/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 \(y+x y-x=0, \quad x=0, \quad d ... [FREE SOLUTION] | 91Ó°ÊÓ

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\(y+x y-x=0, \quad x=0, \quad d x=0.01\)

Short Answer

Expert verified
For non-zero x, the solution to the given differential equation is \(y = \frac{x}{x-1}\). For x = 0, the equation is not defined.

Step by step solution

01

Simplify and Re-arrange the Differential Equation

The given equation, \(y + xy - x = 0\), can be simplified by subtracting y from both sides to get: \(xy - x = -y\).
02

Further Re-arrangement

This can again be re-arranged to maintain only y on the left side. In order to achieve this, it is important to factor x out of the right side. The equation then becomes: \(x(y - 1) = -y\).
03

Solve For y

Now, y can be solved by dividing both sides by x. Before doing this, however, make sure that the denominator, i.e., x is not zero. Since the initial condition given is \(x = 0\), this equation doesn't hold at x=0 as you cannot divide by zero. For any non-zero x, the solution will be: \(y = \frac{x}{x-1}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation Re-arrangement
Understanding how to re-arrange a differential equation is crucial for solving it. In our exercise, we start with the equation \(y + xy - x = 0\) and aim to isolate the variable \(y\) for clearer analysis. As shown in the solution, subtraction is the first step: we take \(y\)\ from both sides to obtain \(xy - x = -y\) .

It is this manipulation that prepares the equation for the critical next step: factoring. By cleverly re-arranging the terms, we can apply algebraic techniques such as factoring to simplify the problem. Remember, the goal is to isolate \(y\)\, or its derivative when dealing with differential equations. Proper re-arrangement paves the way for us to use other mathematical tools with greater ease.
Factoring in Algebra
Factoring is a powerful tool in algebra that can simplify many equations, including differential equations. In our exercise, we reach a point where the equation looks like \(xy - x = -y\)\, and factoring is our next move. Here, we factor out an \(x\)\ from the terms on the left, which gives us \( x(y - 1) = -y \)\, a much simpler form.

Why is this helpful? Factoring reduces equations to a simpler state which can often reveal the solutions more directly. In the context of differential equations, factoring can make the separation of variables possible, which is a method used for solving these types of equations. By transforming the equation into a product of factors, we set ourselves up for the subsequent steps needed to solve for \(y\)\.
Analyzing Initial Conditions
When solving a differential equation, initial conditions act as guidelines to pin down the exact solution from a family of possible solutions. The initial condition in our exercise specifies \(x = 0\) ; however, a quick glance at our re-arranged equation \( y = \frac{x}{x-1} \)\ tells us that we're dealt a tricky hand since the equation is undefined at \(x = 0\)\—you can't divide by zero!

Initial conditions are not just arbitrary numbers; they represent physically meaningful quantities in practical applications. They ensure that the mathematical solution aligns with the reality it models. Understanding this helps us recognize the importance of carefully analyzing initial conditions before proceeding with solving the equation, as they can affect the domain and the validity of the solution.

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Most popular questions from this chapter

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