/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 For the following exercises, use... [FREE SOLUTION] | 91Ó°ÊÓ

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For the following exercises, use the given vectors \(\mathbf{a}\) and \(\mathbf{b}\) to find and express the vectors \(\mathbf{a}+\mathbf{b}, 4 \mathbf{a}\), and \(-5 \mathbf{a}+3 \mathbf{b}\) in component form. $$ \mathbf{a}=\langle 3,-2,4\rangle, \mathbf{b}=\langle-5,6,-9\rangle $$

Short Answer

Expert verified
\( \mathbf{a}+\mathbf{b} = \langle -2, 4, -5 \rangle \), \( 4\mathbf{a} = \langle 12, -8, 16 \rangle \), and \(-5\mathbf{a}+3\mathbf{b} = \langle -30, 28, -47 \rangle \).

Step by step solution

01

Find the Sum of Vectors

To find the sum of vectors \( \mathbf{a} \) and \( \mathbf{b} \), add their corresponding components. Thus, \( \mathbf{a} + \mathbf{b} = \langle 3 + (-5), -2 + 6, 4 + (-9) \rangle = \langle -2, 4, -5 \rangle \).
02

Multiply Vector by Scalar

To multiply \( \mathbf{a} \) by 4, multiply each component of \( \mathbf{a} \) by 4. So, \( 4\mathbf{a} = \langle 4(3), 4(-2), 4(4) \rangle = \langle 12, -8, 16 \rangle \).
03

Compute Linear Combination of Vectors

To find \(-5\mathbf{a}+3\mathbf{b}\), first multiply each vector by its scalar. Compute \(-5\mathbf{a} = \langle -5(3), -5(-2), -5(4) \rangle = \langle -15, 10, -20 \rangle \) and \(3\mathbf{b} = \langle 3(-5), 3(6), 3(-9) \rangle = \langle -15, 18, -27 \rangle \). Add these results: \(-5\mathbf{a} + 3\mathbf{b} = \langle -15 + (-15), 10 + 18, -20 + (-27) \rangle = \langle -30, 28, -47 \rangle \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
In mathematics, vector addition is a fundamental operation used to combine two vectors to produce a third. In the simplest version, if you have vectors \( \mathbf{a} \) and \( \mathbf{b} \), vector addition involves adding each corresponding component of these vectors.
Consider the example from the exercise: - \( \mathbf{a} = \langle 3, -2, 4 \rangle \) - \( \mathbf{b} = \langle -5, 6, -9 \rangle \) The addition process is quite straightforward. You take the first components of each vector—3 from \( \mathbf{a} \) and -5 from \( \mathbf{b} \)—and add them together to get -2. You repeat this process for the second and third components.
So,
  • First components: \( 3 + (-5) = -2 \)
  • Second components: \( -2 + 6 = 4 \)
  • Third components: \( 4 + (-9) = -5 \)
This gives the resulting vector: \( \langle -2, 4, -5 \rangle \).
Remember, vector addition is both commutative and associative, meaning you can add vectors in any order and group them as you see fit, and the result will be the same.
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar (a simple number), which stretches or shrinks the vector. Consider vector \( \mathbf{a} = \langle 3, -2, 4 \rangle \) from the exercise. If we multiply this vector by a scalar value, say 4, the operation is done by multiplying each component of \( \mathbf{a} \) by 4.
Here's how it happens step by step:
  • The first component is \( 3 \times 4 = 12 \)
  • The second component is \( -2 \times 4 = -8 \)
  • The third component is \( 4 \times 4 = 16 \)
So, \( 4 \mathbf{a} \) becomes \( \langle 12, -8, 16 \rangle \).
It's important to understand that scalar multiplication changes the magnitude of the vector but not its direction (unless the scalar is negative, which reverses the direction). This operation is fundamental when dealing with vector spaces, as it allows us to scale vectors to any desired length while maintaining their direction.
Linear Combinations
Linear combinations involve creating a new vector from multiples of two or more vectors. For example, find the linear combination \(-5\mathbf{a} + 3\mathbf{b}\) by scaling each vector accordingly and then adding them.
Start with scaling:
- Vector \(-5 \mathbf{a}\):
  • Multiply each component of \( \mathbf{a} = \langle 3, -2, 4 \rangle \) by \(-5\):
  • \(-5\times3 = -15\)
  • \(-5\times(-2) = 10\)
  • \(-5\times4 = -20\)
This results in \( \langle -15, 10, -20 \rangle \)
Then, for vector \(3\mathbf{b}\):
  • Multiply each component of \( \mathbf{b} = \langle -5, 6, -9 \rangle \) by 3:
  • \(3\times(-5) = -15\)
  • \(3\times6 = 18\)
  • \(3\times(-9) = -27\)
This results in \( \langle -15, 18, -27 \rangle \)
Finally, add the resulting vectors:
  • Components: \(-15 + (-15) = -30\)
  • Components: \(10 + 18 = 28\)
  • Components: \(-20 + (-27) = -47\)
Thus, the linear combination \(-5\mathbf{a} + 3\mathbf{b}\) results in \( \langle -30, 28, -47 \rangle \).
Linear combinations are crucial in understanding vector spaces, as they allow us to represent any vector in the space as a combination of a few basis vectors. This concept is widely used in various fields including physics, engineering, and computer graphics.

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Most popular questions from this chapter

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