Consider \(\mathbf{r}(t)=\langle\cos t, \sin t, 2 t\rangle\) the position vector
of a particle at time \(t \in[0,30]\), where the components of are expressed in
centimeters and time in seconds. Let \(\overrightarrow{O P}\) be the position
vector of the particle after \(1 \mathrm{sec}\).
a. Show that all vectors \(\overrightarrow{P Q}\), where \(Q(x, y, z)\) is an
arbitrary point, orthogonal to the instantaneous velocity vector
\(\mathbf{v}(1)\) of the particle after \(1 \mathrm{sec}\), can be expressed as
\(\overrightarrow{P Q}=\langle x-\cos 1, y-\sin 1, z-2\rangle\), where \(x \sin
1-y \cos 1-2 z+4=0 .\) The set of point \(Q\) describes a plane called the normal
plane to the path of the particle at point \(P\)
b. Use a CAS to visualize the instantaneous velocity vector and the normal
plane at point \(P\) along with the path of the particle.