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Find parametric and symmetric equations of the line passing through points \((1,-3,2)\) and \((5,-2,8)\).

Short Answer

Expert verified
Parametric: \( x = 1 + 4t, y = -3 + t, z = 2 + 6t \). Symmetric: \( \frac{x - 1}{4} = y + 3 = \frac{z - 2}{6} \).

Step by step solution

01

Determine the Direction Vector

To find the direction vector \( \mathbf{d} \) of the line, subtract the coordinates of the two given points. Let the points be \( P_1(1,-3,2) \) and \( P_2(5,-2,8) \). The direction vector \( \mathbf{d} \) is calculated as: \[ \mathbf{d} = (p_2 - p_1, q_2 - q_1, r_2 - r_1) = (5 - 1, -2 - (-3), 8 - 2) = (4, 1, 6) \]
02

Write the Parametric Equations

Using point \( P_1(1,-3,2) \) as the starting point and \( \mathbf{d} = (4, 1, 6) \) as the direction vector, the parametric equations of the line are given by: \[ x = 1 + 4t \] \[ y = -3 + t \] \[ z = 2 + 6t \] Where \( t \) is the parameter.
03

Find the Symmetric Equations

To write the symmetric equations, solve each parametric equation for \( t \), then set them equal: From \( x = 1 + 4t \), \[ t = \frac{x - 1}{4} \] From \( y = -3 + t \), \[ t = y + 3 \] From \( z = 2 + 6t \), \[ t = \frac{z - 2}{6} \] The symmetric equations are therefore: \[ \frac{x - 1}{4} = y + 3 = \frac{z - 2}{6} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Direction Vector
The direction vector is a fundamental concept when dealing with lines in three-dimensional space. It essentially provides the line's orientation by indicating the direction in which the line proceeds. The direction vector \( \mathbf{d} \) is derived by subtracting the coordinates of a given start point from those of another point on the line.

For example, consider two points: \( P_1(1,-3,2) \) and \( P_2(5,-2,8) \). The direction vector \( \mathbf{d} \) is calculated by the difference in coordinates:
  • \( x ext{-component}: 5 - 1 = 4 \)
  • \( y ext{-component}: -2 - (-3) = 1 \)
  • \( z ext{-component}: 8 - 2 = 6 \)
Thus, \( \mathbf{d} = (4, 1, 6) \).

This direction vector is vital as it is used to form both the parametric and symmetric equations of the line.
Symmetric Equations
Symmetric equations offer a way to describe a line in space without explicitly tying each coordinate to the parameter \( t \). To obtain these, we first express each coordinate in terms of \( t \) from the parametric equations and then equalize them.

Starting with our parametric equations:
  • \( x = 1 + 4t \)
  • \( y = -3 + t \)
  • \( z = 2 + 6t \)
We solve for \( t \) in each:
  • From \( x = 1 + 4t \), we get \( t = \frac{x - 1}{4} \)
  • From \( y = -3 + t \), we get \( t = y + 3 \)
  • From \( z = 2 + 6t \), we get \( t = \frac{z - 2}{6} \)
By setting these equal, we derive the symmetric equation: \[ \frac{x - 1}{4} = y + 3 = \frac{z - 2}{6} \] This concise form helps to visualize how each coordinate progresses along the line without referencing the parameter \( t \).
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, allows us to represent geometric figures using algebraic equations. It's particularly useful for solving problems in three-dimensional space, like finding the equations of a line passing through two points. In this case, using points and vectors, we convert spatial positions into equations that can be easily manipulated mathematically.

With coordinate geometry, a line can be uniquely determined by a starting point and a direction vector. The point gives us a specific spot on the line, while the direction vector helps chart the line's path. For instance, starting from the point \( (1,-3,2) \) and using the direction vector \( (4, 1, 6) \), the line can be expressed in different forms:
  • Parametric Form: Conveys the position along the line at any point as each coordinate varies with \( t \).
  • Symmetric Form: Removes the parameter \( t \) and relates the spatial coordinates directly to each other.
This approach is crucial in understanding geometric relationships and transformations in three-dimensional space. It bridges the gap between algebra and geometry, providing deeper insights into spatial problems.

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