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In Exercises \(11-18\) , find the exact length of the curve analytically by antidifferentiation. You will need to simplify the integrand algebraically before finding an antiderivative. $$y=x^{3 / 2} \text { from } x=0 \text { to } x=4$$

Short Answer

Expert verified
The exact length of the curve is calculated to be \( L = \frac{196}{15}\)

Step by step solution

01

Define the Type of Problem

The problem given can be defined as finding the length of a curve given by \(y=f(x) = x^ {3/2}\) between two points defined by the range \(x=0\) to \(x=4\). This can be solved using the formula for the length of the curve \(L = \int_{a}^{b} \sqrt{1 + [f'(x)]^2} dx\). The goal is to find the antiderivative of the integrand.
02

Find Derivative of the Given Function

First, differentiate the given function \(f(x) = x^{3/2}\) with respect to \(x\). The derivative is \(f'(x) = \frac{3}{2} x^{1/2}\).
03

Compute the Integral

Now, compute the integral by plugging the derivative into the curve length formula. Hence, we get \( L = \int_{0}^{4} \sqrt{1 + [\frac{3}{2} x^{1/2}]^2} dx . \) Simplifying the integrand algebraically and finding its antiderivative is the main task here.
04

Simplify the Integrand and Calculate the Antiderivative

Simplify the integrand algebraically and find its antiderivative. After computations, we find that \( L = \frac{16}{15} [3x^{3/2} + 2\sqrt{x} + 2] |_{0}^{4} \)
05

Evaluate the Definite Integral

Evaluate the definite integral by plugging the values of \(x\) equals to 4 and 0. After evaluating, we find that the exact length of the curve \( L = \frac{196}{15}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Antidifferentiation
Antidifferentiation, often referred to as integration, is a fundamental concept in calculus. It involves finding a function, called the antiderivative, whose derivative is the original function given. For example, if we have a function represented by the formula \( f(x) = x^{a} \), then the antiderivative of this function is \( F(x) = \frac{x^{a+1}}{a+1} + C \) where \( C \) is the constant of integration. Antidifferentiation is not only about finding the original function; it is also about understanding the area under a curve, solving differential equations, and analyzing the accumulated quantities. For the given exercise, antiderifferentiation plays a crucial role in finding the length of a curve. By taking the integral of a function, we essentially 'undo' the differentiation process, allowing us to explore properties of the original curve that are otherwise not apparent when only looking at its derivative.
Curve Length Formula
The curve length formula is a key tool in calculus used to determine the length of a curve between two points. For a function \( y = f(x) \), the length \( L \) of the curve from \( x=a \) to \( x=b \) is given by \( L = \int_{a}^{b} \sqrt{1 + [f'(x)]^2} \, dx \). This formula incorporates the Pythagorean theorem, summing the infinitesimal distances along the curve to give the total length. It becomes particularly useful when dealing with curves that cannot be easily analyzed using geometric shapes like circles or rectangles. For the exercise at hand, applying the curve length formula required finding the derivative of the given function \( f(x) = x^{3/2} \) and then evaluating the integral to find the exact length of the curve analytically. The curve length formula is essential for understanding complex geometric properties in a variety of fields, from engineering to physics.
Definite Integral
The definite integral is a concept that is essential for comprehending the accumulation of quantities, such as area, volume, and, as in our case, the length of a curve. It is represented as the integral of a function with upper and lower limits, which denote the bounds of integration. The notation \( \int_{a}^{b} f(x)\, dx \) signifies the definite integral of function \( f(x) \) from \( x=a \) to \( x=b \). Upon evaluating a definite integral, you receive a numerical value representing the total accumulation between the specified bounds. In our textbook exercise, the definite integral was used in Step 5 to calculate the exact length of the curve by evaluating the antiderivative function at the upper limit \( x=4 \) and subtracting its value at the lower limit \( x=0 \). This process, known as the 'Fundamental Theorem of Calculus,' simplifies the computation involved in these elaborate operations and is indispensable for solving concrete problems related to real-world applications.

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