitude and direction. Vectors can represented in various forms like geometric form, which uses arrows to denote direction, and algebraic or component form. In the component form, vectors are expressed using the i, j, and k unit vectors corresponding to the x, y, and z directions, respectively.

A fundamental operation in vector algebra is the cross product (i.e., vector product), which results in a new vector perpendicular to the original two vectors involved. The cross product is particularly useful in determining the area of parallelograms formed by vectors, finding torques, and in physics for rotational dynamics. Its calculation often involves using the determinant of a matrix that includes unit vectors i, j, k along with the components of the involved vectors. Utilizing cross products can aid in simplifying complex problems in physics and engineering by providing a robust method to handle three-dimensional vectors.
Determinants
Determinants play a crucial role in calculating cross products amongst vectors. A determinant is a scalar value derived from a square matrix, often used to determine if a matrix has an inverse and in calculating areas and volumes. In the context of vectors, the cross product uses a special 3x3 matrix setup where the top row consists of unit vectors (i, j, k), and the subsequent rows contain the components of the two vectors being multiplied.

For example, to compute the cross product of two vectors, \( \mathbf{a} = \mathbf{i} + \mathbf{j} \) and \( \mathbf{b} = \mathbf{i} - \mathbf{k} \), their components are laid out in a matrix:\[ \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 1 & 1 & 0 \ 1 & 0 & -1 \end{vmatrix} \]

The determinant is evaluated as:\[ \mathbf{i}(1 \cdot -1 - 0 \cdot 0) - \mathbf{j}(1 \cdot -1 - 0 \cdot 1) + \mathbf{k}(1 \cdot 0 - 1 \cdot 1) \].

Understanding determinants allows for accurate computation of cross products, which in turn can lead to insights into the geometric and physical properties of a problem.
Component Form
In vector algebra, expressing a vector in component form makes it easier to perform operations and solve problems. When a vector is given in component form, it is typically written as a combination of the unit vectors i, j, and k, which represent the directions along the Cartesian coordinate axes.

For example, the vector \( \mathbf{a} = \mathbf{i} + \mathbf{j} \) signifes that it has components of 1 in the x-direction and 1 in the y-direction. This form allows for straightforward calculations of vector operations such as addition, subtraction, and importantly cross products.

The result of a cross product like \( \mathbf{a} \times \mathbf{b} = -\mathbf{i} + \mathbf{j} - \mathbf{k} \) is also provided in component form, showing the resulting vector's components in the respective directions. By using component form, one can easily visualize the direction and magnitude of vectors involved, making the handling of more complex vector interactions well-manageable. This skill is essential for tackling practical problems in engineering, physics, and computer graphics.

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