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True or False If \(f(c)\) is a local maximum of a continuous function \(f\) on an open interval \((a, b),\) then \(f^{\prime}(c)=0 .\) Justify your answer.

Short Answer

Expert verified
The statement is False. There exist functions with local maxima at which the derivative either does not exist or is not zero.

Step by step solution

01

Analyze the Relationship

The relationship between a local maximum of a function and its derivative at that point is given by Fermat's Theorem, which states that if \(f(c)\) has a local maximum or minimum and if \(f^{\prime}(c)\) exists, then \(f^{\prime}(c)=0\). But the derivative does not always exist at a local maximum of a function, which is important to consider.
02

Counterexamples

It's also helpful to think of a function for which the derivative does not exist at a local maximum. An example of this is the absolute value function, \(f(x)= |x|\). This function has a local maximum at \(x=0\), but the derivative, \(f^{\prime}\), does not exist at that point. This is because the function is not differentiable at \(x=0\). There's another example in \(f(x) = x^3\) at \(x=0\). Despite the point \(x=0\) being a local maximum, \(f'(0) = 0\) and not necessarily equal to 0.
03

Conclusion

Considering this information, the statement, 'If \( f(c) \) is a local maximum of a continuous function \( f \) on an open interval \( (a, b) \), then \( f^{\prime}(c)=0 \),' is not always true. Therefore, the answer is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fermat's Theorem
When studying local maximum calculus, one encounters Fermat's Theorem, a fundamental principle that lays the groundwork for understanding the critical points of functions. This theorem states that if a function has a local maximum or minimum at a point, and if the function is differentiable at that point, then the derivative at that point is zero. The intuitive idea here is that the slope of the tangent line to the function at the peak (maximum) or trough (minimum) of a curve must be flat, which means having a slope of zero.

However, it is crucial to mention that Fermat's Theorem applies only when the function is differentiable at that point. That means a function might still have a local maximum even if the derivative does not exist at that point, complicating the relationship between local extrema and derivatives.
Derivative of a Function
Understanding the derivative of a function is vital in calculus, as it measures how a function changes as its input changes. In essence, the derivative represents the slope of the tangent line to the curve of the function at a certain point. It is the limit of the average rate of change of the function over an interval as that interval becomes infinitesimally small.

Mathematically, if you have a function given by \(f(x)\), its derivative \(f'(x)\) at a certain point \(x = a\) is given by the limit \[ f'(a) = \lim_{h \to 0} \frac{f(a+h) - f(a)}{h} \]. If this limit exists, we say the function is differentiable at that point and the derivative there gives us essential information about the function's behavior.
Continuous Function
The concept of a continuous function is integral to calculus and the analysis of real-valued functions. A function \(f(x)\) is considered continuous at a point \(x = a\) if three conditions are met: firstly, \(f(a)\) must be defined; secondly, \(\lim_{x \to a} f(x)\) must exist; and thirdly, \(\lim_{x \to a} f(x) = f(a)\). This ensures that the graph of \(f\) at \(a\) has no breaks, jumps, or holes, and can be drawn without lifting the pen from the paper.

A continuous function over an open interval \( (a, b) \) means that the function is continuous at every point within that interval. This continuity is a prerequisite for applying Fermat's Theorem and hence, related to finding local maxima.
Differentiability
Differentiability is a property of a function that tells us if the function's derivative exists at a given point. When a function \(f\) is differentiable at \(x = c\), we can determine its instantaneous rate of change at that point using its derivative \(f'(c)\). Differentiability implies continuity; if a function is differentiable at a certain point, it must also be continuous there. However, the converse is not always true; a function can be continuous at a point but not differentiable there.

For instance, a function with a sharp corner or cusp, like the absolute value function at \(x = 0\), is continuous but not differentiable at that point. Identifying whether a function is differentiable at a point is an important step in analyzing its local extrema and applying Fermat's Theorem.

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Most popular questions from this chapter

Draining Hemispherical Reservoir Water is flowing at the rate of 6 \(\mathrm{m}^{3} / \mathrm{min}\) from a reservoir shaped like a hemispherical bowl of radius \(13 \mathrm{m},\) shown here in profile. Answer the following questions given that the volume of water in a hemispherical bowl of radius \(R\) is \(V=(\pi / 3) y^{2}(3 R-y)\) when the water is \(y\) units deep. (a) At what rate is the water level changing when the water is 8 m deep? (b) What is the radius \(r\) of the water's surface when the water is \(y\) m deep? (c) At what rate is the radius \(r\) changing when the water is 8 \(\mathrm{m}\) deep?

You may use a graphing calculator to solve the following problems. True or False Newton's method will not find the zero of \(f(x)=x /\left(x^{2}+1\right)\) if the first guess is greater than \(1 .\) Justify your answer.

Analyzing Derivative Data Assume that \(f\) is continuous on \([-2,2]\) and differentiable on \((-2,2) .\) The table gives some values of \(f^{\prime}(x)\) $$ \begin{array}{cccc}\hline x & {f^{\prime}(x)} & {x} & {f^{\prime}(x)} \\\ \hline-2 & {7} & {0.25} & {-4.81} \\ {-1.75} & {4.19} & {0.5} & {-4.25} \\\ {-1.5} & {1.75} & {0.75} & {-3.31} \\ {-1.25} & {-0.31} & {1} & {-2}\end{array} $$ $$ \begin{array}{rrrr}{-1} & {-2} & {1.25} & {-0.31} \\ {-0.75} & {-3.31} & {1.5} & {1.75} \\ {-0.5} & {-4.25} & {1.75} & {4.19}\end{array} $$ $$ \begin{array}{cccc}{-0.25} & {-4.81} & {2} & {7} \\ {0} & {-5}\end{array} $$ $$ \begin{array}{l}{\text { (a) Estimate where } f \text { is increasing, decreasing, and has local }} \\ {\text { extrema. }} \\ {\text { (b) Find a quadratic regression equation for the data in the table }} \\ {\text { and superimpose its graph on a scatter plot of the data. }} \\ {\text { (c) Use the model in part (b) for } f^{\prime} \text { and find a formula for } f \text { that }} \\ {\text { satisties } f(0)=0 .}\end{array} $$

Writing to Learn The function $$ f(x)=\left\\{\begin{array}{ll}{x,} & {0 \leq x<1} \\ {0,} & {x=1}\end{array}\right. $$ is zero at \(x=0\) and at \(x=1 .\) Its derivative is equal to 1 at every point between 0 and \(1,\) so \(f^{\prime}\) is never zero between 0 and 1 and the graph of \(f\) has no tangent parallel to the chord from \((0,0)\) to \((1,0) .\) Explain why this does not contradict the Mean Value Theorem.

Motion along a Circle A wheel of radius 2 ft makes 8 revolutions about its center every second. (a) Explain how the parametric equations \(x=2 \cos \theta, \quad y=2 \sin \theta\) \(x=2 \cos \theta, \quad y=2 \sin \theta\) (b) Express \(\theta\) as a function of time \(t\) . (c) Find the rate of horizontal movement and the rate of vertical movement of a point on the edge of the wheel when it is at the position given by \(\theta=\pi / 4, \pi / 2,\) and \(\pi .\)

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