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Multiple Choice If \(f\) is a continuous, decreasing function on \([0,10]\) with a critical point at \((4,2),\) which of the following statements must be false? (A) \(f(10)\) is an absolute minimum of \(f\) on \([0,10] .\) (B) \(f(4)\) is neither a relative maximum nor a relative minimum. (C) \(f^{\prime}(4)\) does not exist. (D) \(f^{\prime}(4)=0\) (E) \(f^{\prime}(4)<0\)

Short Answer

Expert verified
The statement that must be false is (E) \(f^{\prime}(4)<0\).

Step by step solution

01

Evaluate statement (A)

The function is continuously decreasing on [0,10]. Thus, the function value at 10 will be the minimum among all points, i.e., f(10) is definitely an absolute minimum. So, statement (A) is true.
02

Evaluate statement (B)

Since the function is continuously decreasing on the interval, the value at any given point will always be higher than the value at any subsequent point. Hence, at the point (4,2), which is a critical point, f(4) cannot be either a relative maximum or a relative minimum, as the function doesn't switch its increase-decrease behaviour at this point. Statement (B) is also true.
03

Evaluate statement (C)

At critical points, the derivative does not exist or is equal to zero. However, we are given that f is a continuous function, therefore the derivative can exist at (4,2). Thus, it is possible that f'(4) exists, making statement (C) true.
04

Evaluate statement (D)

As already noted, at critical points, the derivative either does not exist or equals zero. Since f'(4) might exist (as mentioned in statement C), it could be that the derivative at the point equals zero, thus statement (D) is true.
05

Evaluate statement (E) and conclude

For a function to be decreasing, the derivative has to be less than zero. However, when the function reaches a critical point, the derivative can be zero or undefined. Thus, statement (E) which claims that f'(4)<0 must be false. The derivative at a critical point could be zero and truth of this statement contradicts with given condition that it is a critical point at (4,2).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuity in Calculus
In calculus, continuity is an essential property of a function. A function is continuous on an interval if there are no sudden jumps or breaks in its graph within that interval. This means for any point within the interval, you can find a small range around the point, called a neighborhood, where the function behaves predictably without any breaks.

Continuous functions have a few interesting qualities. For instance:
  • A continuous function on a closed interval \(\[a, b\]\) reaches both its maximum and minimum values. This is known as the Extreme Value Theorem.
  • If a function is continuous on an interval and differentiable within that interval, then it also follows the Intermediate Value Theorem.
Understanding continuity helps in identifying whether you can trust the function to behave as expected and in recognizing where critical points might occur. For instance, in our problem, a critical point exists at \(\(4, 2\)\), where the behavior of the function changes in a way that does not disrupt its overall continuity.
Decreasing Functions
Decreasing functions are functions where, as you move along the x-axis from left to right, the function values fall or remain the same. This is very different from increasing functions, where values rise.

Important properties of decreasing functions include:
  • The first derivative, \(f'(x)\), of the function will be negative or zero at any point in the interval over which the function is decreasing.
  • If a function is strictly decreasing, then \(f'(x) < 0\) across all points in the interval.
Decreasing functions often have critical points where their first derivative is zero or where the derivative does not exist, usually indicating a maximum or minimum point if these points don't interrupt the decrease. In the problem given, the function was overall decreasing and a critical point at \(\(4, 2\)\) indicates a property of the derivative at that point.
Derivatives and Differentiability
Derivatives represent the rate of change of a function. They're like the speed at which function values are changing concerning some unit change in x. Differentiability involves whether a derivative exists at every point in an interval.

Understanding derivatives and differentiability includes the following:
  • If a function has a derivative at a point, it is said to be differentiable at that point. This means you can find a tangent at the point on the graph.
  • A non-differentiable point could be a sharp corner or cusp, a vertical tangent, or a discontinuity.
Critical points are points where the derivative of a function is zero or undefined. These points often indicate where a function has local minima, maxima, or points of inflection. In analyzing a function, critical points are crucial because they show where major behavior changes occur. For the function in the exercise, the derivative at the critical point \(\(4, 2\)\) helps us understand that it is a crucial spot for examining the function's behavior.

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