/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 In Exercises \(1-8,(a)\) state w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(1-8,(a)\) state whether or not the function satisfies the hypotheses of the Mean Value Theorem on the given interval, and (b) if it does, find each value of \(c\) in the interval \((a, b)\) that satisfies the equation $$f(x)=\ln (x-1) \quad \text { on }[2,4]$$

Short Answer

Expert verified
The function \(f(x)=\ln (x-1)\) satisfies the hypothesis of the Mean Value Theorem on the interval [2,4]. The value of \(c\) in the interval (2,4) that satisfies the Mean Value Theorem is \(c = \frac{1}{\ln(3)} + 1\).

Step by step solution

01

Check if the function satisfies the Mean Value Theorem

First, we need to check the hypothesis of the Mean Value Theorem. The function \(f(x)=\ln (x-1)\) is continuous and differentiable on the open interval (1,+\(\infty\)). Since the interval [2,4] lies within the domain (1,+\(\infty\)), the function satisfies the hypothesis of the Mean Value Theorem.
02

Calculate the average rate of change over the interval

The average rate of change over the interval [2,4] is given by \(\frac{f(b)-f(a)}{b-a}\). Which is \(\frac{f(4)-f(2)}{4-2} = \frac{\ln(4-1)-\ln(2-1)}{4-2} = \frac{\ln(3)-\ln(1)}{2} = \ln(3)\).
03

Calculate the derivative of the function and find c

The derivative of \(f(x)=\ln (x-1)\) is \(f'(x) = \frac{1}{x-1}\). We set \(f'(x)\) equal to the average rate of change over the interval, and solve this equation for \(x\). Thus, \(\frac{1}{x-1} = \ln(3)\) which gives \(x = \frac{1}{\ln(3)} + 1\)
04

Check if the value of c lies in interval (2,4)

Since \(c = \frac{1}{\ln(3)} + 1 > 2\) and \(c < 4\), \(c\) lies in the interval \((2,4)\). Therefore, the value of \(c\) that satisfies the Mean Value Theorem is \(c = \frac{1}{\ln(3)} + 1\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a vast field of mathematics that deals with the study of rates of change (differential calculus) and accumulation of quantities (integral calculus). At the core of calculus is the concept of limits, which provides a rigorous way to approach the idea of instantaneous speed or area under the curve. Calculus allows us to understand the behavior of functions and systems in a dynamic and precise way, enabling us to solve complex problems in engineering, physics, economics, and more.

One of the fundamental theorems in calculus is the Mean Value Theorem. It connects the concept of derivatives (rates of change) with the difference in function values over a certain interval, guaranteeing a particular concordance between the average rate of change and the instantaneous rate of change at least at one point in that interval. It requires a function to be continuous over the closed interval and differentiable over the open interval, which are conditions rooted deeply in the nature of calculus.
Average Rate of Change
The average rate of change is a concept that describes how much a quantity changes on average over a particular interval. In the context of functions, it is the change in the function's value divided by the change in the input value over an interval. Mathematically, if we have a function f(x) defined on an interval [a, b], the average rate of change is expressed as \( \frac{f(b)-f(a)}{b-a} \).

This concept is analogous to the average speed of an object moving along a path; it doesn't tell us about the object's speed at a specific point but gives a general idea of the object's speed over the distance traveled. In calculus, understanding the average rate of change sets the stage for grasping more detailed behavior via the derivative, which can be thought of as the 'instantaneous' rate of change.
Differentiability
Differentiability refers to the ability of a function to have a derivative at every point within a certain interval. When a function is differentiable on an interval, it means that its derivative exists at every point in that interval, indicating that the function has a tangent line that touches the curve exactly at any given point within the interval.

A function being differentiable also implies that it is smooth and has no sharp corners or discontinuities. This concept is critical when dealing with the Mean Value Theorem, which necessitates a function to be differentiable in its open interval domain. When we look at a function such as \( f(x) = \ln (x-1) \), establishing its differentiability on the interval is essential to finding the specific point at which the function's instantaneous rate of change matches its average rate of change over the interval.
Continuity
Continuity is a characteristic of a function that implies it can be drawn without lifting the pencil from the paper, meaning no gaps, jumps, or sudden changes in direction. A function is considered continuous at a point if the limit of the function as it approaches the point from both directions equals the function’s value at that point.

For a function to fulfill the requirements of the Mean Value Theorem, it must be continuous over the closed interval [a, b]. This is because the theorem relies on the fact that the function behaves predictably over the entire interval. The continuity of functions like \( f(x) = \ln (x-1) \) is one of the prerequisites that need to be checked before we can apply the Mean Value Theorem to find the values of c in the given interval where the instantaneous rate of change equals the average rate of change.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Boring a Cylinder The mechanics at Lincoln Automotive are reboring a 6 -in. deep cylinder to fit a new piston. The machine they are using increases the cylinder's radius one-thousandth of an inch every 3 min. How rapidly is the cylinder volume increasing when the bore (diameter) is 3.800 in.?

Wilson Lot Size Formula One of the formulas for inventory management says that the average weekly cost of ordering, paying for, and holding merchandise is $$A(q)=\frac{k m}{q}+c m+\frac{h q}{2}$$ where \(q\) is the quantity you order when things run low (shoes, radios, brooms, or whatever the item might be), \(k\) is the cost of placing an order (the same, no matter how often you order), \(c\) is the cost of one item (a constant), \(m\) is the number of items sold each week (a constant), and \(h\) is the weekly holding cost per item (a constant that takes into account things such as space, utilities, insurance, and security). (a) Your job, as the inventory manager for your store, is to find the quantity that will minimize \(A(q) .\) What is it? (The formula you get for the answer is called the Wilson lot size formula.) (b) Shipping costs sometimes depend on order size. When they do, it is more realistic to replace \(k\) by \(k+b q,\) the sum of \(k\) and a constant multiple of \(q .\) What is the most economical quantity to order now?

$$ \begin{array}{l}{\text { Multiple Choice Which of the following functions is an }} \\ {\text { antiderivative of } \frac{1}{\sqrt{x}} ? \quad \mathrm{}}\end{array} $$ $$ (\mathbf{A})-\frac{1}{\sqrt{2 x^{3}}}(\mathbf{B})-\frac{2}{\sqrt{x}} \quad(\mathbf{C}) \frac{\sqrt{x}}{2}(\mathbf{D}) \sqrt{x}+5(\mathbf{E}) 2 \sqrt{x}-10 $$

Multiple Choice If \(y=\tan x, x=\pi,\) and \(d x=0.5,\) what does \(d y\) equal? \(\begin{array}{lll}{\text { (A) }-0.25} & {\text { (B) }-0.5} & {\text { (C) } 0} & {\text { (D) } 0.5}\end{array}\) (E) 0.25

Multiple Choice If \(a<0,\) the graph of \(y=a x^{3}+3 x^{2}+\) \(4 x+5\) is concave up on (A) \(\left(-\infty,-\frac{1}{a}\right)\) (B) \(\left(-\infty, \frac{1}{a}\right)\) (C) \(\left(-\frac{1}{a}, \infty\right) (D) \)\left(\frac{1}{a}, \infty\right)\( (E) \)(-\infty,-1)$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.